TSTP Solution File: SET027+3 by Bliksem---1.12

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Bliksem---1.12
% Problem  : SET027+3 : TPTP v8.1.0. Released v2.2.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : bliksem %s

% Computer : n021.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 0s
% DateTime : Mon Jul 18 22:45:44 EDT 2022

% Result   : Theorem 0.72s 1.10s
% Output   : Refutation 0.72s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.13  % Problem  : SET027+3 : TPTP v8.1.0. Released v2.2.0.
% 0.13/0.14  % Command  : bliksem %s
% 0.14/0.35  % Computer : n021.cluster.edu
% 0.14/0.35  % Model    : x86_64 x86_64
% 0.14/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.35  % Memory   : 8042.1875MB
% 0.14/0.35  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.14/0.35  % CPULimit : 300
% 0.14/0.35  % DateTime : Sun Jul 10 04:38:52 EDT 2022
% 0.14/0.35  % CPUTime  : 
% 0.72/1.10  *** allocated 10000 integers for termspace/termends
% 0.72/1.10  *** allocated 10000 integers for clauses
% 0.72/1.10  *** allocated 10000 integers for justifications
% 0.72/1.10  Bliksem 1.12
% 0.72/1.10  
% 0.72/1.10  
% 0.72/1.10  Automatic Strategy Selection
% 0.72/1.10  
% 0.72/1.10  
% 0.72/1.10  Clauses:
% 0.72/1.10  
% 0.72/1.10  { ! subset( X, Y ), ! member( Z, X ), member( Z, Y ) }.
% 0.72/1.10  { ! member( skol1( Z, Y ), Y ), subset( X, Y ) }.
% 0.72/1.10  { member( skol1( X, Y ), X ), subset( X, Y ) }.
% 0.72/1.10  { subset( X, X ) }.
% 0.72/1.10  { subset( skol2, skol4 ) }.
% 0.72/1.10  { subset( skol4, skol3 ) }.
% 0.72/1.10  { ! subset( skol2, skol3 ) }.
% 0.72/1.10  
% 0.72/1.10  percentage equality = 0.000000, percentage horn = 0.857143
% 0.72/1.10  This a non-horn, non-equality problem
% 0.72/1.10  
% 0.72/1.10  
% 0.72/1.10  Options Used:
% 0.72/1.10  
% 0.72/1.10  useres =            1
% 0.72/1.10  useparamod =        0
% 0.72/1.10  useeqrefl =         0
% 0.72/1.10  useeqfact =         0
% 0.72/1.10  usefactor =         1
% 0.72/1.10  usesimpsplitting =  0
% 0.72/1.10  usesimpdemod =      0
% 0.72/1.10  usesimpres =        3
% 0.72/1.10  
% 0.72/1.10  resimpinuse      =  1000
% 0.72/1.10  resimpclauses =     20000
% 0.72/1.10  substype =          standard
% 0.72/1.10  backwardsubs =      1
% 0.72/1.10  selectoldest =      5
% 0.72/1.10  
% 0.72/1.10  litorderings [0] =  split
% 0.72/1.10  litorderings [1] =  liftord
% 0.72/1.10  
% 0.72/1.10  termordering =      none
% 0.72/1.10  
% 0.72/1.10  litapriori =        1
% 0.72/1.10  termapriori =       0
% 0.72/1.10  litaposteriori =    0
% 0.72/1.10  termaposteriori =   0
% 0.72/1.10  demodaposteriori =  0
% 0.72/1.10  ordereqreflfact =   0
% 0.72/1.10  
% 0.72/1.10  litselect =         none
% 0.72/1.10  
% 0.72/1.10  maxweight =         15
% 0.72/1.10  maxdepth =          30000
% 0.72/1.10  maxlength =         115
% 0.72/1.10  maxnrvars =         195
% 0.72/1.10  excuselevel =       1
% 0.72/1.10  increasemaxweight = 1
% 0.72/1.10  
% 0.72/1.10  maxselected =       10000000
% 0.72/1.10  maxnrclauses =      10000000
% 0.72/1.10  
% 0.72/1.10  showgenerated =    0
% 0.72/1.10  showkept =         0
% 0.72/1.10  showselected =     0
% 0.72/1.10  showdeleted =      0
% 0.72/1.10  showresimp =       1
% 0.72/1.10  showstatus =       2000
% 0.72/1.10  
% 0.72/1.10  prologoutput =     0
% 0.72/1.10  nrgoals =          5000000
% 0.72/1.10  totalproof =       1
% 0.72/1.10  
% 0.72/1.10  Symbols occurring in the translation:
% 0.72/1.10  
% 0.72/1.10  {}  [0, 0]      (w:1, o:2, a:1, s:1, b:0), 
% 0.72/1.10  .  [1, 2]      (w:1, o:17, a:1, s:1, b:0), 
% 0.72/1.10  !  [4, 1]      (w:0, o:12, a:1, s:1, b:0), 
% 0.72/1.10  =  [13, 2]      (w:1, o:0, a:0, s:1, b:0), 
% 0.72/1.10  ==>  [14, 2]      (w:1, o:0, a:0, s:1, b:0), 
% 0.72/1.10  subset  [37, 2]      (w:1, o:41, a:1, s:1, b:0), 
% 0.72/1.10  member  [39, 2]      (w:1, o:42, a:1, s:1, b:0), 
% 0.72/1.10  skol1  [40, 2]      (w:1, o:43, a:1, s:1, b:0), 
% 0.72/1.10  skol2  [41, 0]      (w:1, o:9, a:1, s:1, b:0), 
% 0.72/1.10  skol3  [42, 0]      (w:1, o:10, a:1, s:1, b:0), 
% 0.72/1.10  skol4  [43, 0]      (w:1, o:11, a:1, s:1, b:0).
% 0.72/1.10  
% 0.72/1.10  
% 0.72/1.10  Starting Search:
% 0.72/1.10  
% 0.72/1.10  
% 0.72/1.10  Bliksems!, er is een bewijs:
% 0.72/1.10  % SZS status Theorem
% 0.72/1.10  % SZS output start Refutation
% 0.72/1.10  
% 0.72/1.10  (0) {G0,W9,D2,L3,V3,M2} I { ! subset( X, Y ), member( Z, Y ), ! member( Z, 
% 0.72/1.10    X ) }.
% 0.72/1.10  (1) {G0,W8,D3,L2,V3,M1} I { subset( X, Y ), ! member( skol1( Z, Y ), Y )
% 0.72/1.10     }.
% 0.72/1.10  (2) {G0,W8,D3,L2,V2,M1} I { subset( X, Y ), member( skol1( X, Y ), X ) }.
% 0.72/1.10  (4) {G0,W3,D2,L1,V0,M1} I { subset( skol2, skol4 ) }.
% 0.72/1.10  (5) {G0,W3,D2,L1,V0,M1} I { subset( skol4, skol3 ) }.
% 0.72/1.10  (6) {G0,W3,D2,L1,V0,M1} I { ! subset( skol2, skol3 ) }.
% 0.72/1.10  (8) {G1,W11,D3,L3,V4,M1} R(0,1) { ! subset( X, Y ), subset( T, Y ), ! 
% 0.72/1.10    member( skol1( Z, Y ), X ) }.
% 0.72/1.10  (9) {G1,W11,D3,L3,V3,M1} R(2,0) { subset( X, Y ), ! subset( X, Z ), member
% 0.72/1.10    ( skol1( X, Y ), Z ) }.
% 0.72/1.10  (11) {G2,W12,D2,L4,V4,M4} R(9,8) { ! subset( X, Z ), ! subset( Z, Y ), 
% 0.72/1.10    subset( T, Y ), subset( X, Y ) }.
% 0.72/1.10  (13) {G3,W9,D2,L3,V3,M3} F(11) { ! subset( Y, Z ), subset( X, Z ), ! subset
% 0.72/1.10    ( X, Y ) }.
% 0.72/1.10  (16) {G4,W6,D2,L2,V1,M1} R(13,4) { subset( skol2, X ), ! subset( skol4, X )
% 0.72/1.10     }.
% 0.72/1.10  (24) {G5,W0,D0,L0,V0,M0} R(16,5);r(6) {  }.
% 0.72/1.10  
% 0.72/1.10  
% 0.72/1.10  % SZS output end Refutation
% 0.72/1.10  found a proof!
% 0.72/1.10  
% 0.72/1.10  
% 0.72/1.10  Unprocessed initial clauses:
% 0.72/1.10  
% 0.72/1.10  (26) {G0,W9,D2,L3,V3,M3}  { ! subset( X, Y ), ! member( Z, X ), member( Z, 
% 0.72/1.10    Y ) }.
% 0.72/1.10  (27) {G0,W8,D3,L2,V3,M2}  { ! member( skol1( Z, Y ), Y ), subset( X, Y )
% 0.72/1.10     }.
% 0.72/1.10  (28) {G0,W8,D3,L2,V2,M2}  { member( skol1( X, Y ), X ), subset( X, Y ) }.
% 0.72/1.10  (29) {G0,W3,D2,L1,V1,M1}  { subset( X, X ) }.
% 0.72/1.10  (30) {G0,W3,D2,L1,V0,M1}  { subset( skol2, skol4 ) }.
% 0.72/1.10  (31) {G0,W3,D2,L1,V0,M1}  { subset( skol4, skol3 ) }.
% 0.72/1.10  (32) {G0,W3,D2,L1,V0,M1}  { ! subset( skol2, skol3 ) }.
% 0.72/1.10  
% 0.72/1.10  
% 0.72/1.10  Total Proof:
% 0.72/1.10  
% 0.72/1.10  subsumption: (0) {G0,W9,D2,L3,V3,M2} I { ! subset( X, Y ), member( Z, Y ), 
% 0.72/1.10    ! member( Z, X ) }.
% 0.72/1.10  parent0: (26) {G0,W9,D2,L3,V3,M3}  { ! subset( X, Y ), ! member( Z, X ), 
% 0.72/1.10    member( Z, Y ) }.
% 0.72/1.10  substitution0:
% 0.72/1.10     X := X
% 0.72/1.10     Y := Y
% 0.72/1.10     Z := Z
% 0.72/1.10  end
% 0.72/1.10  permutation0:
% 0.72/1.10     0 ==> 0
% 0.72/1.10     1 ==> 2
% 0.72/1.10     2 ==> 1
% 0.72/1.10  end
% 0.72/1.10  
% 0.72/1.10  subsumption: (1) {G0,W8,D3,L2,V3,M1} I { subset( X, Y ), ! member( skol1( Z
% 0.72/1.10    , Y ), Y ) }.
% 0.72/1.10  parent0: (27) {G0,W8,D3,L2,V3,M2}  { ! member( skol1( Z, Y ), Y ), subset( 
% 0.72/1.10    X, Y ) }.
% 0.72/1.10  substitution0:
% 0.72/1.10     X := X
% 0.72/1.10     Y := Y
% 0.72/1.10     Z := Z
% 0.72/1.10  end
% 0.72/1.10  permutation0:
% 0.72/1.10     0 ==> 1
% 0.72/1.10     1 ==> 0
% 0.72/1.10  end
% 0.72/1.10  
% 0.72/1.10  subsumption: (2) {G0,W8,D3,L2,V2,M1} I { subset( X, Y ), member( skol1( X, 
% 0.72/1.10    Y ), X ) }.
% 0.72/1.10  parent0: (28) {G0,W8,D3,L2,V2,M2}  { member( skol1( X, Y ), X ), subset( X
% 0.72/1.10    , Y ) }.
% 0.72/1.10  substitution0:
% 0.72/1.10     X := X
% 0.72/1.10     Y := Y
% 0.72/1.10  end
% 0.72/1.10  permutation0:
% 0.72/1.10     0 ==> 1
% 0.72/1.10     1 ==> 0
% 0.72/1.10  end
% 0.72/1.10  
% 0.72/1.10  subsumption: (4) {G0,W3,D2,L1,V0,M1} I { subset( skol2, skol4 ) }.
% 0.72/1.10  parent0: (30) {G0,W3,D2,L1,V0,M1}  { subset( skol2, skol4 ) }.
% 0.72/1.10  substitution0:
% 0.72/1.10  end
% 0.72/1.10  permutation0:
% 0.72/1.10     0 ==> 0
% 0.72/1.10  end
% 0.72/1.10  
% 0.72/1.10  subsumption: (5) {G0,W3,D2,L1,V0,M1} I { subset( skol4, skol3 ) }.
% 0.72/1.10  parent0: (31) {G0,W3,D2,L1,V0,M1}  { subset( skol4, skol3 ) }.
% 0.72/1.10  substitution0:
% 0.72/1.10  end
% 0.72/1.10  permutation0:
% 0.72/1.10     0 ==> 0
% 0.72/1.10  end
% 0.72/1.10  
% 0.72/1.10  subsumption: (6) {G0,W3,D2,L1,V0,M1} I { ! subset( skol2, skol3 ) }.
% 0.72/1.10  parent0: (32) {G0,W3,D2,L1,V0,M1}  { ! subset( skol2, skol3 ) }.
% 0.72/1.10  substitution0:
% 0.72/1.10  end
% 0.72/1.10  permutation0:
% 0.72/1.10     0 ==> 0
% 0.72/1.10  end
% 0.72/1.10  
% 0.72/1.10  resolution: (35) {G1,W11,D3,L3,V4,M3}  { subset( X, Y ), ! subset( T, Y ), 
% 0.72/1.10    ! member( skol1( Z, Y ), T ) }.
% 0.72/1.10  parent0[1]: (1) {G0,W8,D3,L2,V3,M1} I { subset( X, Y ), ! member( skol1( Z
% 0.72/1.10    , Y ), Y ) }.
% 0.72/1.10  parent1[1]: (0) {G0,W9,D2,L3,V3,M2} I { ! subset( X, Y ), member( Z, Y ), !
% 0.72/1.10     member( Z, X ) }.
% 0.72/1.10  substitution0:
% 0.72/1.10     X := X
% 0.72/1.10     Y := Y
% 0.72/1.10     Z := Z
% 0.72/1.10  end
% 0.72/1.10  substitution1:
% 0.72/1.10     X := T
% 0.72/1.10     Y := Y
% 0.72/1.10     Z := skol1( Z, Y )
% 0.72/1.10  end
% 0.72/1.10  
% 0.72/1.10  subsumption: (8) {G1,W11,D3,L3,V4,M1} R(0,1) { ! subset( X, Y ), subset( T
% 0.72/1.10    , Y ), ! member( skol1( Z, Y ), X ) }.
% 0.72/1.10  parent0: (35) {G1,W11,D3,L3,V4,M3}  { subset( X, Y ), ! subset( T, Y ), ! 
% 0.72/1.10    member( skol1( Z, Y ), T ) }.
% 0.72/1.10  substitution0:
% 0.72/1.10     X := T
% 0.72/1.10     Y := Y
% 0.72/1.10     Z := Z
% 0.72/1.10     T := X
% 0.72/1.10  end
% 0.72/1.10  permutation0:
% 0.72/1.10     0 ==> 1
% 0.72/1.10     1 ==> 0
% 0.72/1.10     2 ==> 2
% 0.72/1.10  end
% 0.72/1.10  
% 0.72/1.10  resolution: (37) {G1,W11,D3,L3,V3,M3}  { ! subset( X, Y ), member( skol1( X
% 0.72/1.10    , Z ), Y ), subset( X, Z ) }.
% 0.72/1.10  parent0[2]: (0) {G0,W9,D2,L3,V3,M2} I { ! subset( X, Y ), member( Z, Y ), !
% 0.72/1.10     member( Z, X ) }.
% 0.72/1.10  parent1[1]: (2) {G0,W8,D3,L2,V2,M1} I { subset( X, Y ), member( skol1( X, Y
% 0.72/1.10     ), X ) }.
% 0.72/1.10  substitution0:
% 0.72/1.10     X := X
% 0.72/1.10     Y := Y
% 0.72/1.10     Z := skol1( X, Z )
% 0.72/1.10  end
% 0.72/1.10  substitution1:
% 0.72/1.10     X := X
% 0.72/1.10     Y := Z
% 0.72/1.10  end
% 0.72/1.10  
% 0.72/1.10  subsumption: (9) {G1,W11,D3,L3,V3,M1} R(2,0) { subset( X, Y ), ! subset( X
% 0.72/1.10    , Z ), member( skol1( X, Y ), Z ) }.
% 0.72/1.10  parent0: (37) {G1,W11,D3,L3,V3,M3}  { ! subset( X, Y ), member( skol1( X, Z
% 0.72/1.10     ), Y ), subset( X, Z ) }.
% 0.72/1.10  substitution0:
% 0.72/1.10     X := X
% 0.72/1.10     Y := Z
% 0.72/1.10     Z := Y
% 0.72/1.10  end
% 0.72/1.10  permutation0:
% 0.72/1.10     0 ==> 1
% 0.72/1.10     1 ==> 2
% 0.72/1.10     2 ==> 0
% 0.72/1.10  end
% 0.72/1.10  
% 0.72/1.10  resolution: (41) {G2,W12,D2,L4,V4,M4}  { ! subset( X, Y ), subset( Z, Y ), 
% 0.72/1.10    subset( T, Y ), ! subset( T, X ) }.
% 0.72/1.10  parent0[2]: (8) {G1,W11,D3,L3,V4,M1} R(0,1) { ! subset( X, Y ), subset( T, 
% 0.72/1.10    Y ), ! member( skol1( Z, Y ), X ) }.
% 0.72/1.10  parent1[2]: (9) {G1,W11,D3,L3,V3,M1} R(2,0) { subset( X, Y ), ! subset( X, 
% 0.72/1.10    Z ), member( skol1( X, Y ), Z ) }.
% 0.72/1.10  substitution0:
% 0.72/1.10     X := X
% 0.72/1.10     Y := Y
% 0.72/1.10     Z := T
% 0.72/1.10     T := Z
% 0.72/1.10  end
% 0.72/1.10  substitution1:
% 0.72/1.10     X := T
% 0.72/1.10     Y := Y
% 0.72/1.10     Z := X
% 0.72/1.10  end
% 0.72/1.10  
% 0.72/1.10  subsumption: (11) {G2,W12,D2,L4,V4,M4} R(9,8) { ! subset( X, Z ), ! subset
% 0.72/1.10    ( Z, Y ), subset( T, Y ), subset( X, Y ) }.
% 0.72/1.10  parent0: (41) {G2,W12,D2,L4,V4,M4}  { ! subset( X, Y ), subset( Z, Y ), 
% 0.72/1.10    subset( T, Y ), ! subset( T, X ) }.
% 0.72/1.10  substitution0:
% 0.72/1.10     X := Z
% 0.72/1.10     Y := Y
% 0.72/1.10     Z := T
% 0.72/1.10     T := X
% 0.72/1.10  end
% 0.72/1.10  permutation0:
% 0.72/1.10     0 ==> 1
% 0.72/1.10     1 ==> 2
% 0.72/1.10     2 ==> 3
% 0.72/1.10     3 ==> 0
% 0.72/1.10  end
% 0.72/1.10  
% 0.72/1.10  factor: (46) {G2,W9,D2,L3,V3,M3}  { ! subset( X, Y ), ! subset( Y, Z ), 
% 0.72/1.10    subset( X, Z ) }.
% 0.72/1.10  parent0[2, 3]: (11) {G2,W12,D2,L4,V4,M4} R(9,8) { ! subset( X, Z ), ! 
% 0.72/1.10    subset( Z, Y ), subset( T, Y ), subset( X, Y ) }.
% 0.72/1.10  substitution0:
% 0.72/1.10     X := X
% 0.72/1.10     Y := Z
% 0.72/1.10     Z := Y
% 0.72/1.10     T := X
% 0.72/1.10  end
% 0.72/1.10  
% 0.72/1.10  subsumption: (13) {G3,W9,D2,L3,V3,M3} F(11) { ! subset( Y, Z ), subset( X, 
% 0.72/1.10    Z ), ! subset( X, Y ) }.
% 0.72/1.10  parent0: (46) {G2,W9,D2,L3,V3,M3}  { ! subset( X, Y ), ! subset( Y, Z ), 
% 0.72/1.10    subset( X, Z ) }.
% 0.72/1.10  substitution0:
% 0.72/1.10     X := X
% 0.72/1.10     Y := Y
% 0.72/1.10     Z := Z
% 0.72/1.10  end
% 0.72/1.10  permutation0:
% 0.72/1.10     0 ==> 2
% 0.72/1.10     1 ==> 0
% 0.72/1.10     2 ==> 1
% 0.72/1.10  end
% 0.72/1.10  
% 0.72/1.10  resolution: (49) {G1,W6,D2,L2,V1,M2}  { ! subset( skol4, X ), subset( skol2
% 0.72/1.10    , X ) }.
% 0.72/1.10  parent0[2]: (13) {G3,W9,D2,L3,V3,M3} F(11) { ! subset( Y, Z ), subset( X, Z
% 0.72/1.10     ), ! subset( X, Y ) }.
% 0.72/1.10  parent1[0]: (4) {G0,W3,D2,L1,V0,M1} I { subset( skol2, skol4 ) }.
% 0.72/1.10  substitution0:
% 0.72/1.10     X := skol2
% 0.72/1.10     Y := skol4
% 0.72/1.10     Z := X
% 0.72/1.10  end
% 0.72/1.10  substitution1:
% 0.72/1.10  end
% 0.72/1.10  
% 0.72/1.10  subsumption: (16) {G4,W6,D2,L2,V1,M1} R(13,4) { subset( skol2, X ), ! 
% 0.72/1.10    subset( skol4, X ) }.
% 0.72/1.10  parent0: (49) {G1,W6,D2,L2,V1,M2}  { ! subset( skol4, X ), subset( skol2, X
% 0.72/1.10     ) }.
% 0.72/1.10  substitution0:
% 0.72/1.10     X := X
% 0.72/1.10  end
% 0.72/1.10  permutation0:
% 0.72/1.10     0 ==> 1
% 0.72/1.10     1 ==> 0
% 0.72/1.10  end
% 0.72/1.10  
% 0.72/1.10  resolution: (50) {G1,W3,D2,L1,V0,M1}  { subset( skol2, skol3 ) }.
% 0.72/1.10  parent0[1]: (16) {G4,W6,D2,L2,V1,M1} R(13,4) { subset( skol2, X ), ! subset
% 0.72/1.10    ( skol4, X ) }.
% 0.72/1.10  parent1[0]: (5) {G0,W3,D2,L1,V0,M1} I { subset( skol4, skol3 ) }.
% 0.72/1.10  substitution0:
% 0.72/1.10     X := skol3
% 0.72/1.10  end
% 0.72/1.10  substitution1:
% 0.72/1.10  end
% 0.72/1.10  
% 0.72/1.10  resolution: (51) {G1,W0,D0,L0,V0,M0}  {  }.
% 0.72/1.10  parent0[0]: (6) {G0,W3,D2,L1,V0,M1} I { ! subset( skol2, skol3 ) }.
% 0.72/1.10  parent1[0]: (50) {G1,W3,D2,L1,V0,M1}  { subset( skol2, skol3 ) }.
% 0.72/1.10  substitution0:
% 0.72/1.10  end
% 0.72/1.10  substitution1:
% 0.72/1.10  end
% 0.72/1.10  
% 0.72/1.10  subsumption: (24) {G5,W0,D0,L0,V0,M0} R(16,5);r(6) {  }.
% 0.72/1.10  parent0: (51) {G1,W0,D0,L0,V0,M0}  {  }.
% 0.72/1.10  substitution0:
% 0.72/1.10  end
% 0.72/1.10  permutation0:
% 0.72/1.10  end
% 0.72/1.10  
% 0.72/1.10  Proof check complete!
% 0.72/1.10  
% 0.72/1.10  Memory use:
% 0.72/1.10  
% 0.72/1.10  space for terms:        342
% 0.72/1.10  space for clauses:      1134
% 0.72/1.10  
% 0.72/1.10  
% 0.72/1.10  clauses generated:      55
% 0.72/1.10  clauses kept:           25
% 0.72/1.10  clauses selected:       13
% 0.72/1.10  clauses deleted:        0
% 0.72/1.10  clauses inuse deleted:  0
% 0.72/1.10  
% 0.72/1.10  subsentry:          107
% 0.72/1.10  literals s-matched: 70
% 0.72/1.10  literals matched:   68
% 0.72/1.10  full subsumption:   56
% 0.72/1.10  
% 0.72/1.10  checksum:           142610873
% 0.72/1.10  
% 0.72/1.10  
% 0.72/1.10  Bliksem ended
%------------------------------------------------------------------------------