TSTP Solution File: SET045+1 by Otter---3.3

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Otter---3.3
% Problem  : SET045+1 : TPTP v8.1.0. Released v2.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : otter-tptp-script %s

% Computer : n008.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Wed Jul 27 13:12:55 EDT 2022

% Result   : Theorem 1.60s 1.79s
% Output   : Refutation 1.60s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    3
%            Number of leaves      :    3
% Syntax   : Number of clauses     :    6 (   4 unt;   1 nHn;   5 RR)
%            Number of literals    :    9 (   0 equ;   5 neg)
%            Maximal clause size   :    3 (   1 avg)
%            Maximal term depth    :    2 (   1 avg)
%            Number of predicates  :    2 (   1 usr;   1 prp; 0-2 aty)
%            Number of functors    :    2 (   2 usr;   1 con; 0-1 aty)
%            Number of variables   :    7 (   2 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(2,axiom,
    ( ~ element(A,dollar_f1(B))
    | ~ element(A,A) ),
    file('SET045+1.p',unknown),
    [] ).

cnf(3,axiom,
    ( element(A,dollar_f1(B))
    | ~ element(A,B)
    | element(A,A) ),
    file('SET045+1.p',unknown),
    [] ).

cnf(4,plain,
    ~ element(dollar_f1(A),dollar_f1(A)),
    inference(factor,[status(thm)],[2]),
    [iquote('factor,2.1.2')] ).

cnf(5,plain,
    ~ element(dollar_f1(A),A),
    inference(unit_del,[status(thm)],[inference(factor,[status(thm)],[3]),4]),
    [iquote('factor,3.1.3,unit_del,4')] ).

cnf(6,axiom,
    element(A,dollar_c1),
    file('SET045+1.p',unknown),
    [] ).

cnf(7,plain,
    $false,
    inference(binary,[status(thm)],[6,5]),
    [iquote('binary,6.1,5.1')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.04/0.12  % Problem  : SET045+1 : TPTP v8.1.0. Released v2.0.0.
% 0.04/0.13  % Command  : otter-tptp-script %s
% 0.12/0.34  % Computer : n008.cluster.edu
% 0.12/0.34  % Model    : x86_64 x86_64
% 0.12/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.34  % Memory   : 8042.1875MB
% 0.12/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.34  % CPULimit : 300
% 0.12/0.34  % WCLimit  : 300
% 0.12/0.34  % DateTime : Wed Jul 27 10:37:38 EDT 2022
% 0.12/0.34  % CPUTime  : 
% 1.60/1.79  
% 1.60/1.79  -------- PROOF -------- 
% 1.60/1.79  ----- Otter 3.3f, August 2004 -----
% 1.60/1.79  The process was started by sandbox on n008.cluster.edu,
% 1.60/1.79  Wed Jul 27 10:37:38 2022
% 1.60/1.79  The command was "./otter".  The process ID is 7453.
% 1.60/1.79  
% 1.60/1.79  set(prolog_style_variables).
% 1.60/1.79  set(auto).
% 1.60/1.79     dependent: set(auto1).
% 1.60/1.79     dependent: set(process_input).
% 1.60/1.79     dependent: clear(print_kept).
% 1.60/1.79     dependent: clear(print_new_demod).
% 1.60/1.79     dependent: clear(print_back_demod).
% 1.60/1.79     dependent: clear(print_back_sub).
% 1.60/1.79     dependent: set(control_memory).
% 1.60/1.79     dependent: assign(max_mem, 12000).
% 1.60/1.79     dependent: assign(pick_given_ratio, 4).
% 1.60/1.79     dependent: assign(stats_level, 1).
% 1.60/1.79     dependent: assign(max_seconds, 10800).
% 1.60/1.79  clear(print_given).
% 1.60/1.79  
% 1.60/1.79  formula_list(usable).
% 1.60/1.79  all Z exists Y all X (element(X,Y)<->element(X,Z)& -element(X,X)).
% 1.60/1.79  -(-(exists Z all X element(X,Z))).
% 1.60/1.79  end_of_list.
% 1.60/1.79  
% 1.60/1.79  -------> usable clausifies to:
% 1.60/1.79  
% 1.60/1.79  list(usable).
% 1.60/1.79  0 [] -element(X,$f1(Z))|element(X,Z).
% 1.60/1.79  0 [] -element(X,$f1(Z))| -element(X,X).
% 1.60/1.79  0 [] element(X,$f1(Z))| -element(X,Z)|element(X,X).
% 1.60/1.79  0 [] element(X,$c1).
% 1.60/1.79  end_of_list.
% 1.60/1.79  
% 1.60/1.79  SCAN INPUT: prop=0, horn=0, equality=0, symmetry=0, max_lits=3.
% 1.60/1.79  
% 1.60/1.79  This is a non-Horn set without equality.  The strategy will
% 1.60/1.79  be ordered hyper_res, unit deletion, and factoring, with
% 1.60/1.79  satellites in sos and with nuclei in usable.
% 1.60/1.79  
% 1.60/1.79     dependent: set(hyper_res).
% 1.60/1.79     dependent: set(factor).
% 1.60/1.79     dependent: set(unit_deletion).
% 1.60/1.79  
% 1.60/1.79  ------------> process usable:
% 1.60/1.79  ** KEPT (pick-wt=7): 1 [] -element(A,$f1(B))|element(A,B).
% 1.60/1.79  ** KEPT (pick-wt=7): 2 [] -element(A,$f1(B))| -element(A,A).
% 1.60/1.79  ** KEPT (pick-wt=10): 3 [] element(A,$f1(B))| -element(A,B)|element(A,A).
% 1.60/1.79  
% 1.60/1.79  ------------> process sos:
% 1.60/1.79  ** KEPT (pick-wt=3): 6 [] element(A,$c1).
% 1.60/1.79  
% 1.60/1.79  ----> UNIT CONFLICT at   0.00 sec ----> 7 [binary,6.1,5.1] $F.
% 1.60/1.79  
% 1.60/1.79  Length of proof is 2.  Level of proof is 2.
% 1.60/1.79  
% 1.60/1.79  ---------------- PROOF ----------------
% 1.60/1.79  % SZS status Theorem
% 1.60/1.79  % SZS output start Refutation
% See solution above
% 1.60/1.79  ------------ end of proof -------------
% 1.60/1.79  
% 1.60/1.79  
% 1.60/1.79  Search stopped by max_proofs option.
% 1.60/1.79  
% 1.60/1.79  
% 1.60/1.79  Search stopped by max_proofs option.
% 1.60/1.79  
% 1.60/1.79  ============ end of search ============
% 1.60/1.79  
% 1.60/1.79  -------------- statistics -------------
% 1.60/1.79  clauses given                  0
% 1.60/1.79  clauses generated              2
% 1.60/1.79  clauses kept                   6
% 1.60/1.79  clauses forward subsumed       0
% 1.60/1.79  clauses back subsumed          0
% 1.60/1.79  Kbytes malloced              976
% 1.60/1.79  
% 1.60/1.79  ----------- times (seconds) -----------
% 1.60/1.79  user CPU time          0.00          (0 hr, 0 min, 0 sec)
% 1.60/1.79  system CPU time        0.00          (0 hr, 0 min, 0 sec)
% 1.60/1.79  wall-clock time        2             (0 hr, 0 min, 2 sec)
% 1.60/1.79  
% 1.60/1.79  That finishes the proof of the theorem.
% 1.60/1.79  
% 1.60/1.79  Process 7453 finished Wed Jul 27 10:37:40 2022
% 1.60/1.79  Otter interrupted
% 1.60/1.79  PROOF FOUND
%------------------------------------------------------------------------------