TSTP Solution File: SET045+1 by Duper---1.0
View Problem
- Process Solution
%------------------------------------------------------------------------------
% File : Duper---1.0
% Problem : SET045+1 : TPTP v8.1.2. Released v2.0.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n009.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Thu Aug 31 14:45:17 EDT 2023
% Result : Theorem 5.56s 5.76s
% Output : Proof 5.56s
% Verified :
% SZS Type : -
% Comments :
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.11 % Problem : SET045+1 : TPTP v8.1.2. Released v2.0.0.
% 0.03/0.12 % Command : duper %s
% 0.12/0.33 % Computer : n009.cluster.edu
% 0.12/0.33 % Model : x86_64 x86_64
% 0.12/0.33 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33 % Memory : 8042.1875MB
% 0.12/0.33 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33 % CPULimit : 300
% 0.12/0.33 % WCLimit : 300
% 0.12/0.33 % DateTime : Sat Aug 26 10:31:50 EDT 2023
% 0.12/0.33 % CPUTime :
% 5.56/5.76 SZS status Theorem for theBenchmark.p
% 5.56/5.76 SZS output start Proof for theBenchmark.p
% 5.56/5.76 Clause #0 (by assumption #[]): Eq (∀ (Z : Iota), Exists fun Y => ∀ (X : Iota), Iff (element X Y) (And (element X Z) (Not (element X X)))) True
% 5.56/5.76 Clause #1 (by assumption #[]): Eq (Not (Not (Exists fun Z => ∀ (X : Iota), element X Z))) True
% 5.56/5.76 Clause #2 (by clausification #[1]): Eq (Not (Exists fun Z => ∀ (X : Iota), element X Z)) False
% 5.56/5.76 Clause #3 (by clausification #[2]): Eq (Exists fun Z => ∀ (X : Iota), element X Z) True
% 5.56/5.76 Clause #4 (by clausification #[3]): ∀ (a : Iota), Eq (∀ (X : Iota), element X (skS.0 0 a)) True
% 5.56/5.76 Clause #5 (by clausification #[4]): ∀ (a a_1 : Iota), Eq (element a (skS.0 0 a_1)) True
% 5.56/5.76 Clause #6 (by clausification #[0]): ∀ (a : Iota), Eq (Exists fun Y => ∀ (X : Iota), Iff (element X Y) (And (element X a) (Not (element X X)))) True
% 5.56/5.76 Clause #7 (by clausification #[6]): ∀ (a a_1 : Iota), Eq (∀ (X : Iota), Iff (element X (skS.0 1 a a_1)) (And (element X a) (Not (element X X)))) True
% 5.56/5.76 Clause #8 (by clausification #[7]): ∀ (a a_1 a_2 : Iota), Eq (Iff (element a (skS.0 1 a_1 a_2)) (And (element a a_1) (Not (element a a)))) True
% 5.56/5.76 Clause #9 (by clausification #[8]): ∀ (a a_1 a_2 : Iota), Or (Eq (element a (skS.0 1 a_1 a_2)) True) (Eq (And (element a a_1) (Not (element a a))) False)
% 5.56/5.76 Clause #10 (by clausification #[8]): ∀ (a a_1 a_2 : Iota), Or (Eq (element a (skS.0 1 a_1 a_2)) False) (Eq (And (element a a_1) (Not (element a a))) True)
% 5.56/5.76 Clause #11 (by clausification #[9]): ∀ (a a_1 a_2 : Iota),
% 5.56/5.76 Or (Eq (element a (skS.0 1 a_1 a_2)) True) (Or (Eq (element a a_1) False) (Eq (Not (element a a)) False))
% 5.56/5.76 Clause #12 (by clausification #[11]): ∀ (a a_1 a_2 : Iota), Or (Eq (element a (skS.0 1 a_1 a_2)) True) (Or (Eq (element a a_1) False) (Eq (element a a) True))
% 5.56/5.76 Clause #13 (by superposition #[12, 5]): ∀ (a a_1 a_2 : Iota), Or (Eq (element a (skS.0 1 (skS.0 0 a_1) a_2)) True) (Or (Eq (element a a) True) (Eq False True))
% 5.56/5.76 Clause #14 (by clausification #[10]): ∀ (a a_1 a_2 : Iota), Or (Eq (element a (skS.0 1 a_1 a_2)) False) (Eq (Not (element a a)) True)
% 5.56/5.76 Clause #16 (by clausification #[14]): ∀ (a a_1 a_2 : Iota), Or (Eq (element a (skS.0 1 a_1 a_2)) False) (Eq (element a a) False)
% 5.56/5.76 Clause #17 (by clausification #[13]): ∀ (a a_1 a_2 : Iota), Or (Eq (element a (skS.0 1 (skS.0 0 a_1) a_2)) True) (Eq (element a a) True)
% 5.56/5.76 Clause #21 (by superposition #[17, 16]): ∀ (a a_1 a_2 a_3 : Iota),
% 5.56/5.76 Or (Eq (element (skS.0 1 a a_1) (skS.0 1 (skS.0 0 a_2) a_3)) True) (Or (Eq True False) (Eq True False))
% 5.56/5.76 Clause #26 (by clausification #[21]): ∀ (a a_1 a_2 a_3 : Iota), Or (Eq (element (skS.0 1 a a_1) (skS.0 1 (skS.0 0 a_2) a_3)) True) (Eq True False)
% 5.56/5.76 Clause #27 (by clausification #[26]): ∀ (a a_1 a_2 a_3 : Iota), Eq (element (skS.0 1 a a_1) (skS.0 1 (skS.0 0 a_2) a_3)) True
% 5.56/5.76 Clause #28 (by superposition #[27, 16]): ∀ (a a_1 : Iota), Or (Eq True False) (Eq (element (skS.0 1 a a_1) (skS.0 1 a a_1)) False)
% 5.56/5.76 Clause #32 (by clausification #[28]): ∀ (a a_1 : Iota), Eq (element (skS.0 1 a a_1) (skS.0 1 a a_1)) False
% 5.56/5.76 Clause #33 (by superposition #[32, 27]): Eq False True
% 5.56/5.76 Clause #35 (by clausification #[33]): False
% 5.56/5.76 SZS output end Proof for theBenchmark.p
%------------------------------------------------------------------------------