TSTP Solution File: SET043+1 by Duper---1.0

View Problem - Process Solution

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% File     : Duper---1.0
% Problem  : SET043+1 : TPTP v8.1.2. Released v2.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n004.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 14:45:16 EDT 2023

% Result   : Theorem 3.32s 3.57s
% Output   : Proof 3.32s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.13  % Problem    : SET043+1 : TPTP v8.1.2. Released v2.0.0.
% 0.00/0.14  % Command    : duper %s
% 0.15/0.34  % Computer : n004.cluster.edu
% 0.15/0.34  % Model    : x86_64 x86_64
% 0.15/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.15/0.34  % Memory   : 8042.1875MB
% 0.15/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.15/0.34  % CPULimit   : 300
% 0.15/0.34  % WCLimit    : 300
% 0.15/0.34  % DateTime   : Sat Aug 26 08:56:52 EDT 2023
% 0.15/0.34  % CPUTime    : 
% 3.32/3.57  SZS status Theorem for theBenchmark.p
% 3.32/3.57  SZS output start Proof for theBenchmark.p
% 3.32/3.57  Clause #0 (by assumption #[]): Eq (Not (Not (Exists fun X => ∀ (Y : Iota), Iff (element Y X) (Not (element Y Y))))) True
% 3.32/3.57  Clause #1 (by clausification #[0]): Eq (Not (Exists fun X => ∀ (Y : Iota), Iff (element Y X) (Not (element Y Y)))) False
% 3.32/3.57  Clause #2 (by clausification #[1]): Eq (Exists fun X => ∀ (Y : Iota), Iff (element Y X) (Not (element Y Y))) True
% 3.32/3.57  Clause #3 (by clausification #[2]): ∀ (a : Iota), Eq (∀ (Y : Iota), Iff (element Y (skS.0 0 a)) (Not (element Y Y))) True
% 3.32/3.57  Clause #4 (by clausification #[3]): ∀ (a a_1 : Iota), Eq (Iff (element a (skS.0 0 a_1)) (Not (element a a))) True
% 3.32/3.57  Clause #5 (by clausification #[4]): ∀ (a a_1 : Iota), Or (Eq (element a (skS.0 0 a_1)) True) (Eq (Not (element a a)) False)
% 3.32/3.57  Clause #6 (by clausification #[4]): ∀ (a a_1 : Iota), Or (Eq (element a (skS.0 0 a_1)) False) (Eq (Not (element a a)) True)
% 3.32/3.57  Clause #7 (by clausification #[5]): ∀ (a a_1 : Iota), Or (Eq (element a (skS.0 0 a_1)) True) (Eq (element a a) True)
% 3.32/3.57  Clause #8 (by equality factoring #[7]): ∀ (a : Iota), Or (Ne True True) (Eq (element (skS.0 0 a) (skS.0 0 a)) True)
% 3.32/3.57  Clause #9 (by clausification #[6]): ∀ (a a_1 : Iota), Or (Eq (element a (skS.0 0 a_1)) False) (Eq (element a a) False)
% 3.32/3.57  Clause #13 (by clausification #[8]): ∀ (a : Iota), Or (Eq (element (skS.0 0 a) (skS.0 0 a)) True) (Or (Eq True False) (Eq True False))
% 3.32/3.57  Clause #15 (by clausification #[13]): ∀ (a : Iota), Or (Eq (element (skS.0 0 a) (skS.0 0 a)) True) (Eq True False)
% 3.32/3.57  Clause #16 (by clausification #[15]): ∀ (a : Iota), Eq (element (skS.0 0 a) (skS.0 0 a)) True
% 3.32/3.57  Clause #17 (by superposition #[16, 9]): Or (Eq True False) (Eq True False)
% 3.32/3.57  Clause #18 (by clausification #[17]): Eq True False
% 3.32/3.57  Clause #19 (by clausification #[18]): False
% 3.32/3.57  SZS output end Proof for theBenchmark.p
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