TSTP Solution File: SET591+3 by SPASS---3.9

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%------------------------------------------------------------------------------
% File     : SPASS---3.9
% Problem  : SET591+3 : TPTP v8.1.0. Released v2.2.0.
% Transfm  : none
% Format   : tptp
% Command  : run_spass %d %s

% Computer : n009.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Tue Jul 19 05:27:12 EDT 2022

% Result   : Theorem 0.20s 0.45s
% Output   : Refutation 0.20s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    4
%            Number of leaves      :    7
% Syntax   : Number of clauses     :   14 (   8 unt;   1 nHn;  14 RR)
%            Number of literals    :   22 (   0 equ;  13 neg)
%            Maximal clause size   :    3 (   1 avg)
%            Maximal term depth    :    2 (   1 avg)
%            Number of predicates  :    4 (   3 usr;   1 prp; 0-2 aty)
%            Number of functors    :    8 (   8 usr;   6 con; 0-2 aty)
%            Number of variables   :    0 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(2,axiom,
    ~ equal(skc2,empty_set),
    file('SET591+3.p',unknown),
    [] ).

cnf(3,axiom,
    ~ member(u,empty_set),
    file('SET591+3.p',unknown),
    [] ).

cnf(4,axiom,
    subset(skc2,difference(skc3,skc2)),
    file('SET591+3.p',unknown),
    [] ).

cnf(9,axiom,
    ( subset(u,v)
    | member(skf2(v,u),u) ),
    file('SET591+3.p',unknown),
    [] ).

cnf(12,axiom,
    ( ~ member(u,v)
    | ~ member(u,difference(w,v)) ),
    file('SET591+3.p',unknown),
    [] ).

cnf(13,axiom,
    ( ~ member(u,v)
    | ~ subset(v,w)
    | member(u,w) ),
    file('SET591+3.p',unknown),
    [] ).

cnf(14,axiom,
    ( ~ subset(u,v)
    | ~ subset(v,u)
    | equal(v,u) ),
    file('SET591+3.p',unknown),
    [] ).

cnf(16,plain,
    ( ~ subset(empty_set,skc2)
    | ~ subset(skc2,empty_set) ),
    inference(res,[status(thm),theory(equality)],[14,2]),
    [iquote('0:Res:14.2,2.0')] ).

cnf(19,plain,
    ( ~ member(u,skc2)
    | member(u,difference(skc3,skc2)) ),
    inference(res,[status(thm),theory(equality)],[4,13]),
    [iquote('0:Res:4.0,13.0')] ).

cnf(21,plain,
    ~ member(u,skc2),
    inference(mrr,[status(thm)],[19,12]),
    [iquote('0:MRR:19.1,12.1')] ).

cnf(26,plain,
    subset(empty_set,u),
    inference(res,[status(thm),theory(equality)],[9,3]),
    [iquote('0:Res:9.1,3.0')] ).

cnf(27,plain,
    subset(skc2,u),
    inference(res,[status(thm),theory(equality)],[9,21]),
    [iquote('0:Res:9.1,21.0')] ).

cnf(29,plain,
    ~ subset(skc2,empty_set),
    inference(mrr,[status(thm)],[16,26]),
    [iquote('0:MRR:16.0,26.0')] ).

cnf(30,plain,
    $false,
    inference(mrr,[status(thm)],[29,27]),
    [iquote('0:MRR:29.0,27.0')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.11/0.12  % Problem  : SET591+3 : TPTP v8.1.0. Released v2.2.0.
% 0.11/0.13  % Command  : run_spass %d %s
% 0.13/0.34  % Computer : n009.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit : 300
% 0.13/0.34  % WCLimit  : 600
% 0.13/0.34  % DateTime : Sun Jul 10 12:39:52 EDT 2022
% 0.13/0.34  % CPUTime  : 
% 0.20/0.45  
% 0.20/0.45  SPASS V 3.9 
% 0.20/0.45  SPASS beiseite: Proof found.
% 0.20/0.45  % SZS status Theorem
% 0.20/0.45  Problem: /export/starexec/sandbox2/benchmark/theBenchmark.p 
% 0.20/0.45  SPASS derived 13 clauses, backtracked 0 clauses, performed 0 splits and kept 23 clauses.
% 0.20/0.45  SPASS allocated 97705 KBytes.
% 0.20/0.45  SPASS spent	0:00:00.09 on the problem.
% 0.20/0.45  		0:00:00.04 for the input.
% 0.20/0.45  		0:00:00.03 for the FLOTTER CNF translation.
% 0.20/0.45  		0:00:00.00 for inferences.
% 0.20/0.45  		0:00:00.00 for the backtracking.
% 0.20/0.45  		0:00:00.00 for the reduction.
% 0.20/0.45  
% 0.20/0.45  
% 0.20/0.45  Here is a proof with depth 2, length 14 :
% 0.20/0.45  % SZS output start Refutation
% See solution above
% 0.20/0.45  Formulae used in the proof : prove_th50 empty_set_defn subset_defn difference_defn equal_defn
% 0.20/0.45  
%------------------------------------------------------------------------------