TSTP Solution File: SET786-1 by Bliksem---1.12
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%------------------------------------------------------------------------------
% File : Bliksem---1.12
% Problem : SET786-1 : TPTP v8.1.0. Released v2.5.0.
% Transfm : none
% Format : tptp:raw
% Command : bliksem %s
% Computer : n017.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 0s
% DateTime : Mon Jul 18 22:52:00 EDT 2022
% Result : Unsatisfiable 0.42s 1.08s
% Output : Refutation 0.42s
% Verified :
% SZS Type : -
% Comments :
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.12 % Problem : SET786-1 : TPTP v8.1.0. Released v2.5.0.
% 0.07/0.12 % Command : bliksem %s
% 0.12/0.33 % Computer : n017.cluster.edu
% 0.12/0.33 % Model : x86_64 x86_64
% 0.12/0.33 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33 % Memory : 8042.1875MB
% 0.12/0.33 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33 % CPULimit : 300
% 0.12/0.33 % DateTime : Sat Jul 9 23:41:02 EDT 2022
% 0.12/0.34 % CPUTime :
% 0.42/1.08 *** allocated 10000 integers for termspace/termends
% 0.42/1.08 *** allocated 10000 integers for clauses
% 0.42/1.08 *** allocated 10000 integers for justifications
% 0.42/1.08 Bliksem 1.12
% 0.42/1.08
% 0.42/1.08
% 0.42/1.08 Automatic Strategy Selection
% 0.42/1.08
% 0.42/1.08 Clauses:
% 0.42/1.08 [
% 0.42/1.08 [ ~( element( X, Y ) ), ~( element( Y, X ) ), ~( element( Y, sk1 ) ) ]
% 0.42/1.08 ,
% 0.42/1.08 [ element( X, sk1 ), element( X, sk2( X ) ) ],
% 0.42/1.08 [ element( X, sk1 ), element( sk2( X ), X ) ]
% 0.42/1.08 ] .
% 0.42/1.08
% 0.42/1.08
% 0.42/1.08 percentage equality = 0.000000, percentage horn = 0.333333
% 0.42/1.08 This a non-horn, non-equality problem
% 0.42/1.08
% 0.42/1.08
% 0.42/1.08 Options Used:
% 0.42/1.08
% 0.42/1.08 useres = 1
% 0.42/1.08 useparamod = 0
% 0.42/1.08 useeqrefl = 0
% 0.42/1.08 useeqfact = 0
% 0.42/1.08 usefactor = 1
% 0.42/1.08 usesimpsplitting = 0
% 0.42/1.08 usesimpdemod = 0
% 0.42/1.08 usesimpres = 3
% 0.42/1.08
% 0.42/1.08 resimpinuse = 1000
% 0.42/1.08 resimpclauses = 20000
% 0.42/1.08 substype = standard
% 0.42/1.08 backwardsubs = 1
% 0.42/1.08 selectoldest = 5
% 0.42/1.08
% 0.42/1.08 litorderings [0] = split
% 0.42/1.08 litorderings [1] = liftord
% 0.42/1.08
% 0.42/1.08 termordering = none
% 0.42/1.08
% 0.42/1.08 litapriori = 1
% 0.42/1.08 termapriori = 0
% 0.42/1.08 litaposteriori = 0
% 0.42/1.08 termaposteriori = 0
% 0.42/1.08 demodaposteriori = 0
% 0.42/1.08 ordereqreflfact = 0
% 0.42/1.08
% 0.42/1.08 litselect = none
% 0.42/1.08
% 0.42/1.08 maxweight = 15
% 0.42/1.08 maxdepth = 30000
% 0.42/1.08 maxlength = 115
% 0.42/1.08 maxnrvars = 195
% 0.42/1.08 excuselevel = 1
% 0.42/1.08 increasemaxweight = 1
% 0.42/1.08
% 0.42/1.08 maxselected = 10000000
% 0.42/1.08 maxnrclauses = 10000000
% 0.42/1.08
% 0.42/1.08 showgenerated = 0
% 0.42/1.08 showkept = 0
% 0.42/1.08 showselected = 0
% 0.42/1.08 showdeleted = 0
% 0.42/1.08 showresimp = 1
% 0.42/1.08 showstatus = 2000
% 0.42/1.08
% 0.42/1.08 prologoutput = 1
% 0.42/1.08 nrgoals = 5000000
% 0.42/1.08 totalproof = 1
% 0.42/1.08
% 0.42/1.08 Symbols occurring in the translation:
% 0.42/1.08
% 0.42/1.08 {} [0, 0] (w:1, o:2, a:1, s:1, b:0),
% 0.42/1.08 . [1, 2] (w:1, o:18, a:1, s:1, b:0),
% 0.42/1.08 ! [4, 1] (w:0, o:12, a:1, s:1, b:0),
% 0.42/1.08 = [13, 2] (w:1, o:0, a:0, s:1, b:0),
% 0.42/1.08 ==> [14, 2] (w:1, o:0, a:0, s:1, b:0),
% 0.42/1.08 element [41, 2] (w:1, o:43, a:1, s:1, b:0),
% 0.42/1.08 sk1 [42, 0] (w:1, o:5, a:1, s:1, b:0),
% 0.42/1.08 sk2 [43, 1] (w:1, o:17, a:1, s:1, b:0).
% 0.42/1.08
% 0.42/1.08
% 0.42/1.08 Starting Search:
% 0.42/1.08
% 0.42/1.08
% 0.42/1.08 Bliksems!, er is een bewijs:
% 0.42/1.08 % SZS status Unsatisfiable
% 0.42/1.08 % SZS output start Refutation
% 0.42/1.08
% 0.42/1.08 clause( 0, [ ~( element( Y, X ) ), ~( element( Y, sk1 ) ), ~( element( X, Y
% 0.42/1.08 ) ) ] )
% 0.42/1.08 .
% 0.42/1.08 clause( 1, [ element( X, sk1 ), element( X, sk2( X ) ) ] )
% 0.42/1.08 .
% 0.42/1.08 clause( 2, [ element( sk2( X ), X ), element( X, sk1 ) ] )
% 0.42/1.08 .
% 0.42/1.08 clause( 4, [ ~( element( X, sk1 ) ), ~( element( X, X ) ) ] )
% 0.42/1.08 .
% 0.42/1.08 clause( 5, [ ~( element( sk1, sk1 ) ) ] )
% 0.42/1.08 .
% 0.42/1.08 clause( 8, [ element( sk2( sk1 ), sk1 ) ] )
% 0.42/1.08 .
% 0.42/1.08 clause( 12, [ element( X, sk1 ), ~( element( sk2( X ), sk1 ) ) ] )
% 0.42/1.08 .
% 0.42/1.08 clause( 17, [] )
% 0.42/1.08 .
% 0.42/1.08
% 0.42/1.08
% 0.42/1.08 % SZS output end Refutation
% 0.42/1.08 found a proof!
% 0.42/1.08
% 0.42/1.08 % ABCDEFGHIJKLMNOPQRSTUVWXYZ
% 0.42/1.08
% 0.42/1.08 initialclauses(
% 0.42/1.08 [ clause( 19, [ ~( element( X, Y ) ), ~( element( Y, X ) ), ~( element( Y,
% 0.42/1.08 sk1 ) ) ] )
% 0.42/1.08 , clause( 20, [ element( X, sk1 ), element( X, sk2( X ) ) ] )
% 0.42/1.08 , clause( 21, [ element( X, sk1 ), element( sk2( X ), X ) ] )
% 0.42/1.08 ] ).
% 0.42/1.08
% 0.42/1.08
% 0.42/1.08
% 0.42/1.08 subsumption(
% 0.42/1.08 clause( 0, [ ~( element( Y, X ) ), ~( element( Y, sk1 ) ), ~( element( X, Y
% 0.42/1.08 ) ) ] )
% 0.42/1.08 , clause( 19, [ ~( element( X, Y ) ), ~( element( Y, X ) ), ~( element( Y,
% 0.42/1.08 sk1 ) ) ] )
% 0.42/1.08 , substitution( 0, [ :=( X, X ), :=( Y, Y )] ), permutation( 0, [ ==>( 0, 2
% 0.42/1.08 ), ==>( 1, 0 ), ==>( 2, 1 )] ) ).
% 0.42/1.08
% 0.42/1.08
% 0.42/1.08 subsumption(
% 0.42/1.08 clause( 1, [ element( X, sk1 ), element( X, sk2( X ) ) ] )
% 0.42/1.08 , clause( 20, [ element( X, sk1 ), element( X, sk2( X ) ) ] )
% 0.42/1.08 , substitution( 0, [ :=( X, X )] ), permutation( 0, [ ==>( 0, 0 ), ==>( 1,
% 0.42/1.08 1 )] ) ).
% 0.42/1.08
% 0.42/1.08
% 0.42/1.08 subsumption(
% 0.42/1.08 clause( 2, [ element( sk2( X ), X ), element( X, sk1 ) ] )
% 0.42/1.08 , clause( 21, [ element( X, sk1 ), element( sk2( X ), X ) ] )
% 0.42/1.08 , substitution( 0, [ :=( X, X )] ), permutation( 0, [ ==>( 0, 1 ), ==>( 1,
% 0.42/1.08 0 )] ) ).
% 0.42/1.08
% 0.42/1.08
% 0.42/1.08 factor(
% 0.42/1.08 clause( 32, [ ~( element( X, X ) ), ~( element( X, sk1 ) ) ] )
% 0.42/1.08 , clause( 0, [ ~( element( Y, X ) ), ~( element( Y, sk1 ) ), ~( element( X
% 0.42/1.08 , Y ) ) ] )
% 0.42/1.08 , 0, 2, substitution( 0, [ :=( X, X ), :=( Y, X )] )).
% 0.42/1.08
% 0.42/1.08
% 0.42/1.08 subsumption(
% 0.42/1.08 clause( 4, [ ~( element( X, sk1 ) ), ~( element( X, X ) ) ] )
% 0.42/1.08 , clause( 32, [ ~( element( X, X ) ), ~( element( X, sk1 ) ) ] )
% 0.42/1.08 , substitution( 0, [ :=( X, X )] ), permutation( 0, [ ==>( 0, 1 ), ==>( 1,
% 0.42/1.08 0 )] ) ).
% 0.42/1.08
% 0.42/1.08
% 0.42/1.08 factor(
% 0.42/1.08 clause( 35, [ ~( element( X, X ) ), ~( element( X, sk1 ) ) ] )
% 0.42/1.08 , clause( 0, [ ~( element( Y, X ) ), ~( element( Y, sk1 ) ), ~( element( X
% 0.42/1.08 , Y ) ) ] )
% 0.42/1.08 , 0, 2, substitution( 0, [ :=( X, X ), :=( Y, X )] )).
% 0.42/1.08
% 0.42/1.08
% 0.42/1.08 factor(
% 0.42/1.08 clause( 36, [ ~( element( sk1, sk1 ) ) ] )
% 0.42/1.08 , clause( 35, [ ~( element( X, X ) ), ~( element( X, sk1 ) ) ] )
% 0.42/1.08 , 0, 1, substitution( 0, [ :=( X, sk1 )] )).
% 0.42/1.08
% 0.42/1.08
% 0.42/1.08 subsumption(
% 0.42/1.08 clause( 5, [ ~( element( sk1, sk1 ) ) ] )
% 0.42/1.08 , clause( 36, [ ~( element( sk1, sk1 ) ) ] )
% 0.42/1.08 , substitution( 0, [] ), permutation( 0, [ ==>( 0, 0 )] ) ).
% 0.42/1.08
% 0.42/1.08
% 0.42/1.08
% 0.42/1.08 ==> clause( 8, [ element( sk2( sk1 ), sk1 ) ] )
% 0.42/1.08
% 0.42/1.08
% 0.42/1.08
% 0.42/1.08 !!! Internal Problem: OH, OH, COULD NOT DERIVE GOAL !!!
% 0.42/1.08
% 0.42/1.08 Bliksem ended
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