TSTP Solution File: SET630^5 by Duper---1.0
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%------------------------------------------------------------------------------
% File : Duper---1.0
% Problem : SET630^5 : TPTP v8.1.2. Released v4.0.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n001.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Thu Aug 31 14:47:10 EDT 2023
% Result : Theorem 3.40s 3.78s
% Output : Proof 3.40s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12 % Problem : SET630^5 : TPTP v8.1.2. Released v4.0.0.
% 0.00/0.13 % Command : duper %s
% 0.13/0.34 % Computer : n001.cluster.edu
% 0.13/0.34 % Model : x86_64 x86_64
% 0.13/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34 % Memory : 8042.1875MB
% 0.13/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34 % CPULimit : 300
% 0.13/0.34 % WCLimit : 300
% 0.13/0.34 % DateTime : Sat Aug 26 13:30:30 EDT 2023
% 0.13/0.34 % CPUTime :
% 3.40/3.78 SZS status Theorem for theBenchmark.p
% 3.40/3.78 SZS output start Proof for theBenchmark.p
% 3.40/3.78 Clause #0 (by assumption #[]): Eq
% 3.40/3.78 (Not
% 3.40/3.78 (∀ (X Y : a → Prop),
% 3.40/3.78 Not (Exists fun Xx => And (And (X Xx) (Y Xx)) (Or (And (X Xx) (Not (Y Xx))) (And (Y Xx) (Not (X Xx)))))))
% 3.40/3.78 True
% 3.40/3.78 Clause #1 (by clausification #[0]): Eq
% 3.40/3.78 (∀ (X Y : a → Prop),
% 3.40/3.78 Not (Exists fun Xx => And (And (X Xx) (Y Xx)) (Or (And (X Xx) (Not (Y Xx))) (And (Y Xx) (Not (X Xx))))))
% 3.40/3.78 False
% 3.40/3.78 Clause #2 (by clausification #[1]): ∀ (a_1 : a → Prop),
% 3.40/3.78 Eq
% 3.40/3.78 (Not
% 3.40/3.78 (∀ (Y : a → Prop),
% 3.40/3.78 Not
% 3.40/3.78 (Exists fun Xx =>
% 3.40/3.78 And (And (skS.0 0 a_1 Xx) (Y Xx))
% 3.40/3.78 (Or (And (skS.0 0 a_1 Xx) (Not (Y Xx))) (And (Y Xx) (Not (skS.0 0 a_1 Xx)))))))
% 3.40/3.78 True
% 3.40/3.78 Clause #3 (by clausification #[2]): ∀ (a_1 : a → Prop),
% 3.40/3.78 Eq
% 3.40/3.78 (∀ (Y : a → Prop),
% 3.40/3.78 Not
% 3.40/3.78 (Exists fun Xx =>
% 3.40/3.78 And (And (skS.0 0 a_1 Xx) (Y Xx))
% 3.40/3.78 (Or (And (skS.0 0 a_1 Xx) (Not (Y Xx))) (And (Y Xx) (Not (skS.0 0 a_1 Xx))))))
% 3.40/3.78 False
% 3.40/3.78 Clause #4 (by clausification #[3]): ∀ (a_1 a_2 : a → Prop),
% 3.40/3.78 Eq
% 3.40/3.78 (Not
% 3.40/3.78 (Not
% 3.40/3.78 (Exists fun Xx =>
% 3.40/3.78 And (And (skS.0 0 a_1 Xx) (skS.0 1 a_1 a_2 Xx))
% 3.40/3.78 (Or (And (skS.0 0 a_1 Xx) (Not (skS.0 1 a_1 a_2 Xx))) (And (skS.0 1 a_1 a_2 Xx) (Not (skS.0 0 a_1 Xx)))))))
% 3.40/3.78 True
% 3.40/3.78 Clause #5 (by clausification #[4]): ∀ (a_1 a_2 : a → Prop),
% 3.40/3.78 Eq
% 3.40/3.78 (Not
% 3.40/3.78 (Exists fun Xx =>
% 3.40/3.78 And (And (skS.0 0 a_1 Xx) (skS.0 1 a_1 a_2 Xx))
% 3.40/3.78 (Or (And (skS.0 0 a_1 Xx) (Not (skS.0 1 a_1 a_2 Xx))) (And (skS.0 1 a_1 a_2 Xx) (Not (skS.0 0 a_1 Xx))))))
% 3.40/3.78 False
% 3.40/3.78 Clause #6 (by clausification #[5]): ∀ (a_1 a_2 : a → Prop),
% 3.40/3.78 Eq
% 3.40/3.78 (Exists fun Xx =>
% 3.40/3.78 And (And (skS.0 0 a_1 Xx) (skS.0 1 a_1 a_2 Xx))
% 3.40/3.78 (Or (And (skS.0 0 a_1 Xx) (Not (skS.0 1 a_1 a_2 Xx))) (And (skS.0 1 a_1 a_2 Xx) (Not (skS.0 0 a_1 Xx)))))
% 3.40/3.78 True
% 3.40/3.78 Clause #7 (by clausification #[6]): ∀ (a_1 a_2 : a → Prop) (a_3 : a),
% 3.40/3.78 Eq
% 3.40/3.78 (And (And (skS.0 0 a_1 (skS.0 2 a_1 a_2 a_3)) (skS.0 1 a_1 a_2 (skS.0 2 a_1 a_2 a_3)))
% 3.40/3.78 (Or (And (skS.0 0 a_1 (skS.0 2 a_1 a_2 a_3)) (Not (skS.0 1 a_1 a_2 (skS.0 2 a_1 a_2 a_3))))
% 3.40/3.78 (And (skS.0 1 a_1 a_2 (skS.0 2 a_1 a_2 a_3)) (Not (skS.0 0 a_1 (skS.0 2 a_1 a_2 a_3))))))
% 3.40/3.78 True
% 3.40/3.78 Clause #8 (by clausification #[7]): ∀ (a_1 a_2 : a → Prop) (a_3 : a),
% 3.40/3.78 Eq
% 3.40/3.78 (Or (And (skS.0 0 a_1 (skS.0 2 a_1 a_2 a_3)) (Not (skS.0 1 a_1 a_2 (skS.0 2 a_1 a_2 a_3))))
% 3.40/3.78 (And (skS.0 1 a_1 a_2 (skS.0 2 a_1 a_2 a_3)) (Not (skS.0 0 a_1 (skS.0 2 a_1 a_2 a_3)))))
% 3.40/3.78 True
% 3.40/3.78 Clause #9 (by clausification #[7]): ∀ (a_1 a_2 : a → Prop) (a_3 : a),
% 3.40/3.78 Eq (And (skS.0 0 a_1 (skS.0 2 a_1 a_2 a_3)) (skS.0 1 a_1 a_2 (skS.0 2 a_1 a_2 a_3))) True
% 3.40/3.78 Clause #10 (by clausification #[8]): ∀ (a_1 a_2 : a → Prop) (a_3 : a),
% 3.40/3.78 Or (Eq (And (skS.0 0 a_1 (skS.0 2 a_1 a_2 a_3)) (Not (skS.0 1 a_1 a_2 (skS.0 2 a_1 a_2 a_3)))) True)
% 3.40/3.78 (Eq (And (skS.0 1 a_1 a_2 (skS.0 2 a_1 a_2 a_3)) (Not (skS.0 0 a_1 (skS.0 2 a_1 a_2 a_3)))) True)
% 3.40/3.78 Clause #11 (by clausification #[10]): ∀ (a_1 a_2 : a → Prop) (a_3 : a),
% 3.40/3.78 Or (Eq (And (skS.0 1 a_1 a_2 (skS.0 2 a_1 a_2 a_3)) (Not (skS.0 0 a_1 (skS.0 2 a_1 a_2 a_3)))) True)
% 3.40/3.78 (Eq (Not (skS.0 1 a_1 a_2 (skS.0 2 a_1 a_2 a_3))) True)
% 3.40/3.78 Clause #13 (by clausification #[11]): ∀ (a_1 a_2 : a → Prop) (a_3 : a),
% 3.40/3.78 Or (Eq (Not (skS.0 1 a_1 a_2 (skS.0 2 a_1 a_2 a_3))) True) (Eq (Not (skS.0 0 a_1 (skS.0 2 a_1 a_2 a_3))) True)
% 3.40/3.78 Clause #15 (by clausification #[13]): ∀ (a_1 a_2 : a → Prop) (a_3 : a),
% 3.40/3.78 Or (Eq (Not (skS.0 0 a_1 (skS.0 2 a_1 a_2 a_3))) True) (Eq (skS.0 1 a_1 a_2 (skS.0 2 a_1 a_2 a_3)) False)
% 3.40/3.78 Clause #16 (by clausification #[15]): ∀ (a_1 a_2 : a → Prop) (a_3 : a),
% 3.40/3.78 Or (Eq (skS.0 1 a_1 a_2 (skS.0 2 a_1 a_2 a_3)) False) (Eq (skS.0 0 a_1 (skS.0 2 a_1 a_2 a_3)) False)
% 3.40/3.78 Clause #17 (by clausification #[9]): ∀ (a_1 a_2 : a → Prop) (a_3 : a), Eq (skS.0 1 a_1 a_2 (skS.0 2 a_1 a_2 a_3)) True
% 3.40/3.78 Clause #18 (by clausification #[9]): ∀ (a_1 a_2 : a → Prop) (a_3 : a), Eq (skS.0 0 a_1 (skS.0 2 a_1 a_2 a_3)) True
% 3.40/3.78 Clause #19 (by superposition #[17, 16]): ∀ (a_1 a_2 : a → Prop) (a_3 : a), Or (Eq True False) (Eq (skS.0 0 a_1 (skS.0 2 a_1 a_2 a_3)) False)
% 3.40/3.78 Clause #21 (by clausification #[19]): ∀ (a_1 a_2 : a → Prop) (a_3 : a), Eq (skS.0 0 a_1 (skS.0 2 a_1 a_2 a_3)) False
% 3.40/3.78 Clause #22 (by superposition #[21, 18]): Eq False True
% 3.40/3.78 Clause #23 (by clausification #[22]): False
% 3.40/3.78 SZS output end Proof for theBenchmark.p
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