TSTP Solution File: SET586+3 by Otter---3.3

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Otter---3.3
% Problem  : SET586+3 : TPTP v8.1.0. Released v2.2.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : otter-tptp-script %s

% Computer : n007.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Wed Jul 27 13:13:44 EDT 2022

% Result   : Theorem 2.06s 2.26s
% Output   : Refutation 2.06s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    7
%            Number of leaves      :    9
% Syntax   : Number of clauses     :   17 (  11 unt;   1 nHn;  15 RR)
%            Number of literals    :   25 (   1 equ;   9 neg)
%            Maximal clause size   :    3 (   1 avg)
%            Maximal term depth    :    3 (   1 avg)
%            Number of predicates  :    4 (   2 usr;   1 prp; 0-2 aty)
%            Number of functors    :    5 (   5 usr;   3 con; 0-2 aty)
%            Number of variables   :   18 (   2 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(1,axiom,
    ( ~ member(A,intersection(B,C))
    | member(A,B) ),
    file('SET586+3.p',unknown),
    [] ).

cnf(2,axiom,
    ( ~ member(A,intersection(B,C))
    | member(A,C) ),
    file('SET586+3.p',unknown),
    [] ).

cnf(3,axiom,
    ( member(A,intersection(B,C))
    | ~ member(A,B)
    | ~ member(A,C) ),
    file('SET586+3.p',unknown),
    [] ).

cnf(4,axiom,
    ( ~ subset(A,B)
    | ~ member(C,A)
    | member(C,B) ),
    file('SET586+3.p',unknown),
    [] ).

cnf(5,axiom,
    ( subset(A,B)
    | ~ member(dollar_f1(A,B),B) ),
    file('SET586+3.p',unknown),
    [] ).

cnf(9,axiom,
    ~ subset(intersection(dollar_c3,dollar_c1),intersection(dollar_c2,dollar_c1)),
    file('SET586+3.p',unknown),
    [] ).

cnf(13,axiom,
    ( subset(A,B)
    | member(dollar_f1(A,B),A) ),
    file('SET586+3.p',unknown),
    [] ).

cnf(14,axiom,
    intersection(A,B) = intersection(B,A),
    file('SET586+3.p',unknown),
    [] ).

cnf(17,axiom,
    subset(dollar_c3,dollar_c2),
    file('SET586+3.p',unknown),
    [] ).

cnf(21,plain,
    ~ subset(intersection(dollar_c3,dollar_c1),intersection(dollar_c1,dollar_c2)),
    inference(para_from,[status(thm),theory(equality)],[14,9]),
    [iquote('para_from,14.1.1,9.1.2')] ).

cnf(30,plain,
    member(dollar_f1(intersection(dollar_c3,dollar_c1),intersection(dollar_c1,dollar_c2)),intersection(dollar_c3,dollar_c1)),
    inference(hyper,[status(thm)],[13,21]),
    [iquote('hyper,13,21')] ).

cnf(50,plain,
    member(dollar_f1(intersection(dollar_c3,dollar_c1),intersection(dollar_c1,dollar_c2)),dollar_c1),
    inference(hyper,[status(thm)],[30,2]),
    [iquote('hyper,30,2')] ).

cnf(51,plain,
    member(dollar_f1(intersection(dollar_c3,dollar_c1),intersection(dollar_c1,dollar_c2)),dollar_c3),
    inference(hyper,[status(thm)],[30,1]),
    [iquote('hyper,30,1')] ).

cnf(249,plain,
    member(dollar_f1(intersection(dollar_c3,dollar_c1),intersection(dollar_c1,dollar_c2)),dollar_c2),
    inference(hyper,[status(thm)],[51,4,17]),
    [iquote('hyper,51,4,17')] ).

cnf(579,plain,
    member(dollar_f1(intersection(dollar_c3,dollar_c1),intersection(dollar_c1,dollar_c2)),intersection(dollar_c1,dollar_c2)),
    inference(hyper,[status(thm)],[249,3,50]),
    [iquote('hyper,249,3,50')] ).

cnf(2376,plain,
    subset(intersection(dollar_c3,dollar_c1),intersection(dollar_c1,dollar_c2)),
    inference(hyper,[status(thm)],[579,5]),
    [iquote('hyper,579,5')] ).

cnf(2377,plain,
    $false,
    inference(binary,[status(thm)],[2376,21]),
    [iquote('binary,2376.1,21.1')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.10/0.12  % Problem  : SET586+3 : TPTP v8.1.0. Released v2.2.0.
% 0.10/0.13  % Command  : otter-tptp-script %s
% 0.12/0.34  % Computer : n007.cluster.edu
% 0.12/0.34  % Model    : x86_64 x86_64
% 0.12/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.34  % Memory   : 8042.1875MB
% 0.12/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.34  % CPULimit : 300
% 0.12/0.34  % WCLimit  : 300
% 0.12/0.34  % DateTime : Wed Jul 27 10:37:46 EDT 2022
% 0.12/0.34  % CPUTime  : 
% 2.06/2.26  ----- Otter 3.3f, August 2004 -----
% 2.06/2.26  The process was started by sandbox2 on n007.cluster.edu,
% 2.06/2.26  Wed Jul 27 10:37:46 2022
% 2.06/2.26  The command was "./otter".  The process ID is 6205.
% 2.06/2.26  
% 2.06/2.26  set(prolog_style_variables).
% 2.06/2.26  set(auto).
% 2.06/2.26     dependent: set(auto1).
% 2.06/2.26     dependent: set(process_input).
% 2.06/2.26     dependent: clear(print_kept).
% 2.06/2.26     dependent: clear(print_new_demod).
% 2.06/2.26     dependent: clear(print_back_demod).
% 2.06/2.26     dependent: clear(print_back_sub).
% 2.06/2.26     dependent: set(control_memory).
% 2.06/2.26     dependent: assign(max_mem, 12000).
% 2.06/2.26     dependent: assign(pick_given_ratio, 4).
% 2.06/2.26     dependent: assign(stats_level, 1).
% 2.06/2.26     dependent: assign(max_seconds, 10800).
% 2.06/2.26  clear(print_given).
% 2.06/2.26  
% 2.06/2.26  formula_list(usable).
% 2.06/2.26  all A (A=A).
% 2.06/2.26  all B C D (member(D,intersection(B,C))<->member(D,B)&member(D,C)).
% 2.06/2.26  all B C (subset(B,C)<-> (all D (member(D,B)->member(D,C)))).
% 2.06/2.26  all B C (intersection(B,C)=intersection(C,B)).
% 2.06/2.26  all B subset(B,B).
% 2.06/2.26  all B C (B=C<-> (all D (member(D,B)<->member(D,C)))).
% 2.06/2.26  -(all B C D (subset(B,C)->subset(intersection(B,D),intersection(C,D)))).
% 2.06/2.26  end_of_list.
% 2.06/2.26  
% 2.06/2.26  -------> usable clausifies to:
% 2.06/2.26  
% 2.06/2.26  list(usable).
% 2.06/2.26  0 [] A=A.
% 2.06/2.26  0 [] -member(D,intersection(B,C))|member(D,B).
% 2.06/2.26  0 [] -member(D,intersection(B,C))|member(D,C).
% 2.06/2.26  0 [] member(D,intersection(B,C))| -member(D,B)| -member(D,C).
% 2.06/2.26  0 [] -subset(B,C)| -member(D,B)|member(D,C).
% 2.06/2.26  0 [] subset(B,C)|member($f1(B,C),B).
% 2.06/2.26  0 [] subset(B,C)| -member($f1(B,C),C).
% 2.06/2.26  0 [] intersection(B,C)=intersection(C,B).
% 2.06/2.26  0 [] subset(B,B).
% 2.06/2.26  0 [] B!=C| -member(D,B)|member(D,C).
% 2.06/2.26  0 [] B!=C|member(D,B)| -member(D,C).
% 2.06/2.26  0 [] B=C|member($f2(B,C),B)|member($f2(B,C),C).
% 2.06/2.26  0 [] B=C| -member($f2(B,C),B)| -member($f2(B,C),C).
% 2.06/2.26  0 [] subset($c3,$c2).
% 2.06/2.26  0 [] -subset(intersection($c3,$c1),intersection($c2,$c1)).
% 2.06/2.26  end_of_list.
% 2.06/2.26  
% 2.06/2.26  SCAN INPUT: prop=0, horn=0, equality=1, symmetry=0, max_lits=3.
% 2.06/2.26  
% 2.06/2.26  This ia a non-Horn set with equality.  The strategy will be
% 2.06/2.26  Knuth-Bendix, ordered hyper_res, factoring, and unit
% 2.06/2.26  deletion, with positive clauses in sos and nonpositive
% 2.06/2.26  clauses in usable.
% 2.06/2.26  
% 2.06/2.26     dependent: set(knuth_bendix).
% 2.06/2.26     dependent: set(anl_eq).
% 2.06/2.26     dependent: set(para_from).
% 2.06/2.26     dependent: set(para_into).
% 2.06/2.26     dependent: clear(para_from_right).
% 2.06/2.26     dependent: clear(para_into_right).
% 2.06/2.26     dependent: set(para_from_vars).
% 2.06/2.26     dependent: set(eq_units_both_ways).
% 2.06/2.26     dependent: set(dynamic_demod_all).
% 2.06/2.26     dependent: set(dynamic_demod).
% 2.06/2.26     dependent: set(order_eq).
% 2.06/2.26     dependent: set(back_demod).
% 2.06/2.26     dependent: set(lrpo).
% 2.06/2.26     dependent: set(hyper_res).
% 2.06/2.26     dependent: set(unit_deletion).
% 2.06/2.26     dependent: set(factor).
% 2.06/2.26  
% 2.06/2.26  ------------> process usable:
% 2.06/2.26  ** KEPT (pick-wt=8): 1 [] -member(A,intersection(B,C))|member(A,B).
% 2.06/2.26  ** KEPT (pick-wt=8): 2 [] -member(A,intersection(B,C))|member(A,C).
% 2.06/2.26  ** KEPT (pick-wt=11): 3 [] member(A,intersection(B,C))| -member(A,B)| -member(A,C).
% 2.06/2.26  ** KEPT (pick-wt=9): 4 [] -subset(A,B)| -member(C,A)|member(C,B).
% 2.06/2.26  ** KEPT (pick-wt=8): 5 [] subset(A,B)| -member($f1(A,B),B).
% 2.06/2.26  ** KEPT (pick-wt=9): 6 [] A!=B| -member(C,A)|member(C,B).
% 2.06/2.26  ** KEPT (pick-wt=9): 7 [] A!=B|member(C,A)| -member(C,B).
% 2.06/2.26  ** KEPT (pick-wt=13): 8 [] A=B| -member($f2(A,B),A)| -member($f2(A,B),B).
% 2.06/2.26  ** KEPT (pick-wt=7): 9 [] -subset(intersection($c3,$c1),intersection($c2,$c1)).
% 2.06/2.26  
% 2.06/2.26  ------------> process sos:
% 2.06/2.26  ** KEPT (pick-wt=3): 12 [] A=A.
% 2.06/2.26  ** KEPT (pick-wt=8): 13 [] subset(A,B)|member($f1(A,B),A).
% 2.06/2.26  ** KEPT (pick-wt=7): 14 [] intersection(A,B)=intersection(B,A).
% 2.06/2.26  ** KEPT (pick-wt=3): 15 [] subset(A,A).
% 2.06/2.26  ** KEPT (pick-wt=13): 16 [] A=B|member($f2(A,B),A)|member($f2(A,B),B).
% 2.06/2.26  ** KEPT (pick-wt=3): 17 [] subset($c3,$c2).
% 2.06/2.26    Following clause subsumed by 12 during input processing: 0 [copy,12,flip.1] A=A.
% 2.06/2.26  12 back subsumes 11.
% 2.06/2.26    Following clause subsumed by 14 during input processing: 0 [copy,14,flip.1] intersection(A,B)=intersection(B,A).
% 2.06/2.26  
% 2.06/2.26  ======= end of input processing =======
% 2.06/2.26  
% 2.06/2.26  =========== start of search ===========
% 2.06/2.26  
% 2.06/2.26  -------- PROOF -------- 
% 2.06/2.26  
% 2.06/2.26  ----> UNIT CONFLICT at   0.27 sec ----> 2377 [binary,2376.1,21.1] $F.
% 2.06/2.26  
% 2.06/2.26  Length of proof is 7.  Level of proof is 6.
% 2.06/2.26  
% 2.06/2.26  ---------------- PROOF ----------------
% 2.06/2.26  % SZS status Theorem
% 2.06/2.26  % SZS output start Refutation
% See solution above
% 2.06/2.26  ------------ end of proof -------------
% 2.06/2.26  
% 2.06/2.26  
% 2.06/2.26  Search stopped by max_proofs option.
% 2.06/2.26  
% 2.06/2.26  
% 2.06/2.26  Search stopped by max_proofs option.
% 2.06/2.26  
% 2.06/2.26  ============ end of search ============
% 2.06/2.26  
% 2.06/2.26  -------------- statistics -------------
% 2.06/2.26  clauses given                 78
% 2.06/2.26  clauses generated           5176
% 2.06/2.26  clauses kept                2376
% 2.06/2.26  clauses forward subsumed    2776
% 2.06/2.26  clauses back subsumed         66
% 2.06/2.26  Kbytes malloced             2929
% 2.06/2.26  
% 2.06/2.26  ----------- times (seconds) -----------
% 2.06/2.26  user CPU time          0.27          (0 hr, 0 min, 0 sec)
% 2.06/2.26  system CPU time        0.00          (0 hr, 0 min, 0 sec)
% 2.06/2.26  wall-clock time        2             (0 hr, 0 min, 2 sec)
% 2.06/2.26  
% 2.06/2.26  That finishes the proof of the theorem.
% 2.06/2.26  
% 2.06/2.26  Process 6205 finished Wed Jul 27 10:37:48 2022
% 2.06/2.26  Otter interrupted
% 2.06/2.26  PROOF FOUND
%------------------------------------------------------------------------------