TSTP Solution File: SET899+1 by Bliksem---1.12

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Bliksem---1.12
% Problem  : SET899+1 : TPTP v8.1.0. Released v3.2.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : bliksem %s

% Computer : n017.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 0s
% DateTime : Mon Jul 18 22:53:12 EDT 2022

% Result   : Theorem 0.44s 1.07s
% Output   : Refutation 0.44s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.12  % Problem  : SET899+1 : TPTP v8.1.0. Released v3.2.0.
% 0.03/0.12  % Command  : bliksem %s
% 0.13/0.33  % Computer : n017.cluster.edu
% 0.13/0.33  % Model    : x86_64 x86_64
% 0.13/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.33  % Memory   : 8042.1875MB
% 0.13/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.33  % CPULimit : 300
% 0.13/0.33  % DateTime : Sat Jul  9 23:04:47 EDT 2022
% 0.13/0.34  % CPUTime  : 
% 0.44/1.07  *** allocated 10000 integers for termspace/termends
% 0.44/1.07  *** allocated 10000 integers for clauses
% 0.44/1.07  *** allocated 10000 integers for justifications
% 0.44/1.07  Bliksem 1.12
% 0.44/1.07  
% 0.44/1.07  
% 0.44/1.07  Automatic Strategy Selection
% 0.44/1.07  
% 0.44/1.07  
% 0.44/1.07  Clauses:
% 0.44/1.07  
% 0.44/1.07  { subset( X, X ) }.
% 0.44/1.07  { ! in( X, Y ), ! in( Y, X ) }.
% 0.44/1.07  { empty( skol1 ) }.
% 0.44/1.07  { ! empty( skol2 ) }.
% 0.44/1.07  { subset( skol3, skol4 ) }.
% 0.44/1.07  { ! in( skol5, skol3 ) }.
% 0.44/1.07  { ! subset( skol3, set_difference( skol4, singleton( skol5 ) ) ) }.
% 0.44/1.07  { ! subset( X, Y ), in( Z, X ), subset( X, set_difference( Y, singleton( Z
% 0.44/1.07     ) ) ) }.
% 0.44/1.07  
% 0.44/1.07  percentage equality = 0.000000, percentage horn = 0.875000
% 0.44/1.07  This a non-horn, non-equality problem
% 0.44/1.07  
% 0.44/1.07  
% 0.44/1.07  Options Used:
% 0.44/1.07  
% 0.44/1.07  useres =            1
% 0.44/1.07  useparamod =        0
% 0.44/1.07  useeqrefl =         0
% 0.44/1.07  useeqfact =         0
% 0.44/1.07  usefactor =         1
% 0.44/1.07  usesimpsplitting =  0
% 0.44/1.07  usesimpdemod =      0
% 0.44/1.07  usesimpres =        3
% 0.44/1.07  
% 0.44/1.07  resimpinuse      =  1000
% 0.44/1.07  resimpclauses =     20000
% 0.44/1.07  substype =          standard
% 0.44/1.07  backwardsubs =      1
% 0.44/1.07  selectoldest =      5
% 0.44/1.07  
% 0.44/1.07  litorderings [0] =  split
% 0.44/1.07  litorderings [1] =  liftord
% 0.44/1.07  
% 0.44/1.07  termordering =      none
% 0.44/1.07  
% 0.44/1.07  litapriori =        1
% 0.44/1.07  termapriori =       0
% 0.44/1.07  litaposteriori =    0
% 0.44/1.07  termaposteriori =   0
% 0.44/1.07  demodaposteriori =  0
% 0.44/1.07  ordereqreflfact =   0
% 0.44/1.07  
% 0.44/1.07  litselect =         none
% 0.44/1.07  
% 0.44/1.07  maxweight =         15
% 0.44/1.07  maxdepth =          30000
% 0.44/1.07  maxlength =         115
% 0.44/1.07  maxnrvars =         195
% 0.44/1.07  excuselevel =       1
% 0.44/1.07  increasemaxweight = 1
% 0.44/1.07  
% 0.44/1.07  maxselected =       10000000
% 0.44/1.07  maxnrclauses =      10000000
% 0.44/1.07  
% 0.44/1.07  showgenerated =    0
% 0.44/1.07  showkept =         0
% 0.44/1.07  showselected =     0
% 0.44/1.07  showdeleted =      0
% 0.44/1.07  showresimp =       1
% 0.44/1.07  showstatus =       2000
% 0.44/1.07  
% 0.44/1.07  prologoutput =     0
% 0.44/1.07  nrgoals =          5000000
% 0.44/1.07  totalproof =       1
% 0.44/1.07  
% 0.44/1.07  Symbols occurring in the translation:
% 0.44/1.07  
% 0.44/1.07  {}  [0, 0]      (w:1, o:2, a:1, s:1, b:0), 
% 0.44/1.07  .  [1, 2]      (w:1, o:21, a:1, s:1, b:0), 
% 0.44/1.07  !  [4, 1]      (w:0, o:14, a:1, s:1, b:0), 
% 0.44/1.07  =  [13, 2]      (w:1, o:0, a:0, s:1, b:0), 
% 0.44/1.07  ==>  [14, 2]      (w:1, o:0, a:0, s:1, b:0), 
% 0.44/1.07  subset  [37, 2]      (w:1, o:45, a:1, s:1, b:0), 
% 0.44/1.07  in  [38, 2]      (w:1, o:46, a:1, s:1, b:0), 
% 0.44/1.07  empty  [39, 1]      (w:1, o:19, a:1, s:1, b:0), 
% 0.44/1.07  singleton  [41, 1]      (w:1, o:20, a:1, s:1, b:0), 
% 0.44/1.07  set_difference  [42, 2]      (w:1, o:47, a:1, s:1, b:0), 
% 0.44/1.07  skol1  [43, 0]      (w:1, o:9, a:1, s:1, b:0), 
% 0.44/1.07  skol2  [44, 0]      (w:1, o:10, a:1, s:1, b:0), 
% 0.44/1.07  skol3  [45, 0]      (w:1, o:11, a:1, s:1, b:0), 
% 0.44/1.07  skol4  [46, 0]      (w:1, o:12, a:1, s:1, b:0), 
% 0.44/1.07  skol5  [47, 0]      (w:1, o:13, a:1, s:1, b:0).
% 0.44/1.07  
% 0.44/1.07  
% 0.44/1.07  Starting Search:
% 0.44/1.07  
% 0.44/1.07  
% 0.44/1.07  Bliksems!, er is een bewijs:
% 0.44/1.07  % SZS status Theorem
% 0.44/1.07  % SZS output start Refutation
% 0.44/1.07  
% 0.44/1.07  (4) {G0,W3,D2,L1,V0,M1} I { subset( skol3, skol4 ) }.
% 0.44/1.07  (5) {G0,W3,D2,L1,V0,M1} I { ! in( skol5, skol3 ) }.
% 0.44/1.07  (6) {G0,W6,D4,L1,V0,M1} I { ! subset( skol3, set_difference( skol4, 
% 0.44/1.07    singleton( skol5 ) ) ) }.
% 0.44/1.07  (7) {G0,W12,D4,L3,V3,M1} I { ! subset( X, Y ), subset( X, set_difference( Y
% 0.44/1.07    , singleton( Z ) ) ), in( Z, X ) }.
% 0.44/1.07  (10) {G1,W9,D4,L2,V1,M2} R(7,5) { subset( skol3, set_difference( X, 
% 0.44/1.07    singleton( skol5 ) ) ), ! subset( skol3, X ) }.
% 0.44/1.07  (22) {G2,W0,D0,L0,V0,M0} R(10,6);r(4) {  }.
% 0.44/1.07  
% 0.44/1.07  
% 0.44/1.07  % SZS output end Refutation
% 0.44/1.07  found a proof!
% 0.44/1.07  
% 0.44/1.07  
% 0.44/1.07  Unprocessed initial clauses:
% 0.44/1.07  
% 0.44/1.07  (24) {G0,W3,D2,L1,V1,M1}  { subset( X, X ) }.
% 0.44/1.07  (25) {G0,W6,D2,L2,V2,M2}  { ! in( X, Y ), ! in( Y, X ) }.
% 0.44/1.07  (26) {G0,W2,D2,L1,V0,M1}  { empty( skol1 ) }.
% 0.44/1.07  (27) {G0,W2,D2,L1,V0,M1}  { ! empty( skol2 ) }.
% 0.44/1.07  (28) {G0,W3,D2,L1,V0,M1}  { subset( skol3, skol4 ) }.
% 0.44/1.07  (29) {G0,W3,D2,L1,V0,M1}  { ! in( skol5, skol3 ) }.
% 0.44/1.07  (30) {G0,W6,D4,L1,V0,M1}  { ! subset( skol3, set_difference( skol4, 
% 0.44/1.07    singleton( skol5 ) ) ) }.
% 0.44/1.07  (31) {G0,W12,D4,L3,V3,M3}  { ! subset( X, Y ), in( Z, X ), subset( X, 
% 0.44/1.07    set_difference( Y, singleton( Z ) ) ) }.
% 0.44/1.07  
% 0.44/1.07  
% 0.44/1.07  Total Proof:
% 0.44/1.07  
% 0.44/1.07  subsumption: (4) {G0,W3,D2,L1,V0,M1} I { subset( skol3, skol4 ) }.
% 0.44/1.07  parent0: (28) {G0,W3,D2,L1,V0,M1}  { subset( skol3, skol4 ) }.
% 0.44/1.07  substitution0:
% 0.44/1.07  end
% 0.44/1.07  permutation0:
% 0.44/1.07     0 ==> 0
% 0.44/1.07  end
% 0.44/1.07  
% 0.44/1.07  subsumption: (5) {G0,W3,D2,L1,V0,M1} I { ! in( skol5, skol3 ) }.
% 0.44/1.07  parent0: (29) {G0,W3,D2,L1,V0,M1}  { ! in( skol5, skol3 ) }.
% 0.44/1.07  substitution0:
% 0.44/1.07  end
% 0.44/1.07  permutation0:
% 0.44/1.07     0 ==> 0
% 0.44/1.07  end
% 0.44/1.07  
% 0.44/1.07  subsumption: (6) {G0,W6,D4,L1,V0,M1} I { ! subset( skol3, set_difference( 
% 0.44/1.07    skol4, singleton( skol5 ) ) ) }.
% 0.44/1.07  parent0: (30) {G0,W6,D4,L1,V0,M1}  { ! subset( skol3, set_difference( skol4
% 0.44/1.07    , singleton( skol5 ) ) ) }.
% 0.44/1.07  substitution0:
% 0.44/1.07  end
% 0.44/1.07  permutation0:
% 0.44/1.07     0 ==> 0
% 0.44/1.07  end
% 0.44/1.07  
% 0.44/1.07  subsumption: (7) {G0,W12,D4,L3,V3,M1} I { ! subset( X, Y ), subset( X, 
% 0.44/1.07    set_difference( Y, singleton( Z ) ) ), in( Z, X ) }.
% 0.44/1.07  parent0: (31) {G0,W12,D4,L3,V3,M3}  { ! subset( X, Y ), in( Z, X ), subset
% 0.44/1.07    ( X, set_difference( Y, singleton( Z ) ) ) }.
% 0.44/1.07  substitution0:
% 0.44/1.07     X := X
% 0.44/1.07     Y := Y
% 0.44/1.07     Z := Z
% 0.44/1.07  end
% 0.44/1.07  permutation0:
% 0.44/1.07     0 ==> 0
% 0.44/1.07     1 ==> 2
% 0.44/1.07     2 ==> 1
% 0.44/1.07  end
% 0.44/1.07  
% 0.44/1.07  resolution: (36) {G1,W9,D4,L2,V1,M2}  { ! subset( skol3, X ), subset( skol3
% 0.44/1.07    , set_difference( X, singleton( skol5 ) ) ) }.
% 0.44/1.07  parent0[0]: (5) {G0,W3,D2,L1,V0,M1} I { ! in( skol5, skol3 ) }.
% 0.44/1.07  parent1[2]: (7) {G0,W12,D4,L3,V3,M1} I { ! subset( X, Y ), subset( X, 
% 0.44/1.07    set_difference( Y, singleton( Z ) ) ), in( Z, X ) }.
% 0.44/1.07  substitution0:
% 0.44/1.07  end
% 0.44/1.07  substitution1:
% 0.44/1.07     X := skol3
% 0.44/1.07     Y := X
% 0.44/1.07     Z := skol5
% 0.44/1.07  end
% 0.44/1.07  
% 0.44/1.07  subsumption: (10) {G1,W9,D4,L2,V1,M2} R(7,5) { subset( skol3, 
% 0.44/1.07    set_difference( X, singleton( skol5 ) ) ), ! subset( skol3, X ) }.
% 0.44/1.07  parent0: (36) {G1,W9,D4,L2,V1,M2}  { ! subset( skol3, X ), subset( skol3, 
% 0.44/1.07    set_difference( X, singleton( skol5 ) ) ) }.
% 0.44/1.07  substitution0:
% 0.44/1.07     X := X
% 0.44/1.07  end
% 0.44/1.07  permutation0:
% 0.44/1.07     0 ==> 1
% 0.44/1.07     1 ==> 0
% 0.44/1.07  end
% 0.44/1.07  
% 0.44/1.07  resolution: (37) {G1,W3,D2,L1,V0,M1}  { ! subset( skol3, skol4 ) }.
% 0.44/1.07  parent0[0]: (6) {G0,W6,D4,L1,V0,M1} I { ! subset( skol3, set_difference( 
% 0.44/1.07    skol4, singleton( skol5 ) ) ) }.
% 0.44/1.07  parent1[0]: (10) {G1,W9,D4,L2,V1,M2} R(7,5) { subset( skol3, set_difference
% 0.44/1.07    ( X, singleton( skol5 ) ) ), ! subset( skol3, X ) }.
% 0.44/1.07  substitution0:
% 0.44/1.07  end
% 0.44/1.07  substitution1:
% 0.44/1.07     X := skol4
% 0.44/1.07  end
% 0.44/1.07  
% 0.44/1.07  resolution: (38) {G1,W0,D0,L0,V0,M0}  {  }.
% 0.44/1.07  parent0[0]: (37) {G1,W3,D2,L1,V0,M1}  { ! subset( skol3, skol4 ) }.
% 0.44/1.07  parent1[0]: (4) {G0,W3,D2,L1,V0,M1} I { subset( skol3, skol4 ) }.
% 0.44/1.07  substitution0:
% 0.44/1.07  end
% 0.44/1.07  substitution1:
% 0.44/1.07  end
% 0.44/1.07  
% 0.44/1.07  subsumption: (22) {G2,W0,D0,L0,V0,M0} R(10,6);r(4) {  }.
% 0.44/1.07  parent0: (38) {G1,W0,D0,L0,V0,M0}  {  }.
% 0.44/1.07  substitution0:
% 0.44/1.07  end
% 0.44/1.07  permutation0:
% 0.44/1.07  end
% 0.44/1.07  
% 0.44/1.07  Proof check complete!
% 0.44/1.07  
% 0.44/1.07  Memory use:
% 0.44/1.07  
% 0.44/1.07  space for terms:        313
% 0.44/1.07  space for clauses:      1389
% 0.44/1.07  
% 0.44/1.07  
% 0.44/1.07  clauses generated:      27
% 0.44/1.07  clauses kept:           23
% 0.44/1.07  clauses selected:       14
% 0.44/1.07  clauses deleted:        0
% 0.44/1.07  clauses inuse deleted:  0
% 0.44/1.07  
% 0.44/1.07  subsentry:          21
% 0.44/1.07  literals s-matched: 11
% 0.44/1.07  literals matched:   11
% 0.44/1.07  full subsumption:   0
% 0.44/1.07  
% 0.44/1.07  checksum:           1409258298
% 0.44/1.07  
% 0.44/1.07  
% 0.44/1.07  Bliksem ended
%------------------------------------------------------------------------------