TSTP Solution File: SET599^5 by Duper---1.0

View Problem - Process Solution

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% File     : Duper---1.0
% Problem  : SET599^5 : TPTP v8.1.2. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n015.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 14:46:59 EDT 2023

% Result   : Theorem 3.63s 3.82s
% Output   : Proof 3.63s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12  % Problem    : SET599^5 : TPTP v8.1.2. Released v4.0.0.
% 0.00/0.14  % Command    : duper %s
% 0.14/0.35  % Computer : n015.cluster.edu
% 0.14/0.35  % Model    : x86_64 x86_64
% 0.14/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.35  % Memory   : 8042.1875MB
% 0.14/0.35  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.14/0.35  % CPULimit   : 300
% 0.14/0.35  % WCLimit    : 300
% 0.14/0.35  % DateTime   : Sat Aug 26 16:01:08 EDT 2023
% 0.14/0.35  % CPUTime    : 
% 3.63/3.82  SZS status Theorem for theBenchmark.p
% 3.63/3.82  SZS output start Proof for theBenchmark.p
% 3.63/3.82  Clause #0 (by assumption #[]): Eq (Not (∀ (X Y : a → Prop) (Xx : a), And (X Xx) (Not (Y Xx)) → Or (And (X Xx) (Not (Y Xx))) (And (Y Xx) (Not (X Xx)))))
% 3.63/3.82    True
% 3.63/3.82  Clause #1 (by clausification #[0]): Eq (∀ (X Y : a → Prop) (Xx : a), And (X Xx) (Not (Y Xx)) → Or (And (X Xx) (Not (Y Xx))) (And (Y Xx) (Not (X Xx)))) False
% 3.63/3.82  Clause #2 (by clausification #[1]): ∀ (a_1 : a → Prop),
% 3.63/3.82    Eq
% 3.63/3.82      (Not
% 3.63/3.82        (∀ (Y : a → Prop) (Xx : a),
% 3.63/3.82          And (skS.0 0 a_1 Xx) (Not (Y Xx)) → Or (And (skS.0 0 a_1 Xx) (Not (Y Xx))) (And (Y Xx) (Not (skS.0 0 a_1 Xx)))))
% 3.63/3.82      True
% 3.63/3.82  Clause #3 (by clausification #[2]): ∀ (a_1 : a → Prop),
% 3.63/3.82    Eq
% 3.63/3.82      (∀ (Y : a → Prop) (Xx : a),
% 3.63/3.82        And (skS.0 0 a_1 Xx) (Not (Y Xx)) → Or (And (skS.0 0 a_1 Xx) (Not (Y Xx))) (And (Y Xx) (Not (skS.0 0 a_1 Xx))))
% 3.63/3.82      False
% 3.63/3.82  Clause #4 (by clausification #[3]): ∀ (a_1 a_2 : a → Prop),
% 3.63/3.82    Eq
% 3.63/3.82      (Not
% 3.63/3.82        (∀ (Xx : a),
% 3.63/3.82          And (skS.0 0 a_1 Xx) (Not (skS.0 1 a_1 a_2 Xx)) →
% 3.63/3.82            Or (And (skS.0 0 a_1 Xx) (Not (skS.0 1 a_1 a_2 Xx))) (And (skS.0 1 a_1 a_2 Xx) (Not (skS.0 0 a_1 Xx)))))
% 3.63/3.82      True
% 3.63/3.82  Clause #5 (by clausification #[4]): ∀ (a_1 a_2 : a → Prop),
% 3.63/3.82    Eq
% 3.63/3.82      (∀ (Xx : a),
% 3.63/3.82        And (skS.0 0 a_1 Xx) (Not (skS.0 1 a_1 a_2 Xx)) →
% 3.63/3.82          Or (And (skS.0 0 a_1 Xx) (Not (skS.0 1 a_1 a_2 Xx))) (And (skS.0 1 a_1 a_2 Xx) (Not (skS.0 0 a_1 Xx))))
% 3.63/3.82      False
% 3.63/3.82  Clause #6 (by clausification #[5]): ∀ (a_1 a_2 : a → Prop) (a_3 : a),
% 3.63/3.82    Eq
% 3.63/3.82      (Not
% 3.63/3.82        (And (skS.0 0 a_1 (skS.0 2 a_1 a_2 a_3)) (Not (skS.0 1 a_1 a_2 (skS.0 2 a_1 a_2 a_3))) →
% 3.63/3.82          Or (And (skS.0 0 a_1 (skS.0 2 a_1 a_2 a_3)) (Not (skS.0 1 a_1 a_2 (skS.0 2 a_1 a_2 a_3))))
% 3.63/3.82            (And (skS.0 1 a_1 a_2 (skS.0 2 a_1 a_2 a_3)) (Not (skS.0 0 a_1 (skS.0 2 a_1 a_2 a_3))))))
% 3.63/3.82      True
% 3.63/3.82  Clause #7 (by clausification #[6]): ∀ (a_1 a_2 : a → Prop) (a_3 : a),
% 3.63/3.82    Eq
% 3.63/3.82      (And (skS.0 0 a_1 (skS.0 2 a_1 a_2 a_3)) (Not (skS.0 1 a_1 a_2 (skS.0 2 a_1 a_2 a_3))) →
% 3.63/3.82        Or (And (skS.0 0 a_1 (skS.0 2 a_1 a_2 a_3)) (Not (skS.0 1 a_1 a_2 (skS.0 2 a_1 a_2 a_3))))
% 3.63/3.82          (And (skS.0 1 a_1 a_2 (skS.0 2 a_1 a_2 a_3)) (Not (skS.0 0 a_1 (skS.0 2 a_1 a_2 a_3)))))
% 3.63/3.82      False
% 3.63/3.82  Clause #8 (by clausification #[7]): ∀ (a_1 a_2 : a → Prop) (a_3 : a),
% 3.63/3.82    Eq (And (skS.0 0 a_1 (skS.0 2 a_1 a_2 a_3)) (Not (skS.0 1 a_1 a_2 (skS.0 2 a_1 a_2 a_3)))) True
% 3.63/3.82  Clause #9 (by clausification #[7]): ∀ (a_1 a_2 : a → Prop) (a_3 : a),
% 3.63/3.82    Eq
% 3.63/3.82      (Or (And (skS.0 0 a_1 (skS.0 2 a_1 a_2 a_3)) (Not (skS.0 1 a_1 a_2 (skS.0 2 a_1 a_2 a_3))))
% 3.63/3.82        (And (skS.0 1 a_1 a_2 (skS.0 2 a_1 a_2 a_3)) (Not (skS.0 0 a_1 (skS.0 2 a_1 a_2 a_3)))))
% 3.63/3.82      False
% 3.63/3.82  Clause #10 (by clausification #[8]): ∀ (a_1 a_2 : a → Prop) (a_3 : a), Eq (Not (skS.0 1 a_1 a_2 (skS.0 2 a_1 a_2 a_3))) True
% 3.63/3.82  Clause #11 (by clausification #[8]): ∀ (a_1 a_2 : a → Prop) (a_3 : a), Eq (skS.0 0 a_1 (skS.0 2 a_1 a_2 a_3)) True
% 3.63/3.82  Clause #12 (by clausification #[10]): ∀ (a_1 a_2 : a → Prop) (a_3 : a), Eq (skS.0 1 a_1 a_2 (skS.0 2 a_1 a_2 a_3)) False
% 3.63/3.82  Clause #14 (by clausification #[9]): ∀ (a_1 a_2 : a → Prop) (a_3 : a),
% 3.63/3.82    Eq (And (skS.0 0 a_1 (skS.0 2 a_1 a_2 a_3)) (Not (skS.0 1 a_1 a_2 (skS.0 2 a_1 a_2 a_3)))) False
% 3.63/3.82  Clause #18 (by clausification #[14]): ∀ (a_1 a_2 : a → Prop) (a_3 : a),
% 3.63/3.82    Or (Eq (skS.0 0 a_1 (skS.0 2 a_1 a_2 a_3)) False) (Eq (Not (skS.0 1 a_1 a_2 (skS.0 2 a_1 a_2 a_3))) False)
% 3.63/3.82  Clause #19 (by clausification #[18]): ∀ (a_1 a_2 : a → Prop) (a_3 : a),
% 3.63/3.82    Or (Eq (skS.0 0 a_1 (skS.0 2 a_1 a_2 a_3)) False) (Eq (skS.0 1 a_1 a_2 (skS.0 2 a_1 a_2 a_3)) True)
% 3.63/3.82  Clause #20 (by forward demodulation #[19, 11]): ∀ (a_1 a_2 : a → Prop) (a_3 : a), Or (Eq True False) (Eq (skS.0 1 a_1 a_2 (skS.0 2 a_1 a_2 a_3)) True)
% 3.63/3.82  Clause #21 (by clausification #[20]): ∀ (a_1 a_2 : a → Prop) (a_3 : a), Eq (skS.0 1 a_1 a_2 (skS.0 2 a_1 a_2 a_3)) True
% 3.63/3.82  Clause #22 (by superposition #[21, 12]): Eq True False
% 3.63/3.82  Clause #23 (by clausification #[22]): False
% 3.63/3.82  SZS output end Proof for theBenchmark.p
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