TSTP Solution File: SET689+4 by SPASS---3.9
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- Process Solution
%------------------------------------------------------------------------------
% File : SPASS---3.9
% Problem : SET689+4 : TPTP v8.1.0. Released v2.2.0.
% Transfm : none
% Format : tptp
% Command : run_spass %d %s
% Computer : n010.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Tue Jul 19 05:28:07 EDT 2022
% Result : Theorem 0.19s 0.45s
% Output : Refutation 0.19s
% Verified :
% SZS Type : Refutation
% Derivation depth : 5
% Number of leaves : 8
% Syntax : Number of clauses : 17 ( 7 unt; 3 nHn; 17 RR)
% Number of literals : 29 ( 0 equ; 11 neg)
% Maximal clause size : 3 ( 1 avg)
% Maximal term depth : 2 ( 1 avg)
% Number of predicates : 4 ( 3 usr; 1 prp; 0-2 aty)
% Number of functors : 7 ( 7 usr; 6 con; 0-2 aty)
% Number of variables : 0 ( 0 sgn)
% Comments :
%------------------------------------------------------------------------------
cnf(1,axiom,
subset(skc5,skc3),
file('SET689+4.p',unknown),
[] ).
cnf(2,axiom,
subset(skc4,skc5),
file('SET689+4.p',unknown),
[] ).
cnf(3,axiom,
subset(skc3,skc4),
file('SET689+4.p',unknown),
[] ).
cnf(4,axiom,
~ equal_set(skc5,skc4),
file('SET689+4.p',unknown),
[] ).
cnf(10,axiom,
( subset(u,v)
| member(skf3(v,u),u) ),
file('SET689+4.p',unknown),
[] ).
cnf(15,axiom,
( ~ member(skf3(u,v),u)
| subset(w,u) ),
file('SET689+4.p',unknown),
[] ).
cnf(26,axiom,
( ~ member(u,v)
| ~ subset(v,w)
| member(u,w) ),
file('SET689+4.p',unknown),
[] ).
cnf(27,axiom,
( ~ subset(u,v)
| ~ subset(v,u)
| equal_set(v,u) ),
file('SET689+4.p',unknown),
[] ).
cnf(35,plain,
( ~ member(u,skc3)
| member(u,skc4) ),
inference(res,[status(thm),theory(equality)],[3,26]),
[iquote('0:Res:3.0,26.0')] ).
cnf(38,plain,
( ~ subset(skc5,skc4)
| equal_set(skc5,skc4) ),
inference(res,[status(thm),theory(equality)],[2,27]),
[iquote('0:Res:2.0,27.1')] ).
cnf(43,plain,
( ~ member(u,skc5)
| member(u,skc3) ),
inference(res,[status(thm),theory(equality)],[1,26]),
[iquote('0:Res:1.0,26.0')] ).
cnf(47,plain,
~ subset(skc5,skc4),
inference(mrr,[status(thm)],[38,4]),
[iquote('0:MRR:38.1,4.0')] ).
cnf(64,plain,
( subset(skc5,u)
| member(skf3(u,skc5),skc3) ),
inference(res,[status(thm),theory(equality)],[10,43]),
[iquote('0:Res:10.1,43.0')] ).
cnf(74,plain,
( ~ member(skf3(skc4,u),skc3)
| subset(v,skc4) ),
inference(res,[status(thm),theory(equality)],[35,15]),
[iquote('0:Res:35.1,15.0')] ).
cnf(102,plain,
( subset(skc5,skc4)
| subset(u,skc4) ),
inference(res,[status(thm),theory(equality)],[64,74]),
[iquote('0:Res:64.1,74.0')] ).
cnf(105,plain,
subset(skc5,skc4),
inference(con,[status(thm)],[102]),
[iquote('0:Con:102.1')] ).
cnf(106,plain,
$false,
inference(mrr,[status(thm)],[105,47]),
[iquote('0:MRR:105.0,47.0')] ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.12 % Problem : SET689+4 : TPTP v8.1.0. Released v2.2.0.
% 0.07/0.13 % Command : run_spass %d %s
% 0.13/0.34 % Computer : n010.cluster.edu
% 0.13/0.34 % Model : x86_64 x86_64
% 0.13/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34 % Memory : 8042.1875MB
% 0.13/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34 % CPULimit : 300
% 0.13/0.34 % WCLimit : 600
% 0.13/0.34 % DateTime : Sat Jul 9 23:25:00 EDT 2022
% 0.13/0.34 % CPUTime :
% 0.19/0.45
% 0.19/0.45 SPASS V 3.9
% 0.19/0.45 SPASS beiseite: Proof found.
% 0.19/0.45 % SZS status Theorem
% 0.19/0.45 Problem: /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.19/0.45 SPASS derived 65 clauses, backtracked 0 clauses, performed 0 splits and kept 74 clauses.
% 0.19/0.45 SPASS allocated 85416 KBytes.
% 0.19/0.45 SPASS spent 0:00:00.10 on the problem.
% 0.19/0.45 0:00:00.03 for the input.
% 0.19/0.45 0:00:00.04 for the FLOTTER CNF translation.
% 0.19/0.45 0:00:00.00 for inferences.
% 0.19/0.45 0:00:00.00 for the backtracking.
% 0.19/0.45 0:00:00.00 for the reduction.
% 0.19/0.45
% 0.19/0.45
% 0.19/0.45 Here is a proof with depth 3, length 17 :
% 0.19/0.45 % SZS output start Refutation
% See solution above
% 0.19/0.45 Formulae used in the proof : thI05 subset equal_set
% 0.19/0.45
%------------------------------------------------------------------------------