TSTP Solution File: SET891+1 by Duper---1.0

View Problem - Process Solution

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% File     : Duper---1.0
% Problem  : SET891+1 : TPTP v8.1.2. Released v3.2.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n007.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 14:47:57 EDT 2023

% Result   : Theorem 3.55s 3.75s
% Output   : Proof 3.55s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.12/0.13  % Problem    : SET891+1 : TPTP v8.1.2. Released v3.2.0.
% 0.12/0.14  % Command    : duper %s
% 0.14/0.35  % Computer : n007.cluster.edu
% 0.14/0.35  % Model    : x86_64 x86_64
% 0.14/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.35  % Memory   : 8042.1875MB
% 0.14/0.35  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.14/0.35  % CPULimit   : 300
% 0.14/0.35  % WCLimit    : 300
% 0.14/0.35  % DateTime   : Sat Aug 26 12:44:26 EDT 2023
% 0.14/0.35  % CPUTime    : 
% 3.55/3.75  SZS status Theorem for theBenchmark.p
% 3.55/3.75  SZS output start Proof for theBenchmark.p
% 3.55/3.75  Clause #5 (by assumption #[]): Eq (∀ (A B : Iota), Eq (union (unordered_pair A B)) (set_union2 A B)) True
% 3.55/3.75  Clause #8 (by assumption #[]): Eq (Not (∀ (A B : Iota), Eq (union (unordered_pair (singleton A) (singleton B))) (unordered_pair A B))) True
% 3.55/3.75  Clause #9 (by assumption #[]): Eq (∀ (A B : Iota), Eq (unordered_pair A B) (set_union2 (singleton A) (singleton B))) True
% 3.55/3.75  Clause #34 (by clausification #[5]): ∀ (a : Iota), Eq (∀ (B : Iota), Eq (union (unordered_pair a B)) (set_union2 a B)) True
% 3.55/3.75  Clause #35 (by clausification #[34]): ∀ (a a_1 : Iota), Eq (Eq (union (unordered_pair a a_1)) (set_union2 a a_1)) True
% 3.55/3.75  Clause #36 (by clausification #[35]): ∀ (a a_1 : Iota), Eq (union (unordered_pair a a_1)) (set_union2 a a_1)
% 3.55/3.75  Clause #38 (by clausification #[9]): ∀ (a : Iota), Eq (∀ (B : Iota), Eq (unordered_pair a B) (set_union2 (singleton a) (singleton B))) True
% 3.55/3.75  Clause #39 (by clausification #[38]): ∀ (a a_1 : Iota), Eq (Eq (unordered_pair a a_1) (set_union2 (singleton a) (singleton a_1))) True
% 3.55/3.75  Clause #40 (by clausification #[39]): ∀ (a a_1 : Iota), Eq (unordered_pair a a_1) (set_union2 (singleton a) (singleton a_1))
% 3.55/3.75  Clause #46 (by clausification #[8]): Eq (∀ (A B : Iota), Eq (union (unordered_pair (singleton A) (singleton B))) (unordered_pair A B)) False
% 3.55/3.75  Clause #47 (by clausification #[46]): ∀ (a : Iota),
% 3.55/3.75    Eq
% 3.55/3.75      (Not
% 3.55/3.75        (∀ (B : Iota), Eq (union (unordered_pair (singleton (skS.0 2 a)) (singleton B))) (unordered_pair (skS.0 2 a) B)))
% 3.55/3.75      True
% 3.55/3.75  Clause #48 (by clausification #[47]): ∀ (a : Iota),
% 3.55/3.75    Eq (∀ (B : Iota), Eq (union (unordered_pair (singleton (skS.0 2 a)) (singleton B))) (unordered_pair (skS.0 2 a) B))
% 3.55/3.75      False
% 3.55/3.75  Clause #49 (by clausification #[48]): ∀ (a a_1 : Iota),
% 3.55/3.75    Eq
% 3.55/3.75      (Not
% 3.55/3.75        (Eq (union (unordered_pair (singleton (skS.0 2 a)) (singleton (skS.0 3 a a_1))))
% 3.55/3.75          (unordered_pair (skS.0 2 a) (skS.0 3 a a_1))))
% 3.55/3.75      True
% 3.55/3.75  Clause #50 (by clausification #[49]): ∀ (a a_1 : Iota),
% 3.55/3.75    Eq
% 3.55/3.75      (Eq (union (unordered_pair (singleton (skS.0 2 a)) (singleton (skS.0 3 a a_1))))
% 3.55/3.75        (unordered_pair (skS.0 2 a) (skS.0 3 a a_1)))
% 3.55/3.75      False
% 3.55/3.75  Clause #51 (by clausification #[50]): ∀ (a a_1 : Iota),
% 3.55/3.75    Ne (union (unordered_pair (singleton (skS.0 2 a)) (singleton (skS.0 3 a a_1))))
% 3.55/3.75      (unordered_pair (skS.0 2 a) (skS.0 3 a a_1))
% 3.55/3.75  Clause #52 (by forward demodulation #[51, 36]): ∀ (a a_1 : Iota),
% 3.55/3.75    Ne (set_union2 (singleton (skS.0 2 a)) (singleton (skS.0 3 a a_1))) (unordered_pair (skS.0 2 a) (skS.0 3 a a_1))
% 3.55/3.75  Clause #53 (by forward demodulation #[52, 40]): ∀ (a a_1 : Iota), Ne (unordered_pair (skS.0 2 a) (skS.0 3 a a_1)) (unordered_pair (skS.0 2 a) (skS.0 3 a a_1))
% 3.55/3.75  Clause #54 (by eliminate resolved literals #[53]): False
% 3.55/3.75  SZS output end Proof for theBenchmark.p
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