TSTP Solution File: SET183+3 by Otter---3.3

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Otter---3.3
% Problem  : SET183+3 : TPTP v8.1.0. Released v2.2.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : otter-tptp-script %s

% Computer : n027.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Wed Jul 27 13:13:14 EDT 2022

% Result   : Theorem 1.82s 2.03s
% Output   : Refutation 1.82s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    7
%            Number of leaves      :    9
% Syntax   : Number of clauses     :   16 (  10 unt;   2 nHn;  12 RR)
%            Number of literals    :   25 (   5 equ;   8 neg)
%            Maximal clause size   :    3 (   1 avg)
%            Maximal term depth    :    3 (   1 avg)
%            Number of predicates  :    4 (   2 usr;   1 prp; 0-2 aty)
%            Number of functors    :    4 (   4 usr;   2 con; 0-2 aty)
%            Number of variables   :   17 (   1 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(3,axiom,
    ( member(A,intersection(B,C))
    | ~ member(A,B)
    | ~ member(A,C) ),
    file('SET183+3.p',unknown),
    [] ).

cnf(4,axiom,
    ( ~ subset(A,B)
    | ~ member(C,A)
    | member(C,B) ),
    file('SET183+3.p',unknown),
    [] ).

cnf(5,axiom,
    ( subset(A,B)
    | ~ member(dollar_f1(A,B),B) ),
    file('SET183+3.p',unknown),
    [] ).

cnf(8,axiom,
    ( A = B
    | ~ subset(A,B)
    | ~ subset(B,A) ),
    file('SET183+3.p',unknown),
    [] ).

cnf(12,axiom,
    intersection(dollar_c2,dollar_c1) != dollar_c2,
    file('SET183+3.p',unknown),
    [] ).

cnf(16,axiom,
    A = A,
    file('SET183+3.p',unknown),
    [] ).

cnf(17,axiom,
    subset(intersection(A,B),A),
    file('SET183+3.p',unknown),
    [] ).

cnf(18,axiom,
    ( subset(A,B)
    | member(dollar_f1(A,B),A) ),
    file('SET183+3.p',unknown),
    [] ).

cnf(22,axiom,
    subset(dollar_c2,dollar_c1),
    file('SET183+3.p',unknown),
    [] ).

cnf(36,plain,
    ( member(dollar_f1(A,intersection(A,B)),A)
    | intersection(A,B) = A ),
    inference(hyper,[status(thm)],[18,8,17]),
    [iquote('hyper,18,8,17')] ).

cnf(512,plain,
    member(dollar_f1(dollar_c2,intersection(dollar_c2,dollar_c1)),dollar_c2),
    inference(unit_del,[status(thm)],[inference(para_from,[status(thm),theory(equality)],[36,12]),16]),
    [iquote('para_from,36.2.1,12.1.1,unit_del,16')] ).

cnf(518,plain,
    member(dollar_f1(dollar_c2,intersection(dollar_c2,dollar_c1)),dollar_c1),
    inference(hyper,[status(thm)],[512,4,22]),
    [iquote('hyper,512,4,22')] ).

cnf(565,plain,
    member(dollar_f1(dollar_c2,intersection(dollar_c2,dollar_c1)),intersection(dollar_c2,dollar_c1)),
    inference(hyper,[status(thm)],[518,3,512]),
    [iquote('hyper,518,3,512')] ).

cnf(935,plain,
    subset(dollar_c2,intersection(dollar_c2,dollar_c1)),
    inference(hyper,[status(thm)],[565,5]),
    [iquote('hyper,565,5')] ).

cnf(990,plain,
    intersection(dollar_c2,dollar_c1) = dollar_c2,
    inference(hyper,[status(thm)],[935,8,17]),
    [iquote('hyper,935,8,17')] ).

cnf(992,plain,
    $false,
    inference(binary,[status(thm)],[990,12]),
    [iquote('binary,990.1,12.1')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.06/0.11  % Problem  : SET183+3 : TPTP v8.1.0. Released v2.2.0.
% 0.06/0.12  % Command  : otter-tptp-script %s
% 0.12/0.33  % Computer : n027.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit : 300
% 0.12/0.33  % WCLimit  : 300
% 0.12/0.33  % DateTime : Wed Jul 27 11:01:06 EDT 2022
% 0.12/0.33  % CPUTime  : 
% 1.82/2.02  ----- Otter 3.3f, August 2004 -----
% 1.82/2.02  The process was started by sandbox2 on n027.cluster.edu,
% 1.82/2.02  Wed Jul 27 11:01:07 2022
% 1.82/2.02  The command was "./otter".  The process ID is 8867.
% 1.82/2.02  
% 1.82/2.02  set(prolog_style_variables).
% 1.82/2.02  set(auto).
% 1.82/2.02     dependent: set(auto1).
% 1.82/2.02     dependent: set(process_input).
% 1.82/2.02     dependent: clear(print_kept).
% 1.82/2.02     dependent: clear(print_new_demod).
% 1.82/2.02     dependent: clear(print_back_demod).
% 1.82/2.02     dependent: clear(print_back_sub).
% 1.82/2.02     dependent: set(control_memory).
% 1.82/2.02     dependent: assign(max_mem, 12000).
% 1.82/2.02     dependent: assign(pick_given_ratio, 4).
% 1.82/2.02     dependent: assign(stats_level, 1).
% 1.82/2.02     dependent: assign(max_seconds, 10800).
% 1.82/2.02  clear(print_given).
% 1.82/2.02  
% 1.82/2.02  formula_list(usable).
% 1.82/2.02  all A (A=A).
% 1.82/2.02  all B C D (member(D,intersection(B,C))<->member(D,B)&member(D,C)).
% 1.82/2.02  all B C subset(intersection(B,C),B).
% 1.82/2.02  all B C (subset(B,C)<-> (all D (member(D,B)->member(D,C)))).
% 1.82/2.02  all B C (B=C<->subset(B,C)&subset(C,B)).
% 1.82/2.02  all B C (intersection(B,C)=intersection(C,B)).
% 1.82/2.02  all B subset(B,B).
% 1.82/2.02  all B C (B=C<-> (all D (member(D,B)<->member(D,C)))).
% 1.82/2.02  -(all B C (subset(B,C)->intersection(B,C)=B)).
% 1.82/2.03  end_of_list.
% 1.82/2.03  
% 1.82/2.03  -------> usable clausifies to:
% 1.82/2.03  
% 1.82/2.03  list(usable).
% 1.82/2.03  0 [] A=A.
% 1.82/2.03  0 [] -member(D,intersection(B,C))|member(D,B).
% 1.82/2.03  0 [] -member(D,intersection(B,C))|member(D,C).
% 1.82/2.03  0 [] member(D,intersection(B,C))| -member(D,B)| -member(D,C).
% 1.82/2.03  0 [] subset(intersection(B,C),B).
% 1.82/2.03  0 [] -subset(B,C)| -member(D,B)|member(D,C).
% 1.82/2.03  0 [] subset(B,C)|member($f1(B,C),B).
% 1.82/2.03  0 [] subset(B,C)| -member($f1(B,C),C).
% 1.82/2.03  0 [] B!=C|subset(B,C).
% 1.82/2.03  0 [] B!=C|subset(C,B).
% 1.82/2.03  0 [] B=C| -subset(B,C)| -subset(C,B).
% 1.82/2.03  0 [] intersection(B,C)=intersection(C,B).
% 1.82/2.03  0 [] subset(B,B).
% 1.82/2.03  0 [] B!=C| -member(D,B)|member(D,C).
% 1.82/2.03  0 [] B!=C|member(D,B)| -member(D,C).
% 1.82/2.03  0 [] B=C|member($f2(B,C),B)|member($f2(B,C),C).
% 1.82/2.03  0 [] B=C| -member($f2(B,C),B)| -member($f2(B,C),C).
% 1.82/2.03  0 [] subset($c2,$c1).
% 1.82/2.03  0 [] intersection($c2,$c1)!=$c2.
% 1.82/2.03  end_of_list.
% 1.82/2.03  
% 1.82/2.03  SCAN INPUT: prop=0, horn=0, equality=1, symmetry=0, max_lits=3.
% 1.82/2.03  
% 1.82/2.03  This ia a non-Horn set with equality.  The strategy will be
% 1.82/2.03  Knuth-Bendix, ordered hyper_res, factoring, and unit
% 1.82/2.03  deletion, with positive clauses in sos and nonpositive
% 1.82/2.03  clauses in usable.
% 1.82/2.03  
% 1.82/2.03     dependent: set(knuth_bendix).
% 1.82/2.03     dependent: set(anl_eq).
% 1.82/2.03     dependent: set(para_from).
% 1.82/2.03     dependent: set(para_into).
% 1.82/2.03     dependent: clear(para_from_right).
% 1.82/2.03     dependent: clear(para_into_right).
% 1.82/2.03     dependent: set(para_from_vars).
% 1.82/2.03     dependent: set(eq_units_both_ways).
% 1.82/2.03     dependent: set(dynamic_demod_all).
% 1.82/2.03     dependent: set(dynamic_demod).
% 1.82/2.03     dependent: set(order_eq).
% 1.82/2.03     dependent: set(back_demod).
% 1.82/2.03     dependent: set(lrpo).
% 1.82/2.03     dependent: set(hyper_res).
% 1.82/2.03     dependent: set(unit_deletion).
% 1.82/2.03     dependent: set(factor).
% 1.82/2.03  
% 1.82/2.03  ------------> process usable:
% 1.82/2.03  ** KEPT (pick-wt=8): 1 [] -member(A,intersection(B,C))|member(A,B).
% 1.82/2.03  ** KEPT (pick-wt=8): 2 [] -member(A,intersection(B,C))|member(A,C).
% 1.82/2.03  ** KEPT (pick-wt=11): 3 [] member(A,intersection(B,C))| -member(A,B)| -member(A,C).
% 1.82/2.03  ** KEPT (pick-wt=9): 4 [] -subset(A,B)| -member(C,A)|member(C,B).
% 1.82/2.03  ** KEPT (pick-wt=8): 5 [] subset(A,B)| -member($f1(A,B),B).
% 1.82/2.03  ** KEPT (pick-wt=6): 6 [] A!=B|subset(A,B).
% 1.82/2.03  ** KEPT (pick-wt=6): 7 [] A!=B|subset(B,A).
% 1.82/2.03  ** KEPT (pick-wt=9): 8 [] A=B| -subset(A,B)| -subset(B,A).
% 1.82/2.03  ** KEPT (pick-wt=9): 9 [] A!=B| -member(C,A)|member(C,B).
% 1.82/2.03  ** KEPT (pick-wt=9): 10 [] A!=B|member(C,A)| -member(C,B).
% 1.82/2.03  ** KEPT (pick-wt=13): 11 [] A=B| -member($f2(A,B),A)| -member($f2(A,B),B).
% 1.82/2.03  ** KEPT (pick-wt=5): 12 [] intersection($c2,$c1)!=$c2.
% 1.82/2.03  
% 1.82/2.03  ------------> process sos:
% 1.82/2.03  ** KEPT (pick-wt=3): 16 [] A=A.
% 1.82/2.03  ** KEPT (pick-wt=5): 17 [] subset(intersection(A,B),A).
% 1.82/2.03  ** KEPT (pick-wt=8): 18 [] subset(A,B)|member($f1(A,B),A).
% 1.82/2.03  ** KEPT (pick-wt=7): 19 [] intersection(A,B)=intersection(B,A).
% 1.82/2.03  ** KEPT (pick-wt=3): 20 [] subset(A,A).
% 1.82/2.03  ** KEPT (pick-wt=13): 21 [] A=B|member($f2(A,B),A)|member($f2(A,B),B).
% 1.82/2.03  ** KEPT (pick-wt=3): 22 [] subset($c2,$c1).
% 1.82/2.03    Following clause subsumed by 16 during input processing: 0 [copy,16,flip.1] A=A.
% 1.82/2.03  16 back subsumes 15.
% 1.82/2.03  16 back subsumes 14.
% 1.82/2.03    Following clause subsumed by 19 during input processing: 0 [copy,19,flip.1] intersection(A,B)=intersection(B,A).
% 1.82/2.03  
% 1.82/2.03  ======= end of input processing =======
% 1.82/2.03  
% 1.82/2.03  =========== start of search ===========
% 1.82/2.03  
% 1.82/2.03  -------- PROOF -------- 
% 1.82/2.03  
% 1.82/2.03  ----> UNIT CONFLICT at   0.12 sec ----> 992 [binary,990.1,12.1] $F.
% 1.82/2.03  
% 1.82/2.03  Length of proof is 6.  Level of proof is 6.
% 1.82/2.03  
% 1.82/2.03  ---------------- PROOF ----------------
% 1.82/2.03  % SZS status Theorem
% 1.82/2.03  % SZS output start Refutation
% See solution above
% 1.82/2.03  ------------ end of proof -------------
% 1.82/2.03  
% 1.82/2.03  
% 1.82/2.03  Search stopped by max_proofs option.
% 1.82/2.03  
% 1.82/2.03  
% 1.82/2.03  Search stopped by max_proofs option.
% 1.82/2.03  
% 1.82/2.03  ============ end of search ============
% 1.82/2.03  
% 1.82/2.03  -------------- statistics -------------
% 1.82/2.03  clauses given                 39
% 1.82/2.03  clauses generated           2343
% 1.82/2.03  clauses kept                 990
% 1.82/2.03  clauses forward subsumed    1340
% 1.82/2.03  clauses back subsumed          6
% 1.82/2.03  Kbytes malloced             1953
% 1.82/2.03  
% 1.82/2.03  ----------- times (seconds) -----------
% 1.82/2.03  user CPU time          0.12          (0 hr, 0 min, 0 sec)
% 1.82/2.03  system CPU time        0.00          (0 hr, 0 min, 0 sec)
% 1.82/2.03  wall-clock time        1             (0 hr, 0 min, 1 sec)
% 1.82/2.03  
% 1.82/2.03  That finishes the proof of the theorem.
% 1.82/2.03  
% 1.82/2.03  Process 8867 finished Wed Jul 27 11:01:08 2022
% 1.82/2.03  Otter interrupted
% 1.82/2.03  PROOF FOUND
%------------------------------------------------------------------------------