%------------------------------------------------------------------------------
% File     : Metis---2.4
% Problem  : SET583+3 : TPTP v8.1.0. Released v2.2.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : metis --show proof --show saturation %s

% Computer : n025.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Tue Jul 19 03:35:37 EDT 2022

% Result   : Theorem 0.12s 0.34s
% Output   : CNFRefutation 0.12s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    5
%            Number of leaves      :    2
% Syntax   : Number of formulae    :    9 (   2 unt;   0 def)
%            Number of atoms       :   23 (   7 equ)
%            Maximal formula atoms :    3 (   2 avg)
%            Number of connectives :   22 (   8   ~;   2   |;   6   &)
%                                         (   3 <=>;   3  =>;   0  <=;   0 <~>)
%            Maximal formula depth :    6 (   4 avg)
%            Maximal term depth    :    1 (   1 avg)
%            Number of predicates  :    3 (   1 usr;   1 prp; 0-2 aty)
%            Number of functors    :    0 (   0 usr;   0 con; --- aty)
%            Number of variables   :   14 (   0 sgn  12   !;   2   ?)

% Comments : 
%------------------------------------------------------------------------------
fof(equal_defn,axiom,
    ! [B,C] :
      ( B = C
    <=> ( subset(B,C)
        & subset(C,B) ) ) ).

fof(prove_extensionality,conjecture,
    ! [B,C] :
      ( ( subset(B,C)
        & subset(C,B) )
     => B = C ) ).

fof(subgoal_0,plain,
    ! [B,C] :
      ( ( subset(B,C)
        & subset(C,B) )
     => B = C ),
    inference(strip,[],[prove_extensionality]) ).

fof(negate_0_0,plain,
    ~ ! [B,C] :
        ( ( subset(B,C)
          & subset(C,B) )
       => B = C ),
    inference(negate,[],[subgoal_0]) ).

fof(normalize_0_0,plain,
    ? [B,C] :
      ( B != C
      & subset(B,C)
      & subset(C,B) ),
    inference(canonicalize,[],[negate_0_0]) ).

fof(normalize_0_1,plain,
    ! [B,C] :
      ( B != C
    <=> ( ~ subset(B,C)
        | ~ subset(C,B) ) ),
    inference(canonicalize,[],[equal_defn]) ).

fof(normalize_0_2,plain,
    ! [B,C] :
      ( B != C
    <=> ( ~ subset(B,C)
        | ~ subset(C,B) ) ),
    inference(specialize,[],[normalize_0_1]) ).

fof(normalize_0_3,plain,
    $false,
    inference(simplify,[],[normalize_0_0,normalize_0_2]) ).

cnf(refute_0_0,plain,
    $false,
    inference(canonicalize,[],[normalize_0_3]) ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.06/0.12  % Problem  : SET583+3 : TPTP v8.1.0. Released v2.2.0.
% 0.06/0.12  % Command  : metis --show proof --show saturation %s
% 0.12/0.33  % Computer : n025.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit : 300
% 0.12/0.33  % WCLimit  : 600
% 0.12/0.33  % DateTime : Sat Jul  9 16:43:00 EDT 2022
% 0.12/0.33  % CPUTime  : 
% 0.12/0.34  %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
% 0.12/0.34  % SZS status Theorem for /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.12/0.34  
% 0.12/0.34  % SZS output start CNFRefutation for /export/starexec/sandbox/benchmark/theBenchmark.p
% See solution above
% 0.12/0.34  
%------------------------------------------------------------------------------