%------------------------------------------------------------------------------
% File     : cocATP---0.2.0
% Problem  : SET045^5 : TPTP v6.1.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p

% Computer : n092.star.cs.uiowa.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2609 0 2.40GHz
% Memory   : 32286.75MB
% OS       : Linux 2.6.32-431.20.3.el6.x86_64
% CPULimit : 300s
% DateTime : Thu Jul 17 13:30:03 EDT 2014

% Result   : Theorem 0.63s
% Output   : Proof 0.63s
% Verified : 
% SZS Type : None (Parsing solution fails)
% Syntax   : Number of formulae    : 0

% Comments : 
%------------------------------------------------------------------------------
%----ERROR: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% % Problem  : SET045^5 : TPTP v6.1.0. Released v4.0.0.
% % Command  : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p
% % Computer : n092.star.cs.uiowa.edu
% % Model    : x86_64 x86_64
% % CPU      : Intel(R) Xeon(R) CPU E5-2609 0 @ 2.40GHz
% % Memory   : 32286.75MB
% % OS       : Linux 2.6.32-431.20.3.el6.x86_64
% % CPULimit : 300
% % DateTime : Thu Jul 17 08:17:11 CDT 2014
% % CPUTime  : 0.63 
% Python 2.7.5
% Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox/benchmark/', '/export/starexec/sandbox/benchmark/']
% FOF formula (<kernel.Constant object at 0x1d03368>, <kernel.Type object at 0x1d22830>) of role type named b_type
% Using role type
% Declaring b:Type
% FOF formula (<kernel.Constant object at 0x1d03170>, <kernel.Type object at 0x1d22830>) of role type named a_type
% Using role type
% Declaring a:Type
% FOF formula (<kernel.Constant object at 0x1d03368>, <kernel.Constant object at 0x1d03248>) of role type named cA
% Using role type
% Declaring cA:b
% FOF formula ((ex (a->b)) (fun (U:(a->b))=> (forall (V:a), (((eq b) (U V)) cA)))) of role conjecture named cTTTP5243
% Conjecture to prove = ((ex (a->b)) (fun (U:(a->b))=> (forall (V:a), (((eq b) (U V)) cA)))):Prop
% Parameter a_DUMMY:a.
% We need to prove ['((ex (a->b)) (fun (U:(a->b))=> (forall (V:a), (((eq b) (U V)) cA))))']
% Parameter b:Type.
% Parameter a:Type.
% Parameter cA:b.
% Trying to prove ((ex (a->b)) (fun (U:(a->b))=> (forall (V:a), (((eq b) (U V)) cA))))
% Found eq_ref00:=(eq_ref0 (x V)):(((eq b) (x V)) (x V))
% Found (eq_ref0 (x V)) as proof of (((eq b) (x V)) cA)
% Found ((eq_ref b) (x V)) as proof of (((eq b) (x V)) cA)
% Found ((eq_ref b) (x V)) as proof of (((eq b) (x V)) cA)
% Found (fun (V:a)=> ((eq_ref b) (x V))) as proof of (((eq b) (x V)) cA)
% Found (fun (V:a)=> ((eq_ref b) (x V))) as proof of (forall (V:a), (((eq b) (x V)) cA))
% Found (ex_intro000 (fun (V:a)=> ((eq_ref b) (x V)))) as proof of ((ex (a->b)) (fun (U:(a->b))=> (forall (V:a), (((eq b) (U V)) cA))))
% Found ((ex_intro00 (fun (x2:a)=> cA)) (fun (V:a)=> ((eq_ref b) ((fun (x2:a)=> cA) V)))) as proof of ((ex (a->b)) (fun (U:(a->b))=> (forall (V:a), (((eq b) (U V)) cA))))
% Found (((ex_intro0 (fun (U:(a->b))=> (forall (V:a), (((eq b) (U V)) cA)))) (fun (x2:a)=> cA)) (fun (V:a)=> ((eq_ref b) ((fun (x2:a)=> cA) V)))) as proof of ((ex (a->b)) (fun (U:(a->b))=> (forall (V:a), (((eq b) (U V)) cA))))
% Found ((((ex_intro (a->b)) (fun (U:(a->b))=> (forall (V:a), (((eq b) (U V)) cA)))) (fun (x2:a)=> cA)) (fun (V:a)=> ((eq_ref b) ((fun (x2:a)=> cA) V)))) as proof of ((ex (a->b)) (fun (U:(a->b))=> (forall (V:a), (((eq b) (U V)) cA))))
% Found ((((ex_intro (a->b)) (fun (U:(a->b))=> (forall (V:a), (((eq b) (U V)) cA)))) (fun (x2:a)=> cA)) (fun (V:a)=> ((eq_ref b) ((fun (x2:a)=> cA) V)))) as proof of ((ex (a->b)) (fun (U:(a->b))=> (forall (V:a), (((eq b) (U V)) cA))))
% Got proof ((((ex_intro (a->b)) (fun (U:(a->b))=> (forall (V:a), (((eq b) (U V)) cA)))) (fun (x2:a)=> cA)) (fun (V:a)=> ((eq_ref b) ((fun (x2:a)=> cA) V))))
% Time elapsed = 0.317081s
% node=67 cost=53.000000 depth=9
% ::::::::::::::::::::::
% % SZS status Theorem for /export/starexec/sandbox/benchmark/theBenchmark.p
% % SZS output start Proof for /export/starexec/sandbox/benchmark/theBenchmark.p
% ((((ex_intro (a->b)) (fun (U:(a->b))=> (forall (V:a), (((eq b) (U V)) cA)))) (fun (x2:a)=> cA)) (fun (V:a)=> ((eq_ref b) ((fun (x2:a)=> cA) V))))
% % SZS output end Proof for /export/starexec/sandbox/benchmark/theBenchmark.p
% EOF
%------------------------------------------------------------------------------