TSTP Solution File: SET884+1 by Prover9---1109a

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Prover9---1109a
% Problem  : SET884+1 : TPTP v8.1.0. Released v3.2.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : tptp2X_and_run_prover9 %d %s

% Computer : n027.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Tue Jul 19 04:33:10 EDT 2022

% Result   : Theorem 0.80s 1.06s
% Output   : Refutation 0.80s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.04/0.14  % Problem  : SET884+1 : TPTP v8.1.0. Released v3.2.0.
% 0.04/0.15  % Command  : tptp2X_and_run_prover9 %d %s
% 0.15/0.36  % Computer : n027.cluster.edu
% 0.15/0.36  % Model    : x86_64 x86_64
% 0.15/0.36  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.15/0.36  % Memory   : 8042.1875MB
% 0.15/0.36  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.15/0.36  % CPULimit : 300
% 0.15/0.36  % WCLimit  : 600
% 0.15/0.36  % DateTime : Mon Jul 11 06:57:03 EDT 2022
% 0.15/0.36  % CPUTime  : 
% 0.80/1.06  ============================== Prover9 ===============================
% 0.80/1.06  Prover9 (32) version 2009-11A, November 2009.
% 0.80/1.06  Process 5660 was started by sandbox on n027.cluster.edu,
% 0.80/1.06  Mon Jul 11 06:57:04 2022
% 0.80/1.06  The command was "/export/starexec/sandbox/solver/bin/prover9 -t 300 -f /tmp/Prover9_5507_n027.cluster.edu".
% 0.80/1.06  ============================== end of head ===========================
% 0.80/1.06  
% 0.80/1.06  ============================== INPUT =================================
% 0.80/1.06  
% 0.80/1.06  % Reading from file /tmp/Prover9_5507_n027.cluster.edu
% 0.80/1.06  
% 0.80/1.06  set(prolog_style_variables).
% 0.80/1.06  set(auto2).
% 0.80/1.06      % set(auto2) -> set(auto).
% 0.80/1.06      % set(auto) -> set(auto_inference).
% 0.80/1.06      % set(auto) -> set(auto_setup).
% 0.80/1.06      % set(auto_setup) -> set(predicate_elim).
% 0.80/1.06      % set(auto_setup) -> assign(eq_defs, unfold).
% 0.80/1.06      % set(auto) -> set(auto_limits).
% 0.80/1.06      % set(auto_limits) -> assign(max_weight, "100.000").
% 0.80/1.06      % set(auto_limits) -> assign(sos_limit, 20000).
% 0.80/1.06      % set(auto) -> set(auto_denials).
% 0.80/1.06      % set(auto) -> set(auto_process).
% 0.80/1.06      % set(auto2) -> assign(new_constants, 1).
% 0.80/1.06      % set(auto2) -> assign(fold_denial_max, 3).
% 0.80/1.06      % set(auto2) -> assign(max_weight, "200.000").
% 0.80/1.06      % set(auto2) -> assign(max_hours, 1).
% 0.80/1.06      % assign(max_hours, 1) -> assign(max_seconds, 3600).
% 0.80/1.06      % set(auto2) -> assign(max_seconds, 0).
% 0.80/1.06      % set(auto2) -> assign(max_minutes, 5).
% 0.80/1.06      % assign(max_minutes, 5) -> assign(max_seconds, 300).
% 0.80/1.06      % set(auto2) -> set(sort_initial_sos).
% 0.80/1.06      % set(auto2) -> assign(sos_limit, -1).
% 0.80/1.06      % set(auto2) -> assign(lrs_ticks, 3000).
% 0.80/1.06      % set(auto2) -> assign(max_megs, 400).
% 0.80/1.06      % set(auto2) -> assign(stats, some).
% 0.80/1.06      % set(auto2) -> clear(echo_input).
% 0.80/1.06      % set(auto2) -> set(quiet).
% 0.80/1.06      % set(auto2) -> clear(print_initial_clauses).
% 0.80/1.06      % set(auto2) -> clear(print_given).
% 0.80/1.06  assign(lrs_ticks,-1).
% 0.80/1.06  assign(sos_limit,10000).
% 0.80/1.06  assign(order,kbo).
% 0.80/1.06  set(lex_order_vars).
% 0.80/1.06  clear(print_given).
% 0.80/1.06  
% 0.80/1.06  % formulas(sos).  % not echoed (9 formulas)
% 0.80/1.06  
% 0.80/1.06  ============================== end of input ==========================
% 0.80/1.06  
% 0.80/1.06  % From the command line: assign(max_seconds, 300).
% 0.80/1.06  
% 0.80/1.06  ============================== PROCESS NON-CLAUSAL FORMULAS ==========
% 0.80/1.06  
% 0.80/1.06  % Formulas that are not ordinary clauses:
% 0.80/1.06  1 (all A all B (in(A,B) -> -in(B,A))) # label(antisymmetry_r2_hidden) # label(axiom) # label(non_clause).  [assumption].
% 0.80/1.06  2 (all A all B unordered_pair(A,B) = unordered_pair(B,A)) # label(commutativity_k2_tarski) # label(axiom) # label(non_clause).  [assumption].
% 0.80/1.06  3 (all A all B (B = singleton(A) <-> (all C (in(C,B) <-> C = A)))) # label(d1_tarski) # label(axiom) # label(non_clause).  [assumption].
% 0.80/1.06  4 (all A all B all C (C = unordered_pair(A,B) <-> (all D (in(D,C) <-> D = A | D = B)))) # label(d2_tarski) # label(axiom) # label(non_clause).  [assumption].
% 0.80/1.06  5 (all A all B (subset(A,B) <-> (all C (in(C,A) -> in(C,B))))) # label(d3_tarski) # label(axiom) # label(non_clause).  [assumption].
% 0.80/1.06  6 (exists A empty(A)) # label(rc1_xboole_0) # label(axiom) # label(non_clause).  [assumption].
% 0.80/1.06  7 (exists A -empty(A)) # label(rc2_xboole_0) # label(axiom) # label(non_clause).  [assumption].
% 0.80/1.06  8 (all A all B subset(A,A)) # label(reflexivity_r1_tarski) # label(axiom) # label(non_clause).  [assumption].
% 0.80/1.06  9 -(all A all B all C -(subset(singleton(A),unordered_pair(B,C)) & A != B & A != C)) # label(t25_zfmisc_1) # label(negated_conjecture) # label(non_clause).  [assumption].
% 0.80/1.06  
% 0.80/1.06  ============================== end of process non-clausal formulas ===
% 0.80/1.06  
% 0.80/1.06  ============================== PROCESS INITIAL CLAUSES ===============
% 0.80/1.06  
% 0.80/1.06  ============================== PREDICATE ELIMINATION =================
% 0.80/1.06  10 -subset(A,B) | -in(C,A) | in(C,B) # label(d3_tarski) # label(axiom).  [clausify(5)].
% 0.80/1.06  11 subset(A,A) # label(reflexivity_r1_tarski) # label(axiom).  [clausify(8)].
% 0.80/1.06  12 subset(singleton(c3),unordered_pair(c4,c5)) # label(t25_zfmisc_1) # label(negated_conjecture).  [clausify(9)].
% 0.80/1.06  13 subset(A,B) | in(f3(A,B),A) # label(d3_tarski) # label(axiom).  [clausify(5)].
% 0.80/1.06  14 subset(A,B) | -in(f3(A,B),B) # label(d3_tarski) # label(axiom).  [clausify(5)].
% 0.80/1.06  Derived: -in(A,singleton(c3)) | in(A,unordered_pair(c4,c5)).  [resolve(10,a,12,a)].
% 0.80/1.06  Derived: -in(A,B) | in(A,C) | in(f3(B,C),B).  [resolve(10,a,13,a)].
% 0.80/1.06  Derived: -in(A,B) | in(A,C) | -in(f3(B,C),C).  [resolve(10,a,14,a)].
% 0.80/1.06  
% 0.80/1.06  ============================== end predicate elimination =============
% 0.80/1.06  
% 0.80/1.06  Auto_denials:  (non-Horn, no changes).
% 0.80/1.06  
% 0.80/1.06  Term ordering decisions:
% 0.80/1.06  
% 0.80/1.06  % Assigning unary symbol singleton kb_weight 0 and highest precedence (13).
% 0.80/1.06  Function symbol KB weights:  c1=1. c2=1. c3=1. c4=1. c5=1. unordered_pair=1. f1=1. f3=1. f2=1. singleton=0.
% 0.80/1.06  
% 0.80/1.06  ============================== end of process initial clauses ========
% 0.80/1.06  
% 0.80/1.06  ============================== CLAUSES FOR SEARCH ====================
% 0.80/1.06  
% 0.80/1.06  ============================== end of clauses for search =============
% 0.80/1.06  
% 0.80/1.06  ============================== SEARCH ================================
% 0.80/1.06  
% 0.80/1.06  % Starting search at 0.01 seconds.
% 0.80/1.06  
% 0.80/1.06  ============================== PROOF =================================
% 0.80/1.06  % SZS status Theorem
% 0.80/1.06  % SZS output start Refutation
% 0.80/1.06  
% 0.80/1.06  % Proof 1 at 0.02 (+ 0.00) seconds.
% 0.80/1.06  % Length of proof is 17.
% 0.80/1.06  % Level of proof is 4.
% 0.80/1.06  % Maximum clause weight is 14.000.
% 0.80/1.06  % Given clauses 29.
% 0.80/1.06  
% 0.80/1.06  2 (all A all B unordered_pair(A,B) = unordered_pair(B,A)) # label(commutativity_k2_tarski) # label(axiom) # label(non_clause).  [assumption].
% 0.80/1.06  3 (all A all B (B = singleton(A) <-> (all C (in(C,B) <-> C = A)))) # label(d1_tarski) # label(axiom) # label(non_clause).  [assumption].
% 0.80/1.06  4 (all A all B all C (C = unordered_pair(A,B) <-> (all D (in(D,C) <-> D = A | D = B)))) # label(d2_tarski) # label(axiom) # label(non_clause).  [assumption].
% 0.80/1.06  5 (all A all B (subset(A,B) <-> (all C (in(C,A) -> in(C,B))))) # label(d3_tarski) # label(axiom) # label(non_clause).  [assumption].
% 0.80/1.06  9 -(all A all B all C -(subset(singleton(A),unordered_pair(B,C)) & A != B & A != C)) # label(t25_zfmisc_1) # label(negated_conjecture) # label(non_clause).  [assumption].
% 0.80/1.06  10 -subset(A,B) | -in(C,A) | in(C,B) # label(d3_tarski) # label(axiom).  [clausify(5)].
% 0.80/1.06  12 subset(singleton(c3),unordered_pair(c4,c5)) # label(t25_zfmisc_1) # label(negated_conjecture).  [clausify(9)].
% 0.80/1.06  16 unordered_pair(A,B) = unordered_pair(B,A) # label(commutativity_k2_tarski) # label(axiom).  [clausify(2)].
% 0.80/1.06  20 c4 != c3 # label(t25_zfmisc_1) # label(negated_conjecture).  [clausify(9)].
% 0.80/1.06  21 c5 != c3 # label(t25_zfmisc_1) # label(negated_conjecture).  [clausify(9)].
% 0.80/1.06  24 singleton(A) != B | in(C,B) | C != A # label(d1_tarski) # label(axiom).  [clausify(3)].
% 0.80/1.06  28 unordered_pair(A,B) != C | -in(D,C) | D = A | D = B # label(d2_tarski) # label(axiom).  [clausify(4)].
% 0.80/1.06  31 -in(A,singleton(c3)) | in(A,unordered_pair(c4,c5)).  [resolve(10,a,12,a)].
% 0.80/1.06  53 in(A,singleton(B)) | A != B.  [xx_res(24,a)].
% 0.80/1.06  66 -in(c3,unordered_pair(c4,c5)).  [ur(28,a,16,a,c,21,a(flip),d,20,a(flip))].
% 0.80/1.06  105 in(A,singleton(A)).  [xx_res(53,b)].
% 0.80/1.06  109 $F.  [resolve(105,a,31,a),unit_del(a,66)].
% 0.80/1.06  
% 0.80/1.06  % SZS output end Refutation
% 0.80/1.06  ============================== end of proof ==========================
% 0.80/1.06  
% 0.80/1.06  ============================== STATISTICS ============================
% 0.80/1.06  
% 0.80/1.06  Given=29. Generated=202. Kept=94. proofs=1.
% 0.80/1.06  Usable=29. Sos=54. Demods=1. Limbo=3, Disabled=32. Hints=0.
% 0.80/1.06  Megabytes=0.12.
% 0.80/1.06  User_CPU=0.02, System_CPU=0.00, Wall_clock=0.
% 0.80/1.06  
% 0.80/1.06  ============================== end of statistics =====================
% 0.80/1.06  
% 0.80/1.06  ============================== end of search =========================
% 0.80/1.06  
% 0.80/1.06  THEOREM PROVED
% 0.80/1.06  % SZS status Theorem
% 0.80/1.06  
% 0.80/1.06  Exiting with 1 proof.
% 0.80/1.06  
% 0.80/1.06  Process 5660 exit (max_proofs) Mon Jul 11 06:57:04 2022
% 0.80/1.06  Prover9 interrupted
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