TSTP Solution File: SET044+1 by Otter---3.3
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- Process Solution
%------------------------------------------------------------------------------
% File : Otter---3.3
% Problem : SET044+1 : TPTP v8.1.0. Released v2.0.0.
% Transfm : none
% Format : tptp:raw
% Command : otter-tptp-script %s
% Computer : n021.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Wed Jul 27 13:12:54 EDT 2022
% Result : Theorem 1.68s 1.88s
% Output : Refutation 1.68s
% Verified :
% SZS Type : Refutation
% Derivation depth : 3
% Number of leaves : 4
% Syntax : Number of clauses : 9 ( 3 unt; 3 nHn; 6 RR)
% Number of literals : 15 ( 0 equ; 4 neg)
% Maximal clause size : 2 ( 1 avg)
% Maximal term depth : 2 ( 1 avg)
% Number of predicates : 2 ( 1 usr; 1 prp; 0-2 aty)
% Number of functors : 2 ( 2 usr; 1 con; 0-1 aty)
% Number of variables : 8 ( 0 sgn)
% Comments :
%------------------------------------------------------------------------------
cnf(1,axiom,
( ~ element(A,dollar_c1)
| element(A,A) ),
file('SET044+1.p',unknown),
[] ).
cnf(2,axiom,
( element(A,dollar_c1)
| ~ element(A,A) ),
file('SET044+1.p',unknown),
[] ).
cnf(3,axiom,
( ~ element(A,dollar_f1(B))
| ~ element(A,B) ),
file('SET044+1.p',unknown),
[] ).
cnf(4,axiom,
( element(A,dollar_f1(B))
| element(A,B) ),
file('SET044+1.p',unknown),
[] ).
cnf(6,plain,
( element(dollar_f1(A),A)
| element(dollar_f1(A),dollar_c1) ),
inference(hyper,[status(thm)],[4,2]),
[iquote('hyper,4,2')] ).
cnf(8,plain,
( element(A,dollar_f1(dollar_c1))
| element(A,A) ),
inference(hyper,[status(thm)],[4,1]),
[iquote('hyper,4,1')] ).
cnf(9,plain,
element(dollar_f1(dollar_c1),dollar_c1),
inference(factor,[status(thm)],[6]),
[iquote('factor,6.1.2')] ).
cnf(10,plain,
element(dollar_f1(dollar_c1),dollar_f1(dollar_c1)),
inference(factor,[status(thm)],[8]),
[iquote('factor,8.1.2')] ).
cnf(13,plain,
$false,
inference(hyper,[status(thm)],[10,3,9]),
[iquote('hyper,10,3,9')] ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.12 % Problem : SET044+1 : TPTP v8.1.0. Released v2.0.0.
% 0.07/0.12 % Command : otter-tptp-script %s
% 0.13/0.33 % Computer : n021.cluster.edu
% 0.13/0.33 % Model : x86_64 x86_64
% 0.13/0.33 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.33 % Memory : 8042.1875MB
% 0.13/0.33 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.33 % CPULimit : 300
% 0.13/0.33 % WCLimit : 300
% 0.13/0.33 % DateTime : Wed Jul 27 10:47:38 EDT 2022
% 0.13/0.33 % CPUTime :
% 1.68/1.88 ----- Otter 3.3f, August 2004 -----
% 1.68/1.88 The process was started by sandbox2 on n021.cluster.edu,
% 1.68/1.88 Wed Jul 27 10:47:38 2022
% 1.68/1.88 The command was "./otter". The process ID is 26871.
% 1.68/1.88
% 1.68/1.88 set(prolog_style_variables).
% 1.68/1.88 set(auto).
% 1.68/1.88 dependent: set(auto1).
% 1.68/1.88 dependent: set(process_input).
% 1.68/1.88 dependent: clear(print_kept).
% 1.68/1.88 dependent: clear(print_new_demod).
% 1.68/1.88 dependent: clear(print_back_demod).
% 1.68/1.88 dependent: clear(print_back_sub).
% 1.68/1.88 dependent: set(control_memory).
% 1.68/1.88 dependent: assign(max_mem, 12000).
% 1.68/1.88 dependent: assign(pick_given_ratio, 4).
% 1.68/1.88 dependent: assign(stats_level, 1).
% 1.68/1.88 dependent: assign(max_seconds, 10800).
% 1.68/1.88 clear(print_given).
% 1.68/1.88
% 1.68/1.88 formula_list(usable).
% 1.68/1.88 -((exists Y all X (element(X,Y)<->element(X,X)))-> -(all X1 exists Y1 all Z (element(Z,Y1)<-> -element(Z,X1)))).
% 1.68/1.88 end_of_list.
% 1.68/1.88
% 1.68/1.88 -------> usable clausifies to:
% 1.68/1.88
% 1.68/1.88 list(usable).
% 1.68/1.88 0 [] -element(X,$c1)|element(X,X).
% 1.68/1.88 0 [] element(X,$c1)| -element(X,X).
% 1.68/1.88 0 [] -element(Z,$f1(X1))| -element(Z,X1).
% 1.68/1.88 0 [] element(Z,$f1(X1))|element(Z,X1).
% 1.68/1.88 end_of_list.
% 1.68/1.88
% 1.68/1.88 SCAN INPUT: prop=0, horn=0, equality=0, symmetry=0, max_lits=2.
% 1.68/1.88
% 1.68/1.88 This is a non-Horn set without equality. The strategy will
% 1.68/1.88 be ordered hyper_res, unit deletion, and factoring, with
% 1.68/1.88 satellites in sos and with nuclei in usable.
% 1.68/1.88
% 1.68/1.88 dependent: set(hyper_res).
% 1.68/1.88 dependent: set(factor).
% 1.68/1.88 dependent: set(unit_deletion).
% 1.68/1.88
% 1.68/1.88 ------------> process usable:
% 1.68/1.88 ** KEPT (pick-wt=6): 1 [] -element(A,$c1)|element(A,A).
% 1.68/1.88 ** KEPT (pick-wt=6): 2 [] element(A,$c1)| -element(A,A).
% 1.68/1.88 ** KEPT (pick-wt=7): 3 [] -element(A,$f1(B))| -element(A,B).
% 1.68/1.88
% 1.68/1.88 ------------> process sos:
% 1.68/1.88 ** KEPT (pick-wt=7): 4 [] element(A,$f1(B))|element(A,B).
% 1.68/1.88
% 1.68/1.88 ======= end of input processing =======
% 1.68/1.88
% 1.68/1.88 =========== start of search ===========
% 1.68/1.88
% 1.68/1.88 -------- PROOF --------
% 1.68/1.88
% 1.68/1.88 -----> EMPTY CLAUSE at 0.00 sec ----> 13 [hyper,10,3,9] $F.
% 1.68/1.88
% 1.68/1.88 Length of proof is 4. Level of proof is 2.
% 1.68/1.88
% 1.68/1.88 ---------------- PROOF ----------------
% 1.68/1.88 % SZS status Theorem
% 1.68/1.88 % SZS output start Refutation
% See solution above
% 1.68/1.88 ------------ end of proof -------------
% 1.68/1.88
% 1.68/1.88
% 1.68/1.88 Search stopped by max_proofs option.
% 1.68/1.88
% 1.68/1.88
% 1.68/1.88 Search stopped by max_proofs option.
% 1.68/1.88
% 1.68/1.88 ============ end of search ============
% 1.68/1.88
% 1.68/1.88 -------------- statistics -------------
% 1.68/1.88 clauses given 3
% 1.68/1.88 clauses generated 19
% 1.68/1.88 clauses kept 12
% 1.68/1.88 clauses forward subsumed 10
% 1.68/1.88 clauses back subsumed 0
% 1.68/1.88 Kbytes malloced 976
% 1.68/1.88
% 1.68/1.88 ----------- times (seconds) -----------
% 1.68/1.88 user CPU time 0.00 (0 hr, 0 min, 0 sec)
% 1.68/1.88 system CPU time 0.00 (0 hr, 0 min, 0 sec)
% 1.68/1.88 wall-clock time 1 (0 hr, 0 min, 1 sec)
% 1.68/1.88
% 1.68/1.88 That finishes the proof of the theorem.
% 1.68/1.88
% 1.68/1.88 Process 26871 finished Wed Jul 27 10:47:39 2022
% 1.68/1.88 Otter interrupted
% 1.68/1.88 PROOF FOUND
%------------------------------------------------------------------------------