TSTP Solution File: SET879+1 by SOS---2.0

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : SOS---2.0
% Problem  : SET879+1 : TPTP v8.1.0. Released v3.2.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : sos-script %s

% Computer : n023.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Tue Jul 19 05:21:32 EDT 2022

% Result   : Theorem 0.36s 0.54s
% Output   : Refutation 0.36s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.12  % Problem  : SET879+1 : TPTP v8.1.0. Released v3.2.0.
% 0.07/0.12  % Command  : sos-script %s
% 0.12/0.33  % Computer : n023.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit : 300
% 0.12/0.33  % WCLimit  : 600
% 0.12/0.33  % DateTime : Sun Jul 10 17:48:55 EDT 2022
% 0.12/0.33  % CPUTime  : 
% 0.12/0.35  ----- Otter 3.2, August 2001 -----
% 0.12/0.35  The process was started by sandbox2 on n023.cluster.edu,
% 0.12/0.35  Sun Jul 10 17:48:55 2022
% 0.12/0.35  The command was "./sos".  The process ID is 27773.
% 0.12/0.35  
% 0.12/0.35  set(prolog_style_variables).
% 0.12/0.35  set(auto).
% 0.12/0.35     dependent: set(auto1).
% 0.12/0.35     dependent: set(process_input).
% 0.12/0.35     dependent: clear(print_kept).
% 0.12/0.35     dependent: clear(print_new_demod).
% 0.12/0.35     dependent: clear(print_back_demod).
% 0.12/0.35     dependent: clear(print_back_sub).
% 0.12/0.35     dependent: set(control_memory).
% 0.12/0.35     dependent: assign(max_mem, 12000).
% 0.12/0.35     dependent: assign(pick_given_ratio, 4).
% 0.12/0.35     dependent: assign(stats_level, 1).
% 0.12/0.35     dependent: assign(pick_semantic_ratio, 3).
% 0.12/0.35     dependent: assign(sos_limit, 5000).
% 0.12/0.35     dependent: assign(max_weight, 60).
% 0.12/0.35  clear(print_given).
% 0.12/0.35  
% 0.12/0.35  formula_list(usable).
% 0.12/0.35  
% 0.12/0.35  SCAN INPUT: prop=0, horn=0, equality=1, symmetry=0, max_lits=3.
% 0.12/0.35  
% 0.12/0.35  This ia a non-Horn set with equality.  The strategy will be
% 0.12/0.35  Knuth-Bendix, ordered hyper_res, ur_res, factoring, and
% 0.12/0.35  unit deletion, with positive clauses in sos and nonpositive
% 0.12/0.35  clauses in usable.
% 0.12/0.35  
% 0.12/0.35     dependent: set(knuth_bendix).
% 0.12/0.35     dependent: set(para_from).
% 0.12/0.35     dependent: set(para_into).
% 0.12/0.35     dependent: clear(para_from_right).
% 0.12/0.35     dependent: clear(para_into_right).
% 0.12/0.35     dependent: set(para_from_vars).
% 0.12/0.35     dependent: set(eq_units_both_ways).
% 0.12/0.35     dependent: set(dynamic_demod_all).
% 0.12/0.35     dependent: set(dynamic_demod).
% 0.12/0.35     dependent: set(order_eq).
% 0.12/0.35     dependent: set(back_demod).
% 0.12/0.35     dependent: set(lrpo).
% 0.12/0.35     dependent: set(hyper_res).
% 0.12/0.35     dependent: set(unit_deletion).
% 0.12/0.35     dependent: set(factor).
% 0.12/0.35  
% 0.12/0.35  ------------> process usable:
% 0.12/0.35  
% 0.12/0.35  ------------> process sos:
% 0.12/0.35    Following clause subsumed by 13 during input processing: 0 [copy,13,flip.1] {-} A=A.
% 0.12/0.35  
% 0.12/0.35  ======= end of input processing =======
% 0.12/0.37  
% 0.12/0.37  Model 1 (0.00 seconds, 0 Inserts)
% 0.12/0.37  
% 0.12/0.37  Stopped by limit on number of solutions
% 0.12/0.37  
% 0.12/0.37  
% 0.12/0.37  -------------- Softie stats --------------
% 0.12/0.37  
% 0.12/0.37  UPDATE_STOP: 300
% 0.12/0.37  SFINDER_TIME_LIMIT: 2
% 0.12/0.37  SHORT_CLAUSE_CUTOFF: 4
% 0.12/0.37  number of clauses in intial UL: 9
% 0.12/0.37  number of clauses initially in problem: 13
% 0.12/0.37  percentage of clauses intially in UL: 69
% 0.12/0.37  percentage of distinct symbols occuring in initial UL: 90
% 0.12/0.37  percent of all initial clauses that are short: 100
% 0.12/0.37  absolute distinct symbol count: 10
% 0.12/0.37     distinct predicate count: 3
% 0.12/0.37     distinct function count: 3
% 0.12/0.37     distinct constant count: 4
% 0.12/0.37  
% 0.12/0.37  ---------- no more Softie stats ----------
% 0.12/0.37  
% 0.12/0.37  
% 0.12/0.37  
% 0.12/0.37  =========== start of search ===========
% 0.36/0.54  
% 0.36/0.54  -------- PROOF -------- 
% 0.36/0.54  % SZS status Theorem
% 0.36/0.54  % SZS output start Refutation
% 0.36/0.54  
% 0.36/0.54  Stopped by limit on insertions
% 0.36/0.54  
% 0.36/0.54  Model 2 [ 1 1 74 ] (0.00 seconds, 250000 Inserts)
% 0.36/0.54  
% 0.36/0.54  Stopped by limit on insertions
% 0.36/0.54  
% 0.36/0.54  Model 3 [ 1 1 72 ] (0.00 seconds, 250000 Inserts)
% 0.36/0.54  
% 0.36/0.54  -----> EMPTY CLAUSE at   0.17 sec ----> 154 [hyper,141,5,61] {-} $F.
% 0.36/0.54  
% 0.36/0.54  Length of proof is 6.  Level of proof is 3.
% 0.36/0.54  
% 0.36/0.54  ---------------- PROOF ----------------
% 0.36/0.54  % SZS status Theorem
% 0.36/0.54  % SZS output start Refutation
% 0.36/0.54  
% 0.36/0.54  1 [] {+} -in(A,B)| -in(B,A).
% 0.36/0.54  2 [] {+} A!=singleton(B)| -in(C,A)|C=B.
% 0.36/0.54  3 [] {+} A!=singleton(B)|in(C,A)|C!=B.
% 0.36/0.54  5 [] {+} set_difference(singleton(A),B)!=singleton(A)| -in(A,B).
% 0.36/0.54  7 [] {+} set_difference(singleton($c4),singleton($c3))=singleton($c4)|$c4!=$c3.
% 0.36/0.54  8 [] {+} set_difference(singleton($c4),singleton($c3))!=singleton($c4)|$c4=$c3.
% 0.36/0.54  9 [factor,1.1.2] {+} -in(A,A).
% 0.36/0.54  11 [] {-} set_difference(singleton(A),B)=singleton(A)|in(A,B).
% 0.36/0.54  13 [] {+} A=A.
% 0.36/0.54  39,38 [hyper,11,9] {+} set_difference(singleton(A),A)=singleton(A).
% 0.36/0.54  48 [para_from,11.1.1,8.1.1,unit_del,13] {-} $c4=$c3|in($c4,singleton($c3)).
% 0.36/0.54  61 [hyper,13,3,38,demod,39] {+} in(A,singleton(A)).
% 0.36/0.54  126,125 [hyper,48,2,13,factor_simp] {-} $c4=$c3.
% 0.36/0.54  141 [back_demod,7,demod,126,126,126,unit_del,13] {-} set_difference(singleton($c3),singleton($c3))=singleton($c3).
% 0.36/0.54  154 [hyper,141,5,61] {-} $F.
% 0.36/0.54  
% 0.36/0.54  % SZS output end Refutation
% 0.36/0.54  ------------ end of proof -------------
% 0.36/0.54  
% 0.36/0.54  
% 0.36/0.54  Search stopped by max_proofs option.
% 0.36/0.54  
% 0.36/0.54  
% 0.36/0.54  Search stopped by max_proofs option.
% 0.36/0.54  
% 0.36/0.54  ============ end of search ============
% 0.36/0.54  
% 0.36/0.54  ----------- soft-scott stats ----------
% 0.36/0.54  
% 0.36/0.54  true clauses given           2      (20.0%)
% 0.36/0.54  false clauses given          8
% 0.36/0.54  
% 0.36/0.54        FALSE     TRUE
% 0.36/0.54     9  1         1
% 0.36/0.54    10  0         1
% 0.36/0.54    11  1         1
% 0.36/0.54    12  0         1
% 0.36/0.54    13  1         2
% 0.36/0.54    14  1         3
% 0.36/0.54    17  4         2
% 0.36/0.54    18  2         1
% 0.36/0.54    19  2         0
% 0.36/0.54    20  1         1
% 0.36/0.54    21  4         0
% 0.36/0.54    22  3         5
% 0.36/0.54    23  1         2
% 0.36/0.54    24  1         3
% 0.36/0.54    25  1         0
% 0.36/0.54    27  2         2
% 0.36/0.54    28  2         1
% 0.36/0.54    29  2         5
% 0.36/0.54    30  0         3
% 0.36/0.54    31  0         1
% 0.36/0.54    32  0         1
% 0.36/0.54    33  1         0
% 0.36/0.54    34  4         0
% 0.36/0.54    35  2         1
% 0.36/0.54    36  7         1
% 0.36/0.54    37  5         5
% 0.36/0.54    38  2         0
% 0.36/0.54    40  1         1
% 0.36/0.54    41  1         3
% 0.36/0.54    42  1         1
% 0.36/0.54    44  4         4
% 0.36/0.54    46  0         1
% 0.36/0.54    48  5         4
% 0.36/0.54    50  1         0
% 0.36/0.54    51  0         3
% 0.36/0.54    53  0         2
% 0.36/0.54    57  0         2
% 0.36/0.54    59  1         0
% 0.36/0.54    60  0         1
% 0.36/0.54  tot:  64        65      (50.4% true)
% 0.36/0.54  
% 0.36/0.54  
% 0.36/0.54  Model 3 [ 1 -6 72 ] (0.00 seconds, 250000 Inserts)
% 0.36/0.54  
% 0.36/0.54  That finishes the proof of the theorem.
% 0.36/0.54  
% 0.36/0.54  Process 27773 finished Sun Jul 10 17:48:55 2022
%------------------------------------------------------------------------------