TSTP Solution File: SET117+1 by Duper---1.0

View Problem - Process Solution

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% File     : Duper---1.0
% Problem  : SET117+1 : TPTP v8.1.2. Bugfixed v5.4.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n007.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 14:45:43 EDT 2023

% Result   : Theorem 3.93s 4.10s
% Output   : Proof 3.93s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.12/0.12  % Problem    : SET117+1 : TPTP v8.1.2. Bugfixed v5.4.0.
% 0.12/0.14  % Command    : duper %s
% 0.13/0.35  % Computer : n007.cluster.edu
% 0.13/0.35  % Model    : x86_64 x86_64
% 0.13/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.35  % Memory   : 8042.1875MB
% 0.13/0.35  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.35  % CPULimit   : 300
% 0.13/0.35  % WCLimit    : 300
% 0.13/0.35  % DateTime   : Sat Aug 26 10:40:26 EDT 2023
% 0.13/0.35  % CPUTime    : 
% 3.93/4.10  SZS status Theorem for theBenchmark.p
% 3.93/4.10  SZS output start Proof for theBenchmark.p
% 3.93/4.10  Clause #4 (by assumption #[]): Eq (∀ (X Y : Iota), member (unordered_pair X Y) universal_class) True
% 3.93/4.10  Clause #6 (by assumption #[]): Eq (∀ (X Y : Iota), Eq (ordered_pair X Y) (unordered_pair (singleton X) (unordered_pair X (singleton Y)))) True
% 3.93/4.10  Clause #43 (by assumption #[]): Eq (Not (∀ (X : Iota), Eq (ordered_pair (first X) (second X)) X → member X universal_class)) True
% 3.93/4.10  Clause #63 (by clausification #[43]): Eq (∀ (X : Iota), Eq (ordered_pair (first X) (second X)) X → member X universal_class) False
% 3.93/4.10  Clause #64 (by clausification #[63]): ∀ (a : Iota),
% 3.93/4.10    Eq (Not (Eq (ordered_pair (first (skS.0 1 a)) (second (skS.0 1 a))) (skS.0 1 a) → member (skS.0 1 a) universal_class))
% 3.93/4.10      True
% 3.93/4.10  Clause #65 (by clausification #[64]): ∀ (a : Iota),
% 3.93/4.10    Eq (Eq (ordered_pair (first (skS.0 1 a)) (second (skS.0 1 a))) (skS.0 1 a) → member (skS.0 1 a) universal_class) False
% 3.93/4.10  Clause #66 (by clausification #[65]): ∀ (a : Iota), Eq (Eq (ordered_pair (first (skS.0 1 a)) (second (skS.0 1 a))) (skS.0 1 a)) True
% 3.93/4.10  Clause #67 (by clausification #[65]): ∀ (a : Iota), Eq (member (skS.0 1 a) universal_class) False
% 3.93/4.10  Clause #68 (by clausification #[66]): ∀ (a : Iota), Eq (ordered_pair (first (skS.0 1 a)) (second (skS.0 1 a))) (skS.0 1 a)
% 3.93/4.10  Clause #69 (by clausification #[4]): ∀ (a : Iota), Eq (∀ (Y : Iota), member (unordered_pair a Y) universal_class) True
% 3.93/4.10  Clause #70 (by clausification #[69]): ∀ (a a_1 : Iota), Eq (member (unordered_pair a a_1) universal_class) True
% 3.93/4.10  Clause #127 (by clausification #[6]): ∀ (a : Iota),
% 3.93/4.10    Eq (∀ (Y : Iota), Eq (ordered_pair a Y) (unordered_pair (singleton a) (unordered_pair a (singleton Y)))) True
% 3.93/4.10  Clause #128 (by clausification #[127]): ∀ (a a_1 : Iota), Eq (Eq (ordered_pair a a_1) (unordered_pair (singleton a) (unordered_pair a (singleton a_1)))) True
% 3.93/4.10  Clause #129 (by clausification #[128]): ∀ (a a_1 : Iota), Eq (ordered_pair a a_1) (unordered_pair (singleton a) (unordered_pair a (singleton a_1)))
% 3.93/4.10  Clause #130 (by superposition #[129, 70]): ∀ (a a_1 : Iota), Eq (member (ordered_pair a a_1) universal_class) True
% 3.93/4.10  Clause #136 (by superposition #[130, 68]): ∀ (a : Iota), Eq (member (skS.0 1 a) universal_class) True
% 3.93/4.10  Clause #173 (by superposition #[67, 136]): Eq True False
% 3.93/4.10  Clause #174 (by clausification #[173]): False
% 3.93/4.10  SZS output end Proof for theBenchmark.p
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