TSTP Solution File: SET900+1 by Bliksem---1.12

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Bliksem---1.12
% Problem  : SET900+1 : TPTP v8.1.0. Released v3.2.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : bliksem %s

% Computer : n018.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 0s
% DateTime : Mon Jul 18 22:53:13 EDT 2022

% Result   : Theorem 0.45s 1.06s
% Output   : Refutation 0.45s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.12  % Problem  : SET900+1 : TPTP v8.1.0. Released v3.2.0.
% 0.03/0.13  % Command  : bliksem %s
% 0.13/0.34  % Computer : n018.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit : 300
% 0.13/0.34  % DateTime : Sun Jul 10 00:56:42 EDT 2022
% 0.13/0.34  % CPUTime  : 
% 0.45/1.06  *** allocated 10000 integers for termspace/termends
% 0.45/1.06  *** allocated 10000 integers for clauses
% 0.45/1.06  *** allocated 10000 integers for justifications
% 0.45/1.06  Bliksem 1.12
% 0.45/1.06  
% 0.45/1.06  
% 0.45/1.06  Automatic Strategy Selection
% 0.45/1.06  
% 0.45/1.06  
% 0.45/1.06  Clauses:
% 0.45/1.06  
% 0.45/1.06  { ! in( X, Y ), ! in( Y, X ) }.
% 0.45/1.06  { empty( empty_set ) }.
% 0.45/1.06  { empty( skol1 ) }.
% 0.45/1.06  { ! empty( skol2 ) }.
% 0.45/1.06  { ! skol3 = singleton( skol5 ) }.
% 0.45/1.06  { ! skol3 = empty_set }.
% 0.45/1.06  { ! in( X, skol3 ), X = skol5 }.
% 0.45/1.06  { X = singleton( Y ), X = empty_set, ! skol4( Z, Y ) = Y }.
% 0.45/1.06  { X = singleton( Y ), X = empty_set, in( skol4( X, Y ), X ) }.
% 0.45/1.06  
% 0.45/1.06  percentage equality = 0.533333, percentage horn = 0.777778
% 0.45/1.06  This is a problem with some equality
% 0.45/1.06  
% 0.45/1.06  
% 0.45/1.06  
% 0.45/1.06  Options Used:
% 0.45/1.06  
% 0.45/1.06  useres =            1
% 0.45/1.06  useparamod =        1
% 0.45/1.06  useeqrefl =         1
% 0.45/1.06  useeqfact =         1
% 0.45/1.06  usefactor =         1
% 0.45/1.06  usesimpsplitting =  0
% 0.45/1.06  usesimpdemod =      5
% 0.45/1.06  usesimpres =        3
% 0.45/1.06  
% 0.45/1.06  resimpinuse      =  1000
% 0.45/1.06  resimpclauses =     20000
% 0.45/1.06  substype =          eqrewr
% 0.45/1.06  backwardsubs =      1
% 0.45/1.06  selectoldest =      5
% 0.45/1.06  
% 0.45/1.06  litorderings [0] =  split
% 0.45/1.06  litorderings [1] =  extend the termordering, first sorting on arguments
% 0.45/1.06  
% 0.45/1.06  termordering =      kbo
% 0.45/1.06  
% 0.45/1.06  litapriori =        0
% 0.45/1.06  termapriori =       1
% 0.45/1.06  litaposteriori =    0
% 0.45/1.06  termaposteriori =   0
% 0.45/1.06  demodaposteriori =  0
% 0.45/1.06  ordereqreflfact =   0
% 0.45/1.06  
% 0.45/1.06  litselect =         negord
% 0.45/1.06  
% 0.45/1.06  maxweight =         15
% 0.45/1.06  maxdepth =          30000
% 0.45/1.06  maxlength =         115
% 0.45/1.06  maxnrvars =         195
% 0.45/1.06  excuselevel =       1
% 0.45/1.06  increasemaxweight = 1
% 0.45/1.06  
% 0.45/1.06  maxselected =       10000000
% 0.45/1.06  maxnrclauses =      10000000
% 0.45/1.06  
% 0.45/1.06  showgenerated =    0
% 0.45/1.06  showkept =         0
% 0.45/1.06  showselected =     0
% 0.45/1.06  showdeleted =      0
% 0.45/1.06  showresimp =       1
% 0.45/1.06  showstatus =       2000
% 0.45/1.06  
% 0.45/1.06  prologoutput =     0
% 0.45/1.06  nrgoals =          5000000
% 0.45/1.06  totalproof =       1
% 0.45/1.06  
% 0.45/1.06  Symbols occurring in the translation:
% 0.45/1.06  
% 0.45/1.06  {}  [0, 0]      (w:1, o:2, a:1, s:1, b:0), 
% 0.45/1.06  .  [1, 2]      (w:1, o:21, a:1, s:1, b:0), 
% 0.45/1.06  !  [4, 1]      (w:0, o:14, a:1, s:1, b:0), 
% 0.45/1.06  =  [13, 2]      (w:1, o:0, a:0, s:1, b:0), 
% 0.45/1.06  ==>  [14, 2]      (w:1, o:0, a:0, s:1, b:0), 
% 0.45/1.06  in  [37, 2]      (w:1, o:45, a:1, s:1, b:0), 
% 0.45/1.06  empty_set  [38, 0]      (w:1, o:8, a:1, s:1, b:0), 
% 0.45/1.06  empty  [39, 1]      (w:1, o:19, a:1, s:1, b:0), 
% 0.45/1.06  singleton  [40, 1]      (w:1, o:20, a:1, s:1, b:0), 
% 0.45/1.06  skol1  [42, 0]      (w:1, o:10, a:1, s:1, b:1), 
% 0.45/1.06  skol2  [43, 0]      (w:1, o:11, a:1, s:1, b:1), 
% 0.45/1.06  skol3  [44, 0]      (w:1, o:12, a:1, s:1, b:1), 
% 0.45/1.06  skol4  [45, 2]      (w:1, o:46, a:1, s:1, b:1), 
% 0.45/1.06  skol5  [46, 0]      (w:1, o:13, a:1, s:1, b:1).
% 0.45/1.06  
% 0.45/1.06  
% 0.45/1.06  Starting Search:
% 0.45/1.06  
% 0.45/1.06  
% 0.45/1.06  Bliksems!, er is een bewijs:
% 0.45/1.06  % SZS status Theorem
% 0.45/1.06  % SZS output start Refutation
% 0.45/1.06  
% 0.45/1.06  (4) {G0,W4,D3,L1,V0,M1} I { ! singleton( skol5 ) ==> skol3 }.
% 0.45/1.06  (5) {G0,W3,D2,L1,V0,M1} I { ! skol3 ==> empty_set }.
% 0.45/1.06  (6) {G0,W6,D2,L2,V1,M2} I { ! in( X, skol3 ), X = skol5 }.
% 0.45/1.06  (7) {G0,W12,D3,L3,V3,M3} I { X = singleton( Y ), X = empty_set, ! skol4( Z
% 0.45/1.06    , Y ) ==> Y }.
% 0.45/1.06  (8) {G0,W12,D3,L3,V2,M3} I { X = singleton( Y ), X = empty_set, in( skol4( 
% 0.45/1.06    X, Y ), X ) }.
% 0.45/1.06  (41) {G1,W11,D3,L3,V2,M3} P(7,4) { ! X = skol3, X = empty_set, ! skol4( Y, 
% 0.45/1.06    skol5 ) ==> skol5 }.
% 0.45/1.06  (49) {G2,W8,D3,L2,V1,M2} Q(41) { skol3 ==> empty_set, ! skol4( X, skol5 ) 
% 0.45/1.06    ==> skol5 }.
% 0.45/1.06  (152) {G3,W5,D3,L1,V1,M1} S(49);r(5) { ! skol4( X, skol5 ) ==> skol5 }.
% 0.45/1.06  (155) {G4,W5,D3,L1,V1,M1} P(6,152);q { ! in( skol4( X, skol5 ), skol3 ) }.
% 0.45/1.06  (156) {G5,W7,D3,L2,V0,M2} R(155,8) { singleton( skol5 ) ==> skol3, skol3 
% 0.45/1.06    ==> empty_set }.
% 0.45/1.06  (160) {G6,W0,D0,L0,V0,M0} S(156);r(4);r(5) {  }.
% 0.45/1.06  
% 0.45/1.06  
% 0.45/1.06  % SZS output end Refutation
% 0.45/1.06  found a proof!
% 0.45/1.06  
% 0.45/1.06  
% 0.45/1.06  Unprocessed initial clauses:
% 0.45/1.06  
% 0.45/1.06  (162) {G0,W6,D2,L2,V2,M2}  { ! in( X, Y ), ! in( Y, X ) }.
% 0.45/1.06  (163) {G0,W2,D2,L1,V0,M1}  { empty( empty_set ) }.
% 0.45/1.06  (164) {G0,W2,D2,L1,V0,M1}  { empty( skol1 ) }.
% 0.45/1.06  (165) {G0,W2,D2,L1,V0,M1}  { ! empty( skol2 ) }.
% 0.45/1.06  (166) {G0,W4,D3,L1,V0,M1}  { ! skol3 = singleton( skol5 ) }.
% 0.45/1.06  (167) {G0,W3,D2,L1,V0,M1}  { ! skol3 = empty_set }.
% 0.45/1.06  (168) {G0,W6,D2,L2,V1,M2}  { ! in( X, skol3 ), X = skol5 }.
% 0.45/1.06  (169) {G0,W12,D3,L3,V3,M3}  { X = singleton( Y ), X = empty_set, ! skol4( Z
% 0.45/1.06    , Y ) = Y }.
% 0.45/1.06  (170) {G0,W12,D3,L3,V2,M3}  { X = singleton( Y ), X = empty_set, in( skol4
% 0.45/1.06    ( X, Y ), X ) }.
% 0.45/1.06  
% 0.45/1.06  
% 0.45/1.06  Total Proof:
% 0.45/1.06  
% 0.45/1.06  eqswap: (172) {G0,W4,D3,L1,V0,M1}  { ! singleton( skol5 ) = skol3 }.
% 0.45/1.06  parent0[0]: (166) {G0,W4,D3,L1,V0,M1}  { ! skol3 = singleton( skol5 ) }.
% 0.45/1.06  substitution0:
% 0.45/1.06  end
% 0.45/1.06  
% 0.45/1.06  subsumption: (4) {G0,WCputime limit exceeded (core dumped)
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