TSTP Solution File: SET117+1 by Duper---1.0
View Problem
- Process Solution
%------------------------------------------------------------------------------
% File : Duper---1.0
% Problem : SET117+1 : TPTP v8.1.2. Bugfixed v5.4.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n007.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Thu Aug 31 14:45:43 EDT 2023
% Result : Theorem 3.93s 4.10s
% Output : Proof 3.93s
% Verified :
% SZS Type : -
% Comments :
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.12/0.12 % Problem : SET117+1 : TPTP v8.1.2. Bugfixed v5.4.0.
% 0.12/0.14 % Command : duper %s
% 0.13/0.35 % Computer : n007.cluster.edu
% 0.13/0.35 % Model : x86_64 x86_64
% 0.13/0.35 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.35 % Memory : 8042.1875MB
% 0.13/0.35 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.35 % CPULimit : 300
% 0.13/0.35 % WCLimit : 300
% 0.13/0.35 % DateTime : Sat Aug 26 10:40:26 EDT 2023
% 0.13/0.35 % CPUTime :
% 3.93/4.10 SZS status Theorem for theBenchmark.p
% 3.93/4.10 SZS output start Proof for theBenchmark.p
% 3.93/4.10 Clause #4 (by assumption #[]): Eq (∀ (X Y : Iota), member (unordered_pair X Y) universal_class) True
% 3.93/4.10 Clause #6 (by assumption #[]): Eq (∀ (X Y : Iota), Eq (ordered_pair X Y) (unordered_pair (singleton X) (unordered_pair X (singleton Y)))) True
% 3.93/4.10 Clause #43 (by assumption #[]): Eq (Not (∀ (X : Iota), Eq (ordered_pair (first X) (second X)) X → member X universal_class)) True
% 3.93/4.10 Clause #63 (by clausification #[43]): Eq (∀ (X : Iota), Eq (ordered_pair (first X) (second X)) X → member X universal_class) False
% 3.93/4.10 Clause #64 (by clausification #[63]): ∀ (a : Iota),
% 3.93/4.10 Eq (Not (Eq (ordered_pair (first (skS.0 1 a)) (second (skS.0 1 a))) (skS.0 1 a) → member (skS.0 1 a) universal_class))
% 3.93/4.10 True
% 3.93/4.10 Clause #65 (by clausification #[64]): ∀ (a : Iota),
% 3.93/4.10 Eq (Eq (ordered_pair (first (skS.0 1 a)) (second (skS.0 1 a))) (skS.0 1 a) → member (skS.0 1 a) universal_class) False
% 3.93/4.10 Clause #66 (by clausification #[65]): ∀ (a : Iota), Eq (Eq (ordered_pair (first (skS.0 1 a)) (second (skS.0 1 a))) (skS.0 1 a)) True
% 3.93/4.10 Clause #67 (by clausification #[65]): ∀ (a : Iota), Eq (member (skS.0 1 a) universal_class) False
% 3.93/4.10 Clause #68 (by clausification #[66]): ∀ (a : Iota), Eq (ordered_pair (first (skS.0 1 a)) (second (skS.0 1 a))) (skS.0 1 a)
% 3.93/4.10 Clause #69 (by clausification #[4]): ∀ (a : Iota), Eq (∀ (Y : Iota), member (unordered_pair a Y) universal_class) True
% 3.93/4.10 Clause #70 (by clausification #[69]): ∀ (a a_1 : Iota), Eq (member (unordered_pair a a_1) universal_class) True
% 3.93/4.10 Clause #127 (by clausification #[6]): ∀ (a : Iota),
% 3.93/4.10 Eq (∀ (Y : Iota), Eq (ordered_pair a Y) (unordered_pair (singleton a) (unordered_pair a (singleton Y)))) True
% 3.93/4.10 Clause #128 (by clausification #[127]): ∀ (a a_1 : Iota), Eq (Eq (ordered_pair a a_1) (unordered_pair (singleton a) (unordered_pair a (singleton a_1)))) True
% 3.93/4.10 Clause #129 (by clausification #[128]): ∀ (a a_1 : Iota), Eq (ordered_pair a a_1) (unordered_pair (singleton a) (unordered_pair a (singleton a_1)))
% 3.93/4.10 Clause #130 (by superposition #[129, 70]): ∀ (a a_1 : Iota), Eq (member (ordered_pair a a_1) universal_class) True
% 3.93/4.10 Clause #136 (by superposition #[130, 68]): ∀ (a : Iota), Eq (member (skS.0 1 a) universal_class) True
% 3.93/4.10 Clause #173 (by superposition #[67, 136]): Eq True False
% 3.93/4.10 Clause #174 (by clausification #[173]): False
% 3.93/4.10 SZS output end Proof for theBenchmark.p
%------------------------------------------------------------------------------