TSTP Solution File: SET583+3 by Duper---1.0

View Problem - Process Solution

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% File     : Duper---1.0
% Problem  : SET583+3 : TPTP v8.1.2. Released v2.2.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n027.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 14:46:53 EDT 2023

% Result   : Theorem 3.68s 3.85s
% Output   : Proof 3.68s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.13  % Problem    : SET583+3 : TPTP v8.1.2. Released v2.2.0.
% 0.00/0.14  % Command    : duper %s
% 0.15/0.36  % Computer : n027.cluster.edu
% 0.15/0.36  % Model    : x86_64 x86_64
% 0.15/0.36  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.15/0.36  % Memory   : 8042.1875MB
% 0.15/0.36  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.15/0.36  % CPULimit   : 300
% 0.15/0.36  % WCLimit    : 300
% 0.15/0.36  % DateTime   : Sat Aug 26 08:44:19 EDT 2023
% 0.15/0.36  % CPUTime    : 
% 3.68/3.85  SZS status Theorem for theBenchmark.p
% 3.68/3.85  SZS output start Proof for theBenchmark.p
% 3.68/3.85  Clause #0 (by assumption #[]): Eq (∀ (B C : Iota), Iff (Eq B C) (And (subset B C) (subset C B))) True
% 3.68/3.85  Clause #3 (by assumption #[]): Eq (Not (∀ (B C : Iota), And (subset B C) (subset C B) → Eq B C)) True
% 3.68/3.85  Clause #5 (by clausification #[3]): Eq (∀ (B C : Iota), And (subset B C) (subset C B) → Eq B C) False
% 3.68/3.85  Clause #6 (by clausification #[5]): ∀ (a : Iota), Eq (Not (∀ (C : Iota), And (subset (skS.0 0 a) C) (subset C (skS.0 0 a)) → Eq (skS.0 0 a) C)) True
% 3.68/3.85  Clause #7 (by clausification #[6]): ∀ (a : Iota), Eq (∀ (C : Iota), And (subset (skS.0 0 a) C) (subset C (skS.0 0 a)) → Eq (skS.0 0 a) C) False
% 3.68/3.85  Clause #8 (by clausification #[7]): ∀ (a a_1 : Iota),
% 3.68/3.85    Eq
% 3.68/3.85      (Not
% 3.68/3.85        (And (subset (skS.0 0 a) (skS.0 1 a a_1)) (subset (skS.0 1 a a_1) (skS.0 0 a)) → Eq (skS.0 0 a) (skS.0 1 a a_1)))
% 3.68/3.85      True
% 3.68/3.85  Clause #9 (by clausification #[8]): ∀ (a a_1 : Iota),
% 3.68/3.85    Eq (And (subset (skS.0 0 a) (skS.0 1 a a_1)) (subset (skS.0 1 a a_1) (skS.0 0 a)) → Eq (skS.0 0 a) (skS.0 1 a a_1))
% 3.68/3.85      False
% 3.68/3.85  Clause #10 (by clausification #[9]): ∀ (a a_1 : Iota), Eq (And (subset (skS.0 0 a) (skS.0 1 a a_1)) (subset (skS.0 1 a a_1) (skS.0 0 a))) True
% 3.68/3.85  Clause #11 (by clausification #[9]): ∀ (a a_1 : Iota), Eq (Eq (skS.0 0 a) (skS.0 1 a a_1)) False
% 3.68/3.85  Clause #12 (by clausification #[10]): ∀ (a a_1 : Iota), Eq (subset (skS.0 1 a a_1) (skS.0 0 a)) True
% 3.68/3.85  Clause #13 (by clausification #[10]): ∀ (a a_1 : Iota), Eq (subset (skS.0 0 a) (skS.0 1 a a_1)) True
% 3.68/3.85  Clause #27 (by clausification #[0]): ∀ (a : Iota), Eq (∀ (C : Iota), Iff (Eq a C) (And (subset a C) (subset C a))) True
% 3.68/3.85  Clause #28 (by clausification #[27]): ∀ (a a_1 : Iota), Eq (Iff (Eq a a_1) (And (subset a a_1) (subset a_1 a))) True
% 3.68/3.85  Clause #29 (by clausification #[28]): ∀ (a a_1 : Iota), Or (Eq (Eq a a_1) True) (Eq (And (subset a a_1) (subset a_1 a)) False)
% 3.68/3.85  Clause #31 (by clausification #[29]): ∀ (a a_1 : Iota), Or (Eq (And (subset a a_1) (subset a_1 a)) False) (Eq a a_1)
% 3.68/3.85  Clause #32 (by clausification #[31]): ∀ (a a_1 : Iota), Or (Eq a a_1) (Or (Eq (subset a a_1) False) (Eq (subset a_1 a) False))
% 3.68/3.85  Clause #33 (by superposition #[32, 12]): ∀ (a a_1 : Iota),
% 3.68/3.85    Or (Eq (skS.0 1 a a_1) (skS.0 0 a)) (Or (Eq (subset (skS.0 0 a) (skS.0 1 a a_1)) False) (Eq False True))
% 3.68/3.85  Clause #41 (by clausification #[11]): ∀ (a a_1 : Iota), Ne (skS.0 0 a) (skS.0 1 a a_1)
% 3.68/3.85  Clause #48 (by clausification #[33]): ∀ (a a_1 : Iota), Or (Eq (skS.0 1 a a_1) (skS.0 0 a)) (Eq (subset (skS.0 0 a) (skS.0 1 a a_1)) False)
% 3.68/3.85  Clause #49 (by forward contextual literal cutting #[48, 41]): ∀ (a a_1 : Iota), Eq (subset (skS.0 0 a) (skS.0 1 a a_1)) False
% 3.68/3.85  Clause #50 (by superposition #[49, 13]): Eq False True
% 3.68/3.85  Clause #51 (by clausification #[50]): False
% 3.68/3.85  SZS output end Proof for theBenchmark.p
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