TSTP Solution File: SET063-7 by Twee---2.4.2
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% File : Twee---2.4.2
% Problem : SET063-7 : TPTP v8.1.2. Bugfixed v2.1.0.
% Transfm : none
% Format : tptp:raw
% Command : parallel-twee %s --tstp --conditional-encoding if --smaller --drop-non-horn --give-up-on-saturation --explain-encoding --formal-proof
% Computer : n004.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Thu Aug 31 15:30:59 EDT 2023
% Result : Unsatisfiable 0.20s 0.52s
% Output : Proof 0.20s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.12/0.12 % Problem : SET063-7 : TPTP v8.1.2. Bugfixed v2.1.0.
% 0.12/0.13 % Command : parallel-twee %s --tstp --conditional-encoding if --smaller --drop-non-horn --give-up-on-saturation --explain-encoding --formal-proof
% 0.12/0.35 % Computer : n004.cluster.edu
% 0.12/0.35 % Model : x86_64 x86_64
% 0.12/0.35 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.35 % Memory : 8042.1875MB
% 0.12/0.35 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.35 % CPULimit : 300
% 0.12/0.35 % WCLimit : 300
% 0.12/0.35 % DateTime : Sat Aug 26 13:28:08 EDT 2023
% 0.12/0.35 % CPUTime :
% 0.20/0.52 Command-line arguments: --ground-connectedness --complete-subsets
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% 0.20/0.52 % SZS status Unsatisfiable
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% 0.20/0.52 % SZS output start Proof
% 0.20/0.52 Take the following subset of the input axioms:
% 0.20/0.52 fof(null_class_is_subclass, axiom, ![X]: subclass(null_class, X)).
% 0.20/0.52 fof(prove_corollary_of_null_class_is_subclass_1, negated_conjecture, subclass(x, null_class)).
% 0.20/0.52 fof(prove_corollary_of_null_class_is_subclass_2, negated_conjecture, x!=null_class).
% 0.20/0.52 fof(subclass_implies_equal, axiom, ![Y, X2]: (~subclass(X2, Y) | (~subclass(Y, X2) | X2=Y))).
% 0.20/0.52
% 0.20/0.52 Now clausify the problem and encode Horn clauses using encoding 3 of
% 0.20/0.52 http://www.cse.chalmers.se/~nicsma/papers/horn.pdf.
% 0.20/0.52 We repeatedly replace C & s=t => u=v by the two clauses:
% 0.20/0.52 fresh(y, y, x1...xn) = u
% 0.20/0.52 C => fresh(s, t, x1...xn) = v
% 0.20/0.52 where fresh is a fresh function symbol and x1..xn are the free
% 0.20/0.52 variables of u and v.
% 0.20/0.52 A predicate p(X) is encoded as p(X)=true (this is sound, because the
% 0.20/0.52 input problem has no model of domain size 1).
% 0.20/0.52
% 0.20/0.52 The encoding turns the above axioms into the following unit equations and goals:
% 0.20/0.52
% 0.20/0.52 Axiom 1 (prove_corollary_of_null_class_is_subclass_1): subclass(x, null_class) = true2.
% 0.20/0.52 Axiom 2 (null_class_is_subclass): subclass(null_class, X) = true2.
% 0.20/0.52 Axiom 3 (subclass_implies_equal): fresh6(X, X, Y, Z) = Y.
% 0.20/0.52 Axiom 4 (subclass_implies_equal): fresh5(X, X, Y, Z) = Z.
% 0.20/0.52 Axiom 5 (subclass_implies_equal): fresh6(subclass(X, Y), true2, Y, X) = fresh5(subclass(Y, X), true2, Y, X).
% 0.20/0.52
% 0.20/0.52 Goal 1 (prove_corollary_of_null_class_is_subclass_2): x = null_class.
% 0.20/0.52 Proof:
% 0.20/0.52 x
% 0.20/0.52 = { by axiom 3 (subclass_implies_equal) R->L }
% 0.20/0.52 fresh6(true2, true2, x, null_class)
% 0.20/0.52 = { by axiom 2 (null_class_is_subclass) R->L }
% 0.20/0.52 fresh6(subclass(null_class, x), true2, x, null_class)
% 0.20/0.52 = { by axiom 5 (subclass_implies_equal) }
% 0.20/0.52 fresh5(subclass(x, null_class), true2, x, null_class)
% 0.20/0.52 = { by axiom 1 (prove_corollary_of_null_class_is_subclass_1) }
% 0.20/0.52 fresh5(true2, true2, x, null_class)
% 0.20/0.52 = { by axiom 4 (subclass_implies_equal) }
% 0.20/0.52 null_class
% 0.20/0.52 % SZS output end Proof
% 0.20/0.52
% 0.20/0.52 RESULT: Unsatisfiable (the axioms are contradictory).
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