TSTP Solution File: SET148+3 by Duper---1.0
View Problem
- Process Solution
%------------------------------------------------------------------------------
% File : Duper---1.0
% Problem : SET148+3 : TPTP v8.1.2. Released v2.2.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n026.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Thu Aug 31 14:45:50 EDT 2023
% Result : Theorem 3.50s 3.68s
% Output : Proof 3.50s
% Verified :
% SZS Type : -
% Comments :
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.14 % Problem : SET148+3 : TPTP v8.1.2. Released v2.2.0.
% 0.00/0.15 % Command : duper %s
% 0.15/0.37 % Computer : n026.cluster.edu
% 0.15/0.37 % Model : x86_64 x86_64
% 0.15/0.37 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.15/0.37 % Memory : 8042.1875MB
% 0.15/0.37 % OS : Linux 3.10.0-693.el7.x86_64
% 0.15/0.37 % CPULimit : 300
% 0.15/0.37 % WCLimit : 300
% 0.15/0.37 % DateTime : Sat Aug 26 09:44:33 EDT 2023
% 0.15/0.37 % CPUTime :
% 3.50/3.68 SZS status Theorem for theBenchmark.p
% 3.50/3.68 SZS output start Proof for theBenchmark.p
% 3.50/3.68 Clause #0 (by assumption #[]): Eq (∀ (B C : Iota), subset B C → Eq (intersection B C) B) True
% 3.50/3.68 Clause #5 (by assumption #[]): Eq (∀ (B : Iota), subset B B) True
% 3.50/3.68 Clause #7 (by assumption #[]): Eq (Not (∀ (B : Iota), Eq (intersection B B) B)) True
% 3.50/3.68 Clause #8 (by clausification #[5]): ∀ (a : Iota), Eq (subset a a) True
% 3.50/3.68 Clause #9 (by clausification #[7]): Eq (∀ (B : Iota), Eq (intersection B B) B) False
% 3.50/3.68 Clause #10 (by clausification #[9]): ∀ (a : Iota), Eq (Not (Eq (intersection (skS.0 0 a) (skS.0 0 a)) (skS.0 0 a))) True
% 3.50/3.68 Clause #11 (by clausification #[10]): ∀ (a : Iota), Eq (Eq (intersection (skS.0 0 a) (skS.0 0 a)) (skS.0 0 a)) False
% 3.50/3.68 Clause #12 (by clausification #[11]): ∀ (a : Iota), Ne (intersection (skS.0 0 a) (skS.0 0 a)) (skS.0 0 a)
% 3.50/3.68 Clause #13 (by clausification #[0]): ∀ (a : Iota), Eq (∀ (C : Iota), subset a C → Eq (intersection a C) a) True
% 3.50/3.68 Clause #14 (by clausification #[13]): ∀ (a a_1 : Iota), Eq (subset a a_1 → Eq (intersection a a_1) a) True
% 3.50/3.68 Clause #15 (by clausification #[14]): ∀ (a a_1 : Iota), Or (Eq (subset a a_1) False) (Eq (Eq (intersection a a_1) a) True)
% 3.50/3.68 Clause #16 (by clausification #[15]): ∀ (a a_1 : Iota), Or (Eq (subset a a_1) False) (Eq (intersection a a_1) a)
% 3.50/3.68 Clause #17 (by superposition #[16, 8]): ∀ (a : Iota), Or (Eq (intersection a a) a) (Eq False True)
% 3.50/3.68 Clause #18 (by clausification #[17]): ∀ (a : Iota), Eq (intersection a a) a
% 3.50/3.68 Clause #20 (by backward contextual literal cutting #[18, 12]): False
% 3.50/3.68 SZS output end Proof for theBenchmark.p
%------------------------------------------------------------------------------