TSTP Solution File: SET766+4 by SOS---2.0

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : SOS---2.0
% Problem  : SET766+4 : TPTP v8.1.0. Released v2.2.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : sos-script %s

% Computer : n018.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Tue Jul 19 05:20:31 EDT 2022

% Result   : Theorem 0.20s 0.49s
% Output   : Refutation 0.20s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12  % Problem  : SET766+4 : TPTP v8.1.0. Released v2.2.0.
% 0.12/0.13  % Command  : sos-script %s
% 0.13/0.34  % Computer : n018.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit : 300
% 0.13/0.34  % WCLimit  : 600
% 0.13/0.34  % DateTime : Sun Jul 10 08:00:12 EDT 2022
% 0.13/0.34  % CPUTime  : 
% 0.13/0.36  ----- Otter 3.2, August 2001 -----
% 0.13/0.36  The process was started by sandbox on n018.cluster.edu,
% 0.13/0.36  Sun Jul 10 08:00:12 2022
% 0.13/0.36  The command was "./sos".  The process ID is 23647.
% 0.13/0.36  
% 0.13/0.36  set(prolog_style_variables).
% 0.13/0.36  set(auto).
% 0.13/0.36     dependent: set(auto1).
% 0.13/0.36     dependent: set(process_input).
% 0.13/0.36     dependent: clear(print_kept).
% 0.13/0.36     dependent: clear(print_new_demod).
% 0.13/0.36     dependent: clear(print_back_demod).
% 0.13/0.36     dependent: clear(print_back_sub).
% 0.13/0.36     dependent: set(control_memory).
% 0.13/0.36     dependent: assign(max_mem, 12000).
% 0.13/0.36     dependent: assign(pick_given_ratio, 4).
% 0.13/0.36     dependent: assign(stats_level, 1).
% 0.13/0.36     dependent: assign(pick_semantic_ratio, 3).
% 0.13/0.36     dependent: assign(sos_limit, 5000).
% 0.13/0.36     dependent: assign(max_weight, 60).
% 0.13/0.36  clear(print_given).
% 0.13/0.36  
% 0.13/0.36  formula_list(usable).
% 0.13/0.36  
% 0.13/0.36  SCAN INPUT: prop=0, horn=0, equality=1, symmetry=0, max_lits=7.
% 0.13/0.36  
% 0.13/0.36  This ia a non-Horn set with equality.  The strategy will be
% 0.13/0.36  Knuth-Bendix, ordered hyper_res, ur_res, factoring, and
% 0.13/0.36  unit deletion, with positive clauses in sos and nonpositive
% 0.13/0.36  clauses in usable.
% 0.13/0.36  
% 0.13/0.36     dependent: set(knuth_bendix).
% 0.13/0.36     dependent: set(para_from).
% 0.13/0.36     dependent: set(para_into).
% 0.13/0.36     dependent: clear(para_from_right).
% 0.13/0.36     dependent: clear(para_into_right).
% 0.13/0.36     dependent: set(para_from_vars).
% 0.13/0.36     dependent: set(eq_units_both_ways).
% 0.13/0.36     dependent: set(dynamic_demod_all).
% 0.13/0.36     dependent: set(dynamic_demod).
% 0.13/0.36     dependent: set(order_eq).
% 0.13/0.36     dependent: set(back_demod).
% 0.13/0.36     dependent: set(lrpo).
% 0.13/0.36     dependent: set(hyper_res).
% 0.13/0.36     dependent: set(unit_deletion).
% 0.13/0.36     dependent: set(factor).
% 0.13/0.36  
% 0.13/0.36  ------------> process usable:
% 0.13/0.36  
% 0.13/0.36  ------------> process sos:
% 0.13/0.36    Following clause subsumed by 147 during input processing: 0 [copy,147,flip.1] {-} A=A.
% 0.13/0.36  147 back subsumes 113.
% 0.13/0.36  147 back subsumes 108.
% 0.13/0.36  
% 0.13/0.36  ======= end of input processing =======
% 0.20/0.45  
% 0.20/0.45  
% 0.20/0.45  Failed to model usable list: disabling FINDER
% 0.20/0.45  
% 0.20/0.45  
% 0.20/0.45  
% 0.20/0.45  -------------- Softie stats --------------
% 0.20/0.45  
% 0.20/0.45  UPDATE_STOP: 300
% 0.20/0.45  SFINDER_TIME_LIMIT: 2
% 0.20/0.45  SHORT_CLAUSE_CUTOFF: 4
% 0.20/0.45  number of clauses in intial UL: 106
% 0.20/0.45  number of clauses initially in problem: 139
% 0.20/0.45  percentage of clauses intially in UL: 76
% 0.20/0.45  percentage of distinct symbols occuring in initial UL: 90
% 0.20/0.45  percent of all initial clauses that are short: 100
% 0.20/0.45  absolute distinct symbol count: 42
% 0.20/0.45     distinct predicate count: 9
% 0.20/0.45     distinct function count: 29
% 0.20/0.45     distinct constant count: 4
% 0.20/0.45  
% 0.20/0.45  ---------- no more Softie stats ----------
% 0.20/0.45  
% 0.20/0.45  
% 0.20/0.45  
% 0.20/0.45  =========== start of search ===========
% 0.20/0.49  
% 0.20/0.49  -------- PROOF -------- 
% 0.20/0.49  % SZS status Theorem
% 0.20/0.49  % SZS output start Refutation
% 0.20/0.49  
% 0.20/0.49  ----> UNIT CONFLICT at   0.10 sec ----> 517 [binary,516.1,148.1] {-} $F.
% 0.20/0.49  
% 0.20/0.49  Length of proof is 5.  Level of proof is 4.
% 0.20/0.49  
% 0.20/0.49  ---------------- PROOF ----------------
% 0.20/0.49  % SZS status Theorem
% 0.20/0.49  % SZS output start Refutation
% 0.20/0.49  
% 0.20/0.49  53 [] {+} -equivalence(A,B)| -member(C,B)|apply(A,C,C).
% 0.20/0.49  91 [] {+} member(A,equivalence_class(B,C,D))| -member(A,C)| -apply(D,B,A).
% 0.20/0.49  101 [] {-} -member($c1,equivalence_class($c1,$c3,$c2)).
% 0.20/0.49  142 [] {-} equivalence($c2,$c3).
% 0.20/0.49  144,143 [copy,142,flip.1] {-} equivalence($c3,$c2).
% 0.20/0.49  145 [] {-} member($c1,$c3).
% 0.20/0.49  146 [copy,145,demod,144] {-} member($c1,$c2).
% 0.20/0.49  148 [back_demod,101,demod,144] {-} -member($c1,equivalence_class($c1,$c2,$c2)).
% 0.20/0.49  244 [hyper,146,53,143,demod,144] {-} apply($c2,$c1,$c1).
% 0.20/0.49  516 [hyper,244,91,146] {-} member($c1,equivalence_class($c1,$c2,$c2)).
% 0.20/0.49  517 [binary,516.1,148.1] {-} $F.
% 0.20/0.49  
% 0.20/0.49  % SZS output end Refutation
% 0.20/0.49  ------------ end of proof -------------
% 0.20/0.49  
% 0.20/0.49  
% 0.20/0.49  Search stopped by max_proofs option.
% 0.20/0.49  
% 0.20/0.49  
% 0.20/0.49  Search stopped by max_proofs option.
% 0.20/0.49  
% 0.20/0.49  ============ end of search ============
% 0.20/0.49  
% 0.20/0.49  That finishes the proof of the theorem.
% 0.20/0.49  
% 0.20/0.49  Process 23647 finished Sun Jul 10 08:00:12 2022
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