TSTP Solution File: SET063+3 by Duper---1.0
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% File : Duper---1.0
% Problem : SET063+3 : TPTP v8.1.2. Released v2.2.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n019.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Thu Aug 31 14:45:24 EDT 2023
% Result : Theorem 3.57s 3.80s
% Output : Proof 3.57s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12 % Problem : SET063+3 : TPTP v8.1.2. Released v2.2.0.
% 0.00/0.14 % Command : duper %s
% 0.16/0.35 % Computer : n019.cluster.edu
% 0.16/0.35 % Model : x86_64 x86_64
% 0.16/0.35 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.16/0.35 % Memory : 8042.1875MB
% 0.16/0.35 % OS : Linux 3.10.0-693.el7.x86_64
% 0.16/0.35 % CPULimit : 300
% 0.16/0.35 % WCLimit : 300
% 0.16/0.35 % DateTime : Sat Aug 26 14:04:58 EDT 2023
% 0.16/0.35 % CPUTime :
% 3.57/3.80 SZS status Theorem for theBenchmark.p
% 3.57/3.80 SZS output start Proof for theBenchmark.p
% 3.57/3.80 Clause #0 (by assumption #[]): Eq (∀ (B : Iota), subset empty_set B) True
% 3.57/3.80 Clause #3 (by assumption #[]): Eq (∀ (B C : Iota), Iff (Eq B C) (And (subset B C) (subset C B))) True
% 3.57/3.80 Clause #6 (by assumption #[]): Eq (Not (∀ (B : Iota), subset B empty_set → Eq B empty_set)) True
% 3.57/3.80 Clause #8 (by clausification #[0]): ∀ (a : Iota), Eq (subset empty_set a) True
% 3.57/3.80 Clause #11 (by clausification #[6]): Eq (∀ (B : Iota), subset B empty_set → Eq B empty_set) False
% 3.57/3.80 Clause #12 (by clausification #[11]): ∀ (a : Iota), Eq (Not (subset (skS.0 0 a) empty_set → Eq (skS.0 0 a) empty_set)) True
% 3.57/3.80 Clause #13 (by clausification #[12]): ∀ (a : Iota), Eq (subset (skS.0 0 a) empty_set → Eq (skS.0 0 a) empty_set) False
% 3.57/3.80 Clause #14 (by clausification #[13]): ∀ (a : Iota), Eq (subset (skS.0 0 a) empty_set) True
% 3.57/3.80 Clause #15 (by clausification #[13]): ∀ (a : Iota), Eq (Eq (skS.0 0 a) empty_set) False
% 3.57/3.80 Clause #41 (by clausification #[3]): ∀ (a : Iota), Eq (∀ (C : Iota), Iff (Eq a C) (And (subset a C) (subset C a))) True
% 3.57/3.80 Clause #42 (by clausification #[41]): ∀ (a a_1 : Iota), Eq (Iff (Eq a a_1) (And (subset a a_1) (subset a_1 a))) True
% 3.57/3.80 Clause #43 (by clausification #[42]): ∀ (a a_1 : Iota), Or (Eq (Eq a a_1) True) (Eq (And (subset a a_1) (subset a_1 a)) False)
% 3.57/3.80 Clause #45 (by clausification #[43]): ∀ (a a_1 : Iota), Or (Eq (And (subset a a_1) (subset a_1 a)) False) (Eq a a_1)
% 3.57/3.80 Clause #46 (by clausification #[45]): ∀ (a a_1 : Iota), Or (Eq a a_1) (Or (Eq (subset a a_1) False) (Eq (subset a_1 a) False))
% 3.57/3.80 Clause #48 (by superposition #[46, 8]): ∀ (a : Iota), Or (Eq empty_set a) (Or (Eq (subset a empty_set) False) (Eq False True))
% 3.57/3.80 Clause #51 (by clausification #[48]): ∀ (a : Iota), Or (Eq empty_set a) (Eq (subset a empty_set) False)
% 3.57/3.80 Clause #52 (by superposition #[51, 14]): ∀ (a : Iota), Or (Eq empty_set (skS.0 0 a)) (Eq False True)
% 3.57/3.80 Clause #55 (by clausification #[52]): ∀ (a : Iota), Eq empty_set (skS.0 0 a)
% 3.57/3.80 Clause #57 (by clausification #[15]): ∀ (a : Iota), Ne (skS.0 0 a) empty_set
% 3.57/3.80 Clause #58 (by forward demodulation #[57, 55]): Ne empty_set empty_set
% 3.57/3.80 Clause #59 (by eliminate resolved literals #[58]): False
% 3.57/3.80 SZS output end Proof for theBenchmark.p
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