TSTP Solution File: SET583+3 by SnakeForV---1.0

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : SnakeForV---1.0
% Problem  : SET583+3 : TPTP v8.1.0. Released v2.2.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : vampire --input_syntax tptp --proof tptp --output_axiom_names on --mode portfolio --schedule snake_tptp_uns --cores 0 -t %d %s

% Computer : n022.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Wed Aug 31 18:21:30 EDT 2022

% Result   : Theorem 0.20s 0.48s
% Output   : Refutation 0.20s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :   10
%            Number of leaves      :    3
% Syntax   : Number of formulae    :   19 (   5 unt;   0 def)
%            Number of atoms       :   58 (  20 equ)
%            Maximal formula atoms :    6 (   3 avg)
%            Number of connectives :   60 (  21   ~;  12   |;  22   &)
%                                         (   1 <=>;   4  =>;   0  <=;   0 <~>)
%            Maximal formula depth :    7 (   5 avg)
%            Maximal term depth    :    1 (   1 avg)
%            Number of predicates  :    3 (   1 usr;   1 prp; 0-2 aty)
%            Number of functors    :    2 (   2 usr;   2 con; 0-0 aty)
%            Number of variables   :   24 (  16   !;   8   ?)

% Comments : 
%------------------------------------------------------------------------------
fof(f37,plain,
    $false,
    inference(subsumption_resolution,[],[f36,f29]) ).

fof(f29,plain,
    sK1 != sK2,
    inference(cnf_transformation,[],[f20]) ).

fof(f20,plain,
    ( subset(sK2,sK1)
    & sK1 != sK2
    & subset(sK1,sK2) ),
    inference(skolemisation,[status(esa),new_symbols(skolem,[sK1,sK2])],[f18,f19]) ).

fof(f19,plain,
    ( ? [X0,X1] :
        ( subset(X1,X0)
        & X0 != X1
        & subset(X0,X1) )
   => ( subset(sK2,sK1)
      & sK1 != sK2
      & subset(sK1,sK2) ) ),
    introduced(choice_axiom,[]) ).

fof(f18,plain,
    ? [X0,X1] :
      ( subset(X1,X0)
      & X0 != X1
      & subset(X0,X1) ),
    inference(rectify,[],[f10]) ).

fof(f10,plain,
    ? [X1,X0] :
      ( subset(X0,X1)
      & X0 != X1
      & subset(X1,X0) ),
    inference(flattening,[],[f9]) ).

fof(f9,plain,
    ? [X1,X0] :
      ( X0 != X1
      & subset(X1,X0)
      & subset(X0,X1) ),
    inference(ennf_transformation,[],[f6]) ).

fof(f6,plain,
    ~ ! [X1,X0] :
        ( ( subset(X1,X0)
          & subset(X0,X1) )
       => X0 = X1 ),
    inference(rectify,[],[f5]) ).

fof(f5,negated_conjecture,
    ~ ! [X1,X0] :
        ( ( subset(X1,X0)
          & subset(X0,X1) )
       => X0 = X1 ),
    inference(negated_conjecture,[],[f4]) ).

fof(f4,conjecture,
    ! [X1,X0] :
      ( ( subset(X1,X0)
        & subset(X0,X1) )
     => X0 = X1 ),
    file('/export/starexec/sandbox/benchmark/theBenchmark.p',prove_extensionality) ).

fof(f36,plain,
    sK1 = sK2,
    inference(subsumption_resolution,[],[f33,f30]) ).

fof(f30,plain,
    subset(sK2,sK1),
    inference(cnf_transformation,[],[f20]) ).

fof(f33,plain,
    ( ~ subset(sK2,sK1)
    | sK1 = sK2 ),
    inference(resolution,[],[f28,f23]) ).

fof(f23,plain,
    ! [X0,X1] :
      ( ~ subset(X1,X0)
      | X0 = X1
      | ~ subset(X0,X1) ),
    inference(cnf_transformation,[],[f13]) ).

fof(f13,plain,
    ! [X0,X1] :
      ( ( X0 = X1
        | ~ subset(X1,X0)
        | ~ subset(X0,X1) )
      & ( ( subset(X1,X0)
          & subset(X0,X1) )
        | X0 != X1 ) ),
    inference(rectify,[],[f12]) ).

fof(f12,plain,
    ! [X1,X0] :
      ( ( X0 = X1
        | ~ subset(X0,X1)
        | ~ subset(X1,X0) )
      & ( ( subset(X0,X1)
          & subset(X1,X0) )
        | X0 != X1 ) ),
    inference(flattening,[],[f11]) ).

fof(f11,plain,
    ! [X1,X0] :
      ( ( X0 = X1
        | ~ subset(X0,X1)
        | ~ subset(X1,X0) )
      & ( ( subset(X0,X1)
          & subset(X1,X0) )
        | X0 != X1 ) ),
    inference(nnf_transformation,[],[f1]) ).

fof(f1,axiom,
    ! [X1,X0] :
      ( X0 = X1
    <=> ( subset(X0,X1)
        & subset(X1,X0) ) ),
    file('/export/starexec/sandbox/benchmark/theBenchmark.p',equal_defn) ).

fof(f28,plain,
    subset(sK1,sK2),
    inference(cnf_transformation,[],[f20]) ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.12  % Problem    : SET583+3 : TPTP v8.1.0. Released v2.2.0.
% 0.07/0.13  % Command    : vampire --input_syntax tptp --proof tptp --output_axiom_names on --mode portfolio --schedule snake_tptp_uns --cores 0 -t %d %s
% 0.14/0.34  % Computer : n022.cluster.edu
% 0.14/0.34  % Model    : x86_64 x86_64
% 0.14/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.34  % Memory   : 8042.1875MB
% 0.14/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.14/0.34  % CPULimit   : 300
% 0.14/0.34  % WCLimit    : 300
% 0.14/0.34  % DateTime   : Tue Aug 30 14:03:56 EDT 2022
% 0.14/0.34  % CPUTime    : 
% 0.20/0.47  % (13405)dis+1002_1:12_drc=off:fd=preordered:tgt=full:i=99978:si=on:rawr=on:rtra=on_0 on theBenchmark for (2999ds/99978Mi)
% 0.20/0.47  % (13412)lrs+2_1:1_lcm=reverse:lma=on:sos=all:spb=goal_then_units:ss=included:urr=on:i=39:si=on:rawr=on:rtra=on_0 on theBenchmark for (2999ds/39Mi)
% 0.20/0.48  % (13412)First to succeed.
% 0.20/0.48  % (13412)Refutation found. Thanks to Tanya!
% 0.20/0.48  % SZS status Theorem for theBenchmark
% 0.20/0.48  % SZS output start Proof for theBenchmark
% See solution above
% 0.20/0.48  % (13412)------------------------------
% 0.20/0.48  % (13412)Version: Vampire 4.7 (commit 807e37dd9 on 2022-08-23 09:55:27 +0200)
% 0.20/0.48  % (13412)Linked with Z3 4.8.13.0 f03d756e086f81f2596157241e0decfb1c982299 z3-4.8.4-5390-gf03d756e0
% 0.20/0.48  % (13412)Termination reason: Refutation
% 0.20/0.48  
% 0.20/0.48  % (13412)Memory used [KB]: 5884
% 0.20/0.48  % (13412)Time elapsed: 0.091 s
% 0.20/0.48  % (13412)Instructions burned: 1 (million)
% 0.20/0.48  % (13412)------------------------------
% 0.20/0.48  % (13412)------------------------------
% 0.20/0.48  % (13404)Success in time 0.128 s
%------------------------------------------------------------------------------