TSTP Solution File: SET047+1 by SPASS---3.9

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : SPASS---3.9
% Problem  : SET047+1 : TPTP v8.1.0. Released v2.0.0.
% Transfm  : none
% Format   : tptp
% Command  : run_spass %d %s

% Computer : n012.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Tue Jul 19 05:23:09 EDT 2022

% Result   : Theorem 0.20s 0.43s
% Output   : Refutation 0.20s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :   13
%            Number of leaves      :    6
% Syntax   : Number of clauses     :   27 (  10 unt;   6 nHn;  27 RR)
%            Number of literals    :   51 (   0 equ;  20 neg)
%            Maximal clause size   :    3 (   1 avg)
%            Maximal term depth    :    2 (   1 avg)
%            Number of predicates  :    3 (   2 usr;   1 prp; 0-2 aty)
%            Number of functors    :    6 (   6 usr;   5 con; 0-2 aty)
%            Number of variables   :    0 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(1,axiom,
    ( set_equal(skc3,skc2)
    | set_equal(skc2,skc3) ),
    file('SET047+1.p',unknown),
    [] ).

cnf(2,axiom,
    ( ~ set_equal(skc3,skc2)
    | ~ set_equal(skc2,skc3) ),
    file('SET047+1.p',unknown),
    [] ).

cnf(3,axiom,
    ( ~ set_equal(u,v)
    | ~ element(w,u)
    | element(w,v) ),
    file('SET047+1.p',unknown),
    [] ).

cnf(4,axiom,
    ( ~ set_equal(u,v)
    | ~ element(w,v)
    | element(w,u) ),
    file('SET047+1.p',unknown),
    [] ).

cnf(5,axiom,
    ( set_equal(u,v)
    | element(skf1(v,u),v)
    | element(skf1(v,u),u) ),
    file('SET047+1.p',unknown),
    [] ).

cnf(6,axiom,
    ( ~ element(skf1(u,v),u)
    | ~ element(skf1(u,v),v)
    | set_equal(v,u) ),
    file('SET047+1.p',unknown),
    [] ).

cnf(7,plain,
    set_equal(skc3,skc2),
    inference(spt,[spt(split,[position(s1)])],[1]),
    [iquote('1:Spt:1.0')] ).

cnf(8,plain,
    ~ set_equal(skc2,skc3),
    inference(mrr,[status(thm)],[2,7]),
    [iquote('1:MRR:2.0,7.0')] ).

cnf(9,plain,
    ( ~ element(u,skc2)
    | element(u,skc3) ),
    inference(res,[status(thm),theory(equality)],[7,4]),
    [iquote('1:Res:7.0,4.0')] ).

cnf(10,plain,
    ( ~ element(u,skc3)
    | element(u,skc2) ),
    inference(res,[status(thm),theory(equality)],[7,3]),
    [iquote('1:Res:7.0,3.0')] ).

cnf(14,plain,
    ( set_equal(skc2,u)
    | element(skf1(u,skc2),u)
    | element(skf1(u,skc2),skc3) ),
    inference(res,[status(thm),theory(equality)],[5,9]),
    [iquote('1:Res:5.2,9.0')] ).

cnf(28,plain,
    ( set_equal(skc2,skc3)
    | element(skf1(skc3,skc2),skc3) ),
    inference(fac,[status(thm)],[14]),
    [iquote('1:Fac:14.1,14.2')] ).

cnf(31,plain,
    element(skf1(skc3,skc2),skc3),
    inference(mrr,[status(thm)],[28,8]),
    [iquote('1:MRR:28.0,8.0')] ).

cnf(34,plain,
    ( ~ element(skf1(skc3,skc2),skc2)
    | set_equal(skc2,skc3) ),
    inference(res,[status(thm),theory(equality)],[31,6]),
    [iquote('1:Res:31.0,6.0')] ).

cnf(35,plain,
    ~ element(skf1(skc3,skc2),skc2),
    inference(mrr,[status(thm)],[34,8]),
    [iquote('1:MRR:34.1,8.0')] ).

cnf(37,plain,
    ~ element(skf1(skc3,skc2),skc3),
    inference(res,[status(thm),theory(equality)],[10,35]),
    [iquote('1:Res:10.1,35.0')] ).

cnf(39,plain,
    $false,
    inference(mrr,[status(thm)],[37,31]),
    [iquote('1:MRR:37.0,31.0')] ).

cnf(40,plain,
    ~ set_equal(skc3,skc2),
    inference(spt,[spt(split,[position(sa)])],[39,7]),
    [iquote('1:Spt:39.0,1.0,7.0')] ).

cnf(41,plain,
    set_equal(skc2,skc3),
    inference(spt,[spt(split,[position(s2)])],[1]),
    [iquote('1:Spt:39.0,1.1')] ).

cnf(42,plain,
    ( ~ element(u,skc2)
    | element(u,skc3) ),
    inference(res,[status(thm),theory(equality)],[41,3]),
    [iquote('1:Res:41.0,3.0')] ).

cnf(43,plain,
    ( ~ element(u,skc3)
    | element(u,skc2) ),
    inference(res,[status(thm),theory(equality)],[41,4]),
    [iquote('1:Res:41.0,4.0')] ).

cnf(44,plain,
    ( set_equal(u,skc2)
    | element(skf1(skc2,u),u)
    | element(skf1(skc2,u),skc3) ),
    inference(res,[status(thm),theory(equality)],[5,42]),
    [iquote('1:Res:5.1,42.0')] ).

cnf(46,plain,
    ( ~ element(skf1(skc2,u),skc3)
    | ~ element(skf1(skc2,u),u)
    | set_equal(u,skc2) ),
    inference(res,[status(thm),theory(equality)],[43,6]),
    [iquote('1:Res:43.1,6.0')] ).

cnf(48,plain,
    ( set_equal(skc3,skc2)
    | element(skf1(skc2,skc3),skc3) ),
    inference(fac,[status(thm)],[44]),
    [iquote('1:Fac:44.1,44.2')] ).

cnf(51,plain,
    element(skf1(skc2,skc3),skc3),
    inference(mrr,[status(thm)],[48,40]),
    [iquote('1:MRR:48.0,40.0')] ).

cnf(60,plain,
    ( ~ element(skf1(skc2,skc3),skc3)
    | set_equal(skc3,skc2) ),
    inference(res,[status(thm),theory(equality)],[51,46]),
    [iquote('1:Res:51.0,46.0')] ).

cnf(61,plain,
    $false,
    inference(mrr,[status(thm)],[60,51,40]),
    [iquote('1:MRR:60.0,60.1,51.0,40.0')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.04/0.12  % Problem  : SET047+1 : TPTP v8.1.0. Released v2.0.0.
% 0.04/0.13  % Command  : run_spass %d %s
% 0.13/0.34  % Computer : n012.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit : 300
% 0.13/0.34  % WCLimit  : 600
% 0.13/0.34  % DateTime : Sun Jul 10 18:05:43 EDT 2022
% 0.13/0.34  % CPUTime  : 
% 0.20/0.43  
% 0.20/0.43  SPASS V 3.9 
% 0.20/0.43  SPASS beiseite: Proof found.
% 0.20/0.43  % SZS status Theorem
% 0.20/0.43  Problem: /export/starexec/sandbox2/benchmark/theBenchmark.p 
% 0.20/0.43  SPASS derived 38 clauses, backtracked 3 clauses, performed 1 splits and kept 28 clauses.
% 0.20/0.43  SPASS allocated 85164 KBytes.
% 0.20/0.43  SPASS spent	0:00:00.08 on the problem.
% 0.20/0.43  		0:00:00.03 for the input.
% 0.20/0.43  		0:00:00.03 for the FLOTTER CNF translation.
% 0.20/0.43  		0:00:00.00 for inferences.
% 0.20/0.43  		0:00:00.00 for the backtracking.
% 0.20/0.43  		0:00:00.00 for the reduction.
% 0.20/0.43  
% 0.20/0.43  
% 0.20/0.43  Here is a proof with depth 6, length 27 :
% 0.20/0.43  % SZS output start Refutation
% See solution above
% 0.20/0.43  Formulae used in the proof : pel43 pel43_1
% 0.20/0.43  
%------------------------------------------------------------------------------