TSTP Solution File: SET602+3 by Bliksem---1.12

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Bliksem---1.12
% Problem  : SET602+3 : TPTP v8.1.0. Released v2.2.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : bliksem %s

% Computer : n011.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 0s
% DateTime : Mon Jul 18 22:50:38 EDT 2022

% Result   : Theorem 0.72s 1.11s
% Output   : Refutation 0.72s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.12  % Problem  : SET602+3 : TPTP v8.1.0. Released v2.2.0.
% 0.03/0.13  % Command  : bliksem %s
% 0.13/0.34  % Computer : n011.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit : 300
% 0.13/0.34  % DateTime : Sat Jul  9 23:20:41 EDT 2022
% 0.13/0.34  % CPUTime  : 
% 0.72/1.11  *** allocated 10000 integers for termspace/termends
% 0.72/1.11  *** allocated 10000 integers for clauses
% 0.72/1.11  *** allocated 10000 integers for justifications
% 0.72/1.11  Bliksem 1.12
% 0.72/1.11  
% 0.72/1.11  
% 0.72/1.11  Automatic Strategy Selection
% 0.72/1.11  
% 0.72/1.11  
% 0.72/1.11  Clauses:
% 0.72/1.11  
% 0.72/1.11  { ! difference( X, Y ) = empty_set, subset( X, Y ) }.
% 0.72/1.11  { ! subset( X, Y ), difference( X, Y ) = empty_set }.
% 0.72/1.11  { ! member( X, empty_set ) }.
% 0.72/1.11  { ! member( Z, difference( X, Y ) ), member( Z, X ) }.
% 0.72/1.11  { ! member( Z, difference( X, Y ) ), ! member( Z, Y ) }.
% 0.72/1.11  { ! member( Z, X ), member( Z, Y ), member( Z, difference( X, Y ) ) }.
% 0.72/1.11  { ! X = Y, subset( X, Y ) }.
% 0.72/1.11  { ! X = Y, subset( Y, X ) }.
% 0.72/1.11  { ! subset( X, Y ), ! subset( Y, X ), X = Y }.
% 0.72/1.11  { ! subset( X, Y ), ! member( Z, X ), member( Z, Y ) }.
% 0.72/1.11  { ! member( skol1( Z, Y ), Y ), subset( X, Y ) }.
% 0.72/1.11  { member( skol1( X, Y ), X ), subset( X, Y ) }.
% 0.72/1.11  { subset( X, X ) }.
% 0.72/1.11  { ! empty( X ), ! member( Y, X ) }.
% 0.72/1.11  { member( skol2( X ), X ), empty( X ) }.
% 0.72/1.11  { ! difference( skol3, skol3 ) = empty_set }.
% 0.72/1.11  
% 0.72/1.11  percentage equality = 0.187500, percentage horn = 0.812500
% 0.72/1.11  This is a problem with some equality
% 0.72/1.11  
% 0.72/1.11  
% 0.72/1.11  
% 0.72/1.11  Options Used:
% 0.72/1.11  
% 0.72/1.11  useres =            1
% 0.72/1.11  useparamod =        1
% 0.72/1.11  useeqrefl =         1
% 0.72/1.11  useeqfact =         1
% 0.72/1.11  usefactor =         1
% 0.72/1.11  usesimpsplitting =  0
% 0.72/1.11  usesimpdemod =      5
% 0.72/1.11  usesimpres =        3
% 0.72/1.11  
% 0.72/1.11  resimpinuse      =  1000
% 0.72/1.11  resimpclauses =     20000
% 0.72/1.11  substype =          eqrewr
% 0.72/1.11  backwardsubs =      1
% 0.72/1.11  selectoldest =      5
% 0.72/1.11  
% 0.72/1.11  litorderings [0] =  split
% 0.72/1.11  litorderings [1] =  extend the termordering, first sorting on arguments
% 0.72/1.11  
% 0.72/1.11  termordering =      kbo
% 0.72/1.11  
% 0.72/1.11  litapriori =        0
% 0.72/1.11  termapriori =       1
% 0.72/1.11  litaposteriori =    0
% 0.72/1.11  termaposteriori =   0
% 0.72/1.11  demodaposteriori =  0
% 0.72/1.11  ordereqreflfact =   0
% 0.72/1.11  
% 0.72/1.11  litselect =         negord
% 0.72/1.11  
% 0.72/1.11  maxweight =         15
% 0.72/1.11  maxdepth =          30000
% 0.72/1.11  maxlength =         115
% 0.72/1.11  maxnrvars =         195
% 0.72/1.11  excuselevel =       1
% 0.72/1.11  increasemaxweight = 1
% 0.72/1.11  
% 0.72/1.11  maxselected =       10000000
% 0.72/1.11  maxnrclauses =      10000000
% 0.72/1.11  
% 0.72/1.11  showgenerated =    0
% 0.72/1.11  showkept =         0
% 0.72/1.11  showselected =     0
% 0.72/1.11  showdeleted =      0
% 0.72/1.11  showresimp =       1
% 0.72/1.11  showstatus =       2000
% 0.72/1.11  
% 0.72/1.11  prologoutput =     0
% 0.72/1.11  nrgoals =          5000000
% 0.72/1.11  totalproof =       1
% 0.72/1.11  
% 0.72/1.11  Symbols occurring in the translation:
% 0.72/1.11  
% 0.72/1.11  {}  [0, 0]      (w:1, o:2, a:1, s:1, b:0), 
% 0.72/1.11  .  [1, 2]      (w:1, o:18, a:1, s:1, b:0), 
% 0.72/1.11  !  [4, 1]      (w:0, o:11, a:1, s:1, b:0), 
% 0.72/1.11  =  [13, 2]      (w:1, o:0, a:0, s:1, b:0), 
% 0.72/1.11  ==>  [14, 2]      (w:1, o:0, a:0, s:1, b:0), 
% 0.72/1.11  difference  [37, 2]      (w:1, o:42, a:1, s:1, b:0), 
% 0.72/1.11  empty_set  [38, 0]      (w:1, o:8, a:1, s:1, b:0), 
% 0.72/1.11  subset  [39, 2]      (w:1, o:43, a:1, s:1, b:0), 
% 0.72/1.11  member  [40, 2]      (w:1, o:44, a:1, s:1, b:0), 
% 0.72/1.11  empty  [42, 1]      (w:1, o:16, a:1, s:1, b:0), 
% 0.72/1.11  skol1  [43, 2]      (w:1, o:45, a:1, s:1, b:1), 
% 0.72/1.11  skol2  [44, 1]      (w:1, o:17, a:1, s:1, b:1), 
% 0.72/1.11  skol3  [45, 0]      (w:1, o:10, a:1, s:1, b:1).
% 0.72/1.11  
% 0.72/1.11  
% 0.72/1.11  Starting Search:
% 0.72/1.11  
% 0.72/1.11  
% 0.72/1.11  Bliksems!, er is een bewijs:
% 0.72/1.11  % SZS status Theorem
% 0.72/1.11  % SZS output start Refutation
% 0.72/1.11  
% 0.72/1.11  (1) {G0,W8,D3,L2,V2,M2} I { ! subset( X, Y ), difference( X, Y ) ==> 
% 0.72/1.11    empty_set }.
% 0.72/1.11  (11) {G0,W3,D2,L1,V1,M1} I { subset( X, X ) }.
% 0.72/1.11  (14) {G0,W5,D3,L1,V0,M1} I { ! difference( skol3, skol3 ) ==> empty_set }.
% 0.72/1.11  (19) {G1,W0,D0,L0,V0,M0} R(1,14);r(11) {  }.
% 0.72/1.11  
% 0.72/1.11  
% 0.72/1.11  % SZS output end Refutation
% 0.72/1.11  found a proof!
% 0.72/1.11  
% 0.72/1.11  
% 0.72/1.11  Unprocessed initial clauses:
% 0.72/1.11  
% 0.72/1.11  (21) {G0,W8,D3,L2,V2,M2}  { ! difference( X, Y ) = empty_set, subset( X, Y
% 0.72/1.11     ) }.
% 0.72/1.11  (22) {G0,W8,D3,L2,V2,M2}  { ! subset( X, Y ), difference( X, Y ) = 
% 0.72/1.11    empty_set }.
% 0.72/1.11  (23) {G0,W3,D2,L1,V1,M1}  { ! member( X, empty_set ) }.
% 0.72/1.11  (24) {G0,W8,D3,L2,V3,M2}  { ! member( Z, difference( X, Y ) ), member( Z, X
% 0.72/1.11     ) }.
% 0.72/1.11  (25) {G0,W8,D3,L2,V3,M2}  { ! member( Z, difference( X, Y ) ), ! member( Z
% 0.72/1.11    , Y ) }.
% 0.72/1.11  (26) {G0,W11,D3,L3,V3,M3}  { ! member( Z, X ), member( Z, Y ), member( Z, 
% 0.72/1.11    difference( X, Y ) ) }.
% 0.72/1.11  (27) {G0,W6,D2,L2,V2,M2}  { ! X = Y, subset( X, Y ) }.
% 0.72/1.11  (28) {G0,W6,D2,L2,V2,M2}  { ! X = Y, subset( Y, X ) }.
% 0.72/1.11  (29) {G0,W9,D2,L3,V2,M3}  { ! subset( X, Y ), ! subset( Y, X ), X = Y }.
% 0.72/1.11  (30) {G0,W9,D2,L3,V3,M3}  { ! subset( X, Y ), ! member( Z, X ), member( Z, 
% 0.72/1.11    Y ) }.
% 0.72/1.11  (31) {G0,W8,D3,L2,V3,M2}  { ! member( skol1( Z, Y ), Y ), subset( X, Y )
% 0.72/1.11     }.
% 0.72/1.11  (32) {G0,W8,D3,L2,V2,M2}  { member( skol1( X, Y ), X ), subset( X, Y ) }.
% 0.72/1.11  (33) {G0,W3,D2,L1,V1,M1}  { subset( X, X ) }.
% 0.72/1.11  (34) {G0,W5,D2,L2,V2,M2}  { ! empty( X ), ! member( Y, X ) }.
% 0.72/1.11  (35) {G0,W6,D3,L2,V1,M2}  { member( skol2( X ), X ), empty( X ) }.
% 0.72/1.11  (36) {G0,W5,D3,L1,V0,M1}  { ! difference( skol3, skol3 ) = empty_set }.
% 0.72/1.11  
% 0.72/1.11  
% 0.72/1.11  Total Proof:
% 0.72/1.11  
% 0.72/1.11  subsumption: (1) {G0,W8,D3,L2,V2,M2} I { ! subset( X, Y ), difference( X, Y
% 0.72/1.11     ) ==> empty_set }.
% 0.72/1.11  parent0: (22) {G0,W8,D3,L2,V2,M2}  { ! subset( X, Y ), difference( X, Y ) =
% 0.72/1.11     empty_set }.
% 0.72/1.11  substitution0:
% 0.72/1.11     X := X
% 0.72/1.11     Y := Y
% 0.72/1.11  end
% 0.72/1.11  permutation0:
% 0.72/1.11     0 ==> 0
% 0.72/1.11     1 ==> 1
% 0.72/1.11  end
% 0.72/1.11  
% 0.72/1.11  subsumption: (11) {G0,W3,D2,L1,V1,M1} I { subset( X, X ) }.
% 0.72/1.11  parent0: (33) {G0,W3,D2,L1,V1,M1}  { subset( X, X ) }.
% 0.72/1.11  substitution0:
% 0.72/1.11     X := X
% 0.72/1.11  end
% 0.72/1.11  permutation0:
% 0.72/1.11     0 ==> 0
% 0.72/1.11  end
% 0.72/1.11  
% 0.72/1.11  subsumption: (14) {G0,W5,D3,L1,V0,M1} I { ! difference( skol3, skol3 ) ==> 
% 0.72/1.11    empty_set }.
% 0.72/1.11  parent0: (36) {G0,W5,D3,L1,V0,M1}  { ! difference( skol3, skol3 ) = 
% 0.72/1.11    empty_set }.
% 0.72/1.11  substitution0:
% 0.72/1.11  end
% 0.72/1.11  permutation0:
% 0.72/1.11     0 ==> 0
% 0.72/1.11  end
% 0.72/1.11  
% 0.72/1.11  eqswap: (50) {G0,W8,D3,L2,V2,M2}  { empty_set ==> difference( X, Y ), ! 
% 0.72/1.11    subset( X, Y ) }.
% 0.72/1.11  parent0[1]: (1) {G0,W8,D3,L2,V2,M2} I { ! subset( X, Y ), difference( X, Y
% 0.72/1.12     ) ==> empty_set }.
% 0.72/1.12  substitution0:
% 0.72/1.12     X := X
% 0.72/1.12     Y := Y
% 0.72/1.12  end
% 0.72/1.12  
% 0.72/1.12  eqswap: (51) {G0,W5,D3,L1,V0,M1}  { ! empty_set ==> difference( skol3, 
% 0.72/1.12    skol3 ) }.
% 0.72/1.12  parent0[0]: (14) {G0,W5,D3,L1,V0,M1} I { ! difference( skol3, skol3 ) ==> 
% 0.72/1.12    empty_set }.
% 0.72/1.12  substitution0:
% 0.72/1.12  end
% 0.72/1.12  
% 0.72/1.12  resolution: (52) {G1,W3,D2,L1,V0,M1}  { ! subset( skol3, skol3 ) }.
% 0.72/1.12  parent0[0]: (51) {G0,W5,D3,L1,V0,M1}  { ! empty_set ==> difference( skol3, 
% 0.72/1.12    skol3 ) }.
% 0.72/1.12  parent1[0]: (50) {G0,W8,D3,L2,V2,M2}  { empty_set ==> difference( X, Y ), !
% 0.72/1.12     subset( X, Y ) }.
% 0.72/1.12  substitution0:
% 0.72/1.12  end
% 0.72/1.12  substitution1:
% 0.72/1.12     X := skol3
% 0.72/1.12     Y := skol3
% 0.72/1.12  end
% 0.72/1.12  
% 0.72/1.12  resolution: (53) {G1,W0,D0,L0,V0,M0}  {  }.
% 0.72/1.12  parent0[0]: (52) {G1,W3,D2,L1,V0,M1}  { ! subset( skol3, skol3 ) }.
% 0.72/1.12  parent1[0]: (11) {G0,W3,D2,L1,V1,M1} I { subset( X, X ) }.
% 0.72/1.12  substitution0:
% 0.72/1.12  end
% 0.72/1.12  substitution1:
% 0.72/1.12     X := skol3
% 0.72/1.12  end
% 0.72/1.12  
% 0.72/1.12  subsumption: (19) {G1,W0,D0,L0,V0,M0} R(1,14);r(11) {  }.
% 0.72/1.12  parent0: (53) {G1,W0,D0,L0,V0,M0}  {  }.
% 0.72/1.12  substitution0:
% 0.72/1.12  end
% 0.72/1.12  permutation0:
% 0.72/1.12  end
% 0.72/1.12  
% 0.72/1.12  Proof check complete!
% 0.72/1.12  
% 0.72/1.12  Memory use:
% 0.72/1.12  
% 0.72/1.12  space for terms:        423
% 0.72/1.12  space for clauses:      1150
% 0.72/1.12  
% 0.72/1.12  
% 0.72/1.12  clauses generated:      32
% 0.72/1.12  clauses kept:           20
% 0.72/1.12  clauses selected:       11
% 0.72/1.12  clauses deleted:        0
% 0.72/1.12  clauses inuse deleted:  0
% 0.72/1.12  
% 0.72/1.12  subsentry:          87
% 0.72/1.12  literals s-matched: 61
% 0.72/1.12  literals matched:   61
% 0.72/1.12  full subsumption:   7
% 0.72/1.12  
% 0.72/1.12  checksum:           674060
% 0.72/1.12  
% 0.72/1.12  
% 0.72/1.12  Bliksem ended
%------------------------------------------------------------------------------