TSTP Solution File: SET618+3 by Duper---1.0

View Problem - Process Solution

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% File     : Duper---1.0
% Problem  : SET618+3 : TPTP v8.1.2. Released v2.2.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n006.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 14:47:06 EDT 2023

% Result   : Theorem 3.93s 4.09s
% Output   : Proof 3.93s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12  % Problem    : SET618+3 : TPTP v8.1.2. Released v2.2.0.
% 0.00/0.13  % Command    : duper %s
% 0.14/0.34  % Computer : n006.cluster.edu
% 0.14/0.34  % Model    : x86_64 x86_64
% 0.14/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.34  % Memory   : 8042.1875MB
% 0.14/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.14/0.34  % CPULimit   : 300
% 0.14/0.34  % WCLimit    : 300
% 0.14/0.34  % DateTime   : Sat Aug 26 11:03:37 EDT 2023
% 0.14/0.35  % CPUTime    : 
% 3.93/4.09  SZS status Theorem for theBenchmark.p
% 3.93/4.09  SZS output start Proof for theBenchmark.p
% 3.93/4.09  Clause #0 (by assumption #[]): Eq (∀ (B C : Iota), Eq (symmetric_difference B C) (union (difference B C) (difference C B))) True
% 3.93/4.09  Clause #1 (by assumption #[]): Eq (∀ (B : Iota), Eq (union B B) B) True
% 3.93/4.09  Clause #2 (by assumption #[]): Eq (∀ (B : Iota), Eq (difference B B) empty_set) True
% 3.93/4.09  Clause #11 (by assumption #[]): Eq (Not (∀ (B : Iota), Eq (symmetric_difference B B) empty_set)) True
% 3.93/4.09  Clause #15 (by clausification #[2]): ∀ (a : Iota), Eq (Eq (difference a a) empty_set) True
% 3.93/4.09  Clause #16 (by clausification #[15]): ∀ (a : Iota), Eq (difference a a) empty_set
% 3.93/4.09  Clause #17 (by clausification #[1]): ∀ (a : Iota), Eq (Eq (union a a) a) True
% 3.93/4.09  Clause #18 (by clausification #[17]): ∀ (a : Iota), Eq (union a a) a
% 3.93/4.09  Clause #19 (by clausification #[11]): Eq (∀ (B : Iota), Eq (symmetric_difference B B) empty_set) False
% 3.93/4.09  Clause #20 (by clausification #[19]): ∀ (a : Iota), Eq (Not (Eq (symmetric_difference (skS.0 0 a) (skS.0 0 a)) empty_set)) True
% 3.93/4.09  Clause #21 (by clausification #[20]): ∀ (a : Iota), Eq (Eq (symmetric_difference (skS.0 0 a) (skS.0 0 a)) empty_set) False
% 3.93/4.09  Clause #22 (by clausification #[21]): ∀ (a : Iota), Ne (symmetric_difference (skS.0 0 a) (skS.0 0 a)) empty_set
% 3.93/4.09  Clause #23 (by clausification #[0]): ∀ (a : Iota), Eq (∀ (C : Iota), Eq (symmetric_difference a C) (union (difference a C) (difference C a))) True
% 3.93/4.09  Clause #24 (by clausification #[23]): ∀ (a a_1 : Iota), Eq (Eq (symmetric_difference a a_1) (union (difference a a_1) (difference a_1 a))) True
% 3.93/4.09  Clause #25 (by clausification #[24]): ∀ (a a_1 : Iota), Eq (symmetric_difference a a_1) (union (difference a a_1) (difference a_1 a))
% 3.93/4.09  Clause #27 (by superposition #[25, 16]): ∀ (a : Iota), Eq (symmetric_difference a a) (union empty_set empty_set)
% 3.93/4.09  Clause #28 (by forward demodulation #[27, 18]): ∀ (a : Iota), Eq (symmetric_difference a a) empty_set
% 3.93/4.09  Clause #30 (by backward contextual literal cutting #[28, 22]): False
% 3.93/4.09  SZS output end Proof for theBenchmark.p
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