TSTP Solution File: SET604+3 by Bliksem---1.12

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Bliksem---1.12
% Problem  : SET604+3 : TPTP v8.1.0. Released v2.2.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : bliksem %s

% Computer : n011.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 0s
% DateTime : Mon Jul 18 22:50:40 EDT 2022

% Result   : Theorem 0.72s 1.08s
% Output   : Refutation 0.72s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.11  % Problem  : SET604+3 : TPTP v8.1.0. Released v2.2.0.
% 0.03/0.12  % Command  : bliksem %s
% 0.12/0.33  % Computer : n011.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit : 300
% 0.12/0.33  % DateTime : Sun Jul 10 14:04:11 EDT 2022
% 0.12/0.33  % CPUTime  : 
% 0.72/1.08  *** allocated 10000 integers for termspace/termends
% 0.72/1.08  *** allocated 10000 integers for clauses
% 0.72/1.08  *** allocated 10000 integers for justifications
% 0.72/1.08  Bliksem 1.12
% 0.72/1.08  
% 0.72/1.08  
% 0.72/1.08  Automatic Strategy Selection
% 0.72/1.08  
% 0.72/1.08  
% 0.72/1.08  Clauses:
% 0.72/1.08  
% 0.72/1.08  { subset( empty_set, X ) }.
% 0.72/1.08  { ! difference( X, Y ) = empty_set, subset( X, Y ) }.
% 0.72/1.08  { ! subset( X, Y ), difference( X, Y ) = empty_set }.
% 0.72/1.08  { ! member( X, empty_set ) }.
% 0.72/1.08  { ! member( Z, difference( X, Y ) ), member( Z, X ) }.
% 0.72/1.08  { ! member( Z, difference( X, Y ) ), ! member( Z, Y ) }.
% 0.72/1.08  { ! member( Z, X ), member( Z, Y ), member( Z, difference( X, Y ) ) }.
% 0.72/1.08  { ! X = Y, subset( X, Y ) }.
% 0.72/1.08  { ! X = Y, subset( Y, X ) }.
% 0.72/1.08  { ! subset( X, Y ), ! subset( Y, X ), X = Y }.
% 0.72/1.08  { ! subset( X, Y ), ! member( Z, X ), member( Z, Y ) }.
% 0.72/1.08  { ! member( skol1( Z, Y ), Y ), subset( X, Y ) }.
% 0.72/1.08  { member( skol1( X, Y ), X ), subset( X, Y ) }.
% 0.72/1.08  { subset( X, X ) }.
% 0.72/1.08  { ! empty( X ), ! member( Y, X ) }.
% 0.72/1.08  { member( skol2( X ), X ), empty( X ) }.
% 0.72/1.08  { ! difference( empty_set, skol3 ) = empty_set }.
% 0.72/1.08  
% 0.72/1.08  percentage equality = 0.181818, percentage horn = 0.823529
% 0.72/1.08  This is a problem with some equality
% 0.72/1.08  
% 0.72/1.08  
% 0.72/1.08  
% 0.72/1.08  Options Used:
% 0.72/1.08  
% 0.72/1.08  useres =            1
% 0.72/1.08  useparamod =        1
% 0.72/1.08  useeqrefl =         1
% 0.72/1.08  useeqfact =         1
% 0.72/1.08  usefactor =         1
% 0.72/1.08  usesimpsplitting =  0
% 0.72/1.08  usesimpdemod =      5
% 0.72/1.08  usesimpres =        3
% 0.72/1.08  
% 0.72/1.08  resimpinuse      =  1000
% 0.72/1.08  resimpclauses =     20000
% 0.72/1.08  substype =          eqrewr
% 0.72/1.08  backwardsubs =      1
% 0.72/1.08  selectoldest =      5
% 0.72/1.08  
% 0.72/1.08  litorderings [0] =  split
% 0.72/1.08  litorderings [1] =  extend the termordering, first sorting on arguments
% 0.72/1.08  
% 0.72/1.08  termordering =      kbo
% 0.72/1.08  
% 0.72/1.08  litapriori =        0
% 0.72/1.08  termapriori =       1
% 0.72/1.08  litaposteriori =    0
% 0.72/1.08  termaposteriori =   0
% 0.72/1.08  demodaposteriori =  0
% 0.72/1.08  ordereqreflfact =   0
% 0.72/1.08  
% 0.72/1.08  litselect =         negord
% 0.72/1.08  
% 0.72/1.08  maxweight =         15
% 0.72/1.08  maxdepth =          30000
% 0.72/1.08  maxlength =         115
% 0.72/1.08  maxnrvars =         195
% 0.72/1.08  excuselevel =       1
% 0.72/1.08  increasemaxweight = 1
% 0.72/1.08  
% 0.72/1.08  maxselected =       10000000
% 0.72/1.08  maxnrclauses =      10000000
% 0.72/1.08  
% 0.72/1.08  showgenerated =    0
% 0.72/1.08  showkept =         0
% 0.72/1.08  showselected =     0
% 0.72/1.08  showdeleted =      0
% 0.72/1.08  showresimp =       1
% 0.72/1.08  showstatus =       2000
% 0.72/1.08  
% 0.72/1.08  prologoutput =     0
% 0.72/1.08  nrgoals =          5000000
% 0.72/1.08  totalproof =       1
% 0.72/1.08  
% 0.72/1.08  Symbols occurring in the translation:
% 0.72/1.08  
% 0.72/1.08  {}  [0, 0]      (w:1, o:2, a:1, s:1, b:0), 
% 0.72/1.08  .  [1, 2]      (w:1, o:18, a:1, s:1, b:0), 
% 0.72/1.08  !  [4, 1]      (w:0, o:11, a:1, s:1, b:0), 
% 0.72/1.08  =  [13, 2]      (w:1, o:0, a:0, s:1, b:0), 
% 0.72/1.08  ==>  [14, 2]      (w:1, o:0, a:0, s:1, b:0), 
% 0.72/1.08  empty_set  [36, 0]      (w:1, o:7, a:1, s:1, b:0), 
% 0.72/1.08  subset  [37, 2]      (w:1, o:42, a:1, s:1, b:0), 
% 0.72/1.08  difference  [39, 2]      (w:1, o:43, a:1, s:1, b:0), 
% 0.72/1.08  member  [40, 2]      (w:1, o:44, a:1, s:1, b:0), 
% 0.72/1.08  empty  [42, 1]      (w:1, o:16, a:1, s:1, b:0), 
% 0.72/1.08  skol1  [43, 2]      (w:1, o:45, a:1, s:1, b:1), 
% 0.72/1.08  skol2  [44, 1]      (w:1, o:17, a:1, s:1, b:1), 
% 0.72/1.08  skol3  [45, 0]      (w:1, o:10, a:1, s:1, b:1).
% 0.72/1.08  
% 0.72/1.08  
% 0.72/1.08  Starting Search:
% 0.72/1.08  
% 0.72/1.08  
% 0.72/1.08  Bliksems!, er is een bewijs:
% 0.72/1.08  % SZS status Theorem
% 0.72/1.08  % SZS output start Refutation
% 0.72/1.08  
% 0.72/1.08  (0) {G0,W3,D2,L1,V1,M1} I { subset( empty_set, X ) }.
% 0.72/1.08  (2) {G0,W8,D3,L2,V2,M2} I { ! subset( X, Y ), difference( X, Y ) ==> 
% 0.72/1.08    empty_set }.
% 0.72/1.08  (15) {G0,W5,D3,L1,V0,M1} I { ! difference( empty_set, skol3 ) ==> empty_set
% 0.72/1.08     }.
% 0.72/1.08  (19) {G1,W0,D0,L0,V0,M0} R(2,15);r(0) {  }.
% 0.72/1.08  
% 0.72/1.08  
% 0.72/1.08  % SZS output end Refutation
% 0.72/1.08  found a proof!
% 0.72/1.08  
% 0.72/1.08  
% 0.72/1.08  Unprocessed initial clauses:
% 0.72/1.08  
% 0.72/1.08  (21) {G0,W3,D2,L1,V1,M1}  { subset( empty_set, X ) }.
% 0.72/1.08  (22) {G0,W8,D3,L2,V2,M2}  { ! difference( X, Y ) = empty_set, subset( X, Y
% 0.72/1.08     ) }.
% 0.72/1.08  (23) {G0,W8,D3,L2,V2,M2}  { ! subset( X, Y ), difference( X, Y ) = 
% 0.72/1.08    empty_set }.
% 0.72/1.08  (24) {G0,W3,D2,L1,V1,M1}  { ! member( X, empty_set ) }.
% 0.72/1.08  (25) {G0,W8,D3,L2,V3,M2}  { ! member( Z, difference( X, Y ) ), member( Z, X
% 0.72/1.08     ) }.
% 0.72/1.08  (26) {G0,W8,D3,L2,V3,M2}  { ! member( Z, difference( X, Y ) ), ! member( Z
% 0.72/1.08    , Y ) }.
% 0.72/1.08  (27) {G0,W11,D3,L3,V3,M3}  { ! member( Z, X ), member( Z, Y ), member( Z, 
% 0.72/1.08    difference( X, Y ) ) }.
% 0.72/1.08  (28) {G0,W6,D2,L2,V2,M2}  { ! X = Y, subset( X, Y ) }.
% 0.72/1.08  (29) {G0,W6,D2,L2,V2,M2}  { ! X = Y, subset( Y, X ) }.
% 0.72/1.08  (30) {G0,W9,D2,L3,V2,M3}  { ! subset( X, Y ), ! subset( Y, X ), X = Y }.
% 0.72/1.08  (31) {G0,W9,D2,L3,V3,M3}  { ! subset( X, Y ), ! member( Z, X ), member( Z, 
% 0.72/1.08    Y ) }.
% 0.72/1.08  (32) {G0,W8,D3,L2,V3,M2}  { ! member( skol1( Z, Y ), Y ), subset( X, Y )
% 0.72/1.08     }.
% 0.72/1.08  (33) {G0,W8,D3,L2,V2,M2}  { member( skol1( X, Y ), X ), subset( X, Y ) }.
% 0.72/1.08  (34) {G0,W3,D2,L1,V1,M1}  { subset( X, X ) }.
% 0.72/1.08  (35) {G0,W5,D2,L2,V2,M2}  { ! empty( X ), ! member( Y, X ) }.
% 0.72/1.08  (36) {G0,W6,D3,L2,V1,M2}  { member( skol2( X ), X ), empty( X ) }.
% 0.72/1.08  (37) {G0,W5,D3,L1,V0,M1}  { ! difference( empty_set, skol3 ) = empty_set
% 0.72/1.08     }.
% 0.72/1.08  
% 0.72/1.08  
% 0.72/1.08  Total Proof:
% 0.72/1.08  
% 0.72/1.08  subsumption: (0) {G0,W3,D2,L1,V1,M1} I { subset( empty_set, X ) }.
% 0.72/1.08  parent0: (21) {G0,W3,D2,L1,V1,M1}  { subset( empty_set, X ) }.
% 0.72/1.08  substitution0:
% 0.72/1.08     X := X
% 0.72/1.08  end
% 0.72/1.08  permutation0:
% 0.72/1.08     0 ==> 0
% 0.72/1.08  end
% 0.72/1.08  
% 0.72/1.08  subsumption: (2) {G0,W8,D3,L2,V2,M2} I { ! subset( X, Y ), difference( X, Y
% 0.72/1.08     ) ==> empty_set }.
% 0.72/1.08  parent0: (23) {G0,W8,D3,L2,V2,M2}  { ! subset( X, Y ), difference( X, Y ) =
% 0.72/1.08     empty_set }.
% 0.72/1.08  substitution0:
% 0.72/1.08     X := X
% 0.72/1.08     Y := Y
% 0.72/1.08  end
% 0.72/1.08  permutation0:
% 0.72/1.08     0 ==> 0
% 0.72/1.08     1 ==> 1
% 0.72/1.08  end
% 0.72/1.08  
% 0.72/1.08  subsumption: (15) {G0,W5,D3,L1,V0,M1} I { ! difference( empty_set, skol3 ) 
% 0.72/1.08    ==> empty_set }.
% 0.72/1.08  parent0: (37) {G0,W5,D3,L1,V0,M1}  { ! difference( empty_set, skol3 ) = 
% 0.72/1.08    empty_set }.
% 0.72/1.08  substitution0:
% 0.72/1.08  end
% 0.72/1.08  permutation0:
% 0.72/1.08     0 ==> 0
% 0.72/1.08  end
% 0.72/1.08  
% 0.72/1.08  eqswap: (46) {G0,W8,D3,L2,V2,M2}  { empty_set ==> difference( X, Y ), ! 
% 0.72/1.08    subset( X, Y ) }.
% 0.72/1.08  parent0[1]: (2) {G0,W8,D3,L2,V2,M2} I { ! subset( X, Y ), difference( X, Y
% 0.72/1.08     ) ==> empty_set }.
% 0.72/1.08  substitution0:
% 0.72/1.08     X := X
% 0.72/1.08     Y := Y
% 0.72/1.08  end
% 0.72/1.08  
% 0.72/1.08  eqswap: (47) {G0,W5,D3,L1,V0,M1}  { ! empty_set ==> difference( empty_set, 
% 0.72/1.08    skol3 ) }.
% 0.72/1.08  parent0[0]: (15) {G0,W5,D3,L1,V0,M1} I { ! difference( empty_set, skol3 ) 
% 0.72/1.08    ==> empty_set }.
% 0.72/1.08  substitution0:
% 0.72/1.08  end
% 0.72/1.08  
% 0.72/1.08  resolution: (48) {G1,W3,D2,L1,V0,M1}  { ! subset( empty_set, skol3 ) }.
% 0.72/1.08  parent0[0]: (47) {G0,W5,D3,L1,V0,M1}  { ! empty_set ==> difference( 
% 0.72/1.08    empty_set, skol3 ) }.
% 0.72/1.08  parent1[0]: (46) {G0,W8,D3,L2,V2,M2}  { empty_set ==> difference( X, Y ), !
% 0.72/1.08     subset( X, Y ) }.
% 0.72/1.08  substitution0:
% 0.72/1.08  end
% 0.72/1.08  substitution1:
% 0.72/1.08     X := empty_set
% 0.72/1.08     Y := skol3
% 0.72/1.08  end
% 0.72/1.08  
% 0.72/1.08  resolution: (49) {G1,W0,D0,L0,V0,M0}  {  }.
% 0.72/1.08  parent0[0]: (48) {G1,W3,D2,L1,V0,M1}  { ! subset( empty_set, skol3 ) }.
% 0.72/1.08  parent1[0]: (0) {G0,W3,D2,L1,V1,M1} I { subset( empty_set, X ) }.
% 0.72/1.08  substitution0:
% 0.72/1.08  end
% 0.72/1.08  substitution1:
% 0.72/1.08     X := skol3
% 0.72/1.08  end
% 0.72/1.08  
% 0.72/1.08  subsumption: (19) {G1,W0,D0,L0,V0,M0} R(2,15);r(0) {  }.
% 0.72/1.08  parent0: (49) {G1,W0,D0,L0,V0,M0}  {  }.
% 0.72/1.08  substitution0:
% 0.72/1.08  end
% 0.72/1.08  permutation0:
% 0.72/1.08  end
% 0.72/1.08  
% 0.72/1.08  Proof check complete!
% 0.72/1.08  
% 0.72/1.08  Memory use:
% 0.72/1.08  
% 0.72/1.08  space for terms:        425
% 0.72/1.08  space for clauses:      1168
% 0.72/1.08  
% 0.72/1.08  
% 0.72/1.08  clauses generated:      32
% 0.72/1.08  clauses kept:           20
% 0.72/1.08  clauses selected:       11
% 0.72/1.08  clauses deleted:        0
% 0.72/1.08  clauses inuse deleted:  0
% 0.72/1.08  
% 0.72/1.08  subsentry:          61
% 0.72/1.08  literals s-matched: 41
% 0.72/1.08  literals matched:   41
% 0.72/1.08  full subsumption:   5
% 0.72/1.08  
% 0.72/1.08  checksum:           -1352180048
% 0.72/1.08  
% 0.72/1.08  
% 0.72/1.08  Bliksem ended
%------------------------------------------------------------------------------