TSTP Solution File: SET586^5 by Duper---1.0

View Problem - Process Solution

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% File     : Duper---1.0
% Problem  : SET586^5 : TPTP v8.1.2. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n016.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 14:46:54 EDT 2023

% Result   : Theorem 3.46s 3.71s
% Output   : Proof 3.46s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12  % Problem    : SET586^5 : TPTP v8.1.2. Released v4.0.0.
% 0.00/0.14  % Command    : duper %s
% 0.13/0.35  % Computer : n016.cluster.edu
% 0.13/0.35  % Model    : x86_64 x86_64
% 0.13/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.35  % Memory   : 8042.1875MB
% 0.13/0.35  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.35  % CPULimit   : 300
% 0.13/0.35  % WCLimit    : 300
% 0.13/0.35  % DateTime   : Sat Aug 26 17:05:57 EDT 2023
% 0.13/0.35  % CPUTime    : 
% 3.46/3.71  SZS status Theorem for theBenchmark.p
% 3.46/3.71  SZS output start Proof for theBenchmark.p
% 3.46/3.71  Clause #0 (by assumption #[]): Eq (Not (∀ (X Y Z : a → Prop), (∀ (Xx : a), X Xx → Y Xx) → ∀ (Xx : a), And (X Xx) (Z Xx) → And (Y Xx) (Z Xx))) True
% 3.46/3.71  Clause #1 (by clausification #[0]): Eq (∀ (X Y Z : a → Prop), (∀ (Xx : a), X Xx → Y Xx) → ∀ (Xx : a), And (X Xx) (Z Xx) → And (Y Xx) (Z Xx)) False
% 3.46/3.71  Clause #2 (by clausification #[1]): ∀ (a_1 : a → Prop),
% 3.46/3.71    Eq
% 3.46/3.71      (Not
% 3.46/3.71        (∀ (Y Z : a → Prop),
% 3.46/3.71          (∀ (Xx : a), skS.0 0 a_1 Xx → Y Xx) → ∀ (Xx : a), And (skS.0 0 a_1 Xx) (Z Xx) → And (Y Xx) (Z Xx)))
% 3.46/3.71      True
% 3.46/3.71  Clause #3 (by clausification #[2]): ∀ (a_1 : a → Prop),
% 3.46/3.71    Eq
% 3.46/3.71      (∀ (Y Z : a → Prop),
% 3.46/3.71        (∀ (Xx : a), skS.0 0 a_1 Xx → Y Xx) → ∀ (Xx : a), And (skS.0 0 a_1 Xx) (Z Xx) → And (Y Xx) (Z Xx))
% 3.46/3.71      False
% 3.46/3.71  Clause #4 (by clausification #[3]): ∀ (a_1 a_2 : a → Prop),
% 3.46/3.71    Eq
% 3.46/3.71      (Not
% 3.46/3.71        (∀ (Z : a → Prop),
% 3.46/3.71          (∀ (Xx : a), skS.0 0 a_1 Xx → skS.0 1 a_1 a_2 Xx) →
% 3.46/3.71            ∀ (Xx : a), And (skS.0 0 a_1 Xx) (Z Xx) → And (skS.0 1 a_1 a_2 Xx) (Z Xx)))
% 3.46/3.71      True
% 3.46/3.71  Clause #5 (by clausification #[4]): ∀ (a_1 a_2 : a → Prop),
% 3.46/3.71    Eq
% 3.46/3.71      (∀ (Z : a → Prop),
% 3.46/3.71        (∀ (Xx : a), skS.0 0 a_1 Xx → skS.0 1 a_1 a_2 Xx) →
% 3.46/3.71          ∀ (Xx : a), And (skS.0 0 a_1 Xx) (Z Xx) → And (skS.0 1 a_1 a_2 Xx) (Z Xx))
% 3.46/3.71      False
% 3.46/3.71  Clause #6 (by clausification #[5]): ∀ (a_1 a_2 a_3 : a → Prop),
% 3.46/3.71    Eq
% 3.46/3.71      (Not
% 3.46/3.71        ((∀ (Xx : a), skS.0 0 a_1 Xx → skS.0 1 a_1 a_2 Xx) →
% 3.46/3.71          ∀ (Xx : a), And (skS.0 0 a_1 Xx) (skS.0 2 a_1 a_2 a_3 Xx) → And (skS.0 1 a_1 a_2 Xx) (skS.0 2 a_1 a_2 a_3 Xx)))
% 3.46/3.71      True
% 3.46/3.71  Clause #7 (by clausification #[6]): ∀ (a_1 a_2 a_3 : a → Prop),
% 3.46/3.71    Eq
% 3.46/3.71      ((∀ (Xx : a), skS.0 0 a_1 Xx → skS.0 1 a_1 a_2 Xx) →
% 3.46/3.71        ∀ (Xx : a), And (skS.0 0 a_1 Xx) (skS.0 2 a_1 a_2 a_3 Xx) → And (skS.0 1 a_1 a_2 Xx) (skS.0 2 a_1 a_2 a_3 Xx))
% 3.46/3.71      False
% 3.46/3.71  Clause #8 (by clausification #[7]): ∀ (a_1 a_2 : a → Prop), Eq (∀ (Xx : a), skS.0 0 a_1 Xx → skS.0 1 a_1 a_2 Xx) True
% 3.46/3.71  Clause #9 (by clausification #[7]): ∀ (a_1 a_2 a_3 : a → Prop),
% 3.46/3.71    Eq (∀ (Xx : a), And (skS.0 0 a_1 Xx) (skS.0 2 a_1 a_2 a_3 Xx) → And (skS.0 1 a_1 a_2 Xx) (skS.0 2 a_1 a_2 a_3 Xx))
% 3.46/3.71      False
% 3.46/3.71  Clause #10 (by clausification #[8]): ∀ (a_1 : a → Prop) (a_2 : a) (a_3 : a → Prop), Eq (skS.0 0 a_1 a_2 → skS.0 1 a_1 a_3 a_2) True
% 3.46/3.71  Clause #11 (by clausification #[10]): ∀ (a_1 : a → Prop) (a_2 : a) (a_3 : a → Prop), Or (Eq (skS.0 0 a_1 a_2) False) (Eq (skS.0 1 a_1 a_3 a_2) True)
% 3.46/3.71  Clause #12 (by clausification #[9]): ∀ (a_1 a_2 a_3 : a → Prop) (a_4 : a),
% 3.46/3.71    Eq
% 3.46/3.71      (Not
% 3.46/3.71        (And (skS.0 0 a_1 (skS.0 3 a_1 a_2 a_3 a_4)) (skS.0 2 a_1 a_2 a_3 (skS.0 3 a_1 a_2 a_3 a_4)) →
% 3.46/3.71          And (skS.0 1 a_1 a_2 (skS.0 3 a_1 a_2 a_3 a_4)) (skS.0 2 a_1 a_2 a_3 (skS.0 3 a_1 a_2 a_3 a_4))))
% 3.46/3.71      True
% 3.46/3.71  Clause #13 (by clausification #[12]): ∀ (a_1 a_2 a_3 : a → Prop) (a_4 : a),
% 3.46/3.71    Eq
% 3.46/3.71      (And (skS.0 0 a_1 (skS.0 3 a_1 a_2 a_3 a_4)) (skS.0 2 a_1 a_2 a_3 (skS.0 3 a_1 a_2 a_3 a_4)) →
% 3.46/3.71        And (skS.0 1 a_1 a_2 (skS.0 3 a_1 a_2 a_3 a_4)) (skS.0 2 a_1 a_2 a_3 (skS.0 3 a_1 a_2 a_3 a_4)))
% 3.46/3.71      False
% 3.46/3.71  Clause #14 (by clausification #[13]): ∀ (a_1 a_2 a_3 : a → Prop) (a_4 : a),
% 3.46/3.71    Eq (And (skS.0 0 a_1 (skS.0 3 a_1 a_2 a_3 a_4)) (skS.0 2 a_1 a_2 a_3 (skS.0 3 a_1 a_2 a_3 a_4))) True
% 3.46/3.71  Clause #15 (by clausification #[13]): ∀ (a_1 a_2 a_3 : a → Prop) (a_4 : a),
% 3.46/3.71    Eq (And (skS.0 1 a_1 a_2 (skS.0 3 a_1 a_2 a_3 a_4)) (skS.0 2 a_1 a_2 a_3 (skS.0 3 a_1 a_2 a_3 a_4))) False
% 3.46/3.71  Clause #16 (by clausification #[14]): ∀ (a_1 a_2 a_3 : a → Prop) (a_4 : a), Eq (skS.0 2 a_1 a_2 a_3 (skS.0 3 a_1 a_2 a_3 a_4)) True
% 3.46/3.71  Clause #17 (by clausification #[14]): ∀ (a_1 a_2 a_3 : a → Prop) (a_4 : a), Eq (skS.0 0 a_1 (skS.0 3 a_1 a_2 a_3 a_4)) True
% 3.46/3.71  Clause #18 (by superposition #[17, 11]): ∀ (a_1 a_2 a_3 a_4 : a → Prop) (a_5 : a), Or (Eq True False) (Eq (skS.0 1 a_1 a_2 (skS.0 3 a_1 a_3 a_4 a_5)) True)
% 3.46/3.71  Clause #19 (by clausification #[18]): ∀ (a_1 a_2 a_3 a_4 : a → Prop) (a_5 : a), Eq (skS.0 1 a_1 a_2 (skS.0 3 a_1 a_3 a_4 a_5)) True
% 3.46/3.71  Clause #20 (by clausification #[15]): ∀ (a_1 a_2 a_3 : a → Prop) (a_4 : a),
% 3.46/3.71    Or (Eq (skS.0 1 a_1 a_2 (skS.0 3 a_1 a_2 a_3 a_4)) False) (Eq (skS.0 2 a_1 a_2 a_3 (skS.0 3 a_1 a_2 a_3 a_4)) False)
% 3.46/3.71  Clause #21 (by forward demodulation #[20, 19]): ∀ (a_1 a_2 a_3 : a → Prop) (a_4 : a), Or (Eq True False) (Eq (skS.0 2 a_1 a_2 a_3 (skS.0 3 a_1 a_2 a_3 a_4)) False)
% 3.46/3.71  Clause #22 (by clausification #[21]): ∀ (a_1 a_2 a_3 : a → Prop) (a_4 : a), Eq (skS.0 2 a_1 a_2 a_3 (skS.0 3 a_1 a_2 a_3 a_4)) False
% 3.46/3.71  Clause #23 (by superposition #[22, 16]): Eq False True
% 3.46/3.71  Clause #24 (by clausification #[23]): False
% 3.46/3.71  SZS output end Proof for theBenchmark.p
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