TSTP Solution File: SET020+1 by SPASS---3.9
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%------------------------------------------------------------------------------
% File : SPASS---3.9
% Problem : SET020+1 : TPTP v8.1.0. Bugfixed v5.4.0.
% Transfm : none
% Format : tptp
% Command : run_spass %d %s
% Computer : n025.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Tue Jul 19 05:22:41 EDT 2022
% Result : Theorem 0.20s 0.48s
% Output : Refutation 0.20s
% Verified :
% SZS Type : Refutation
% Derivation depth : 6
% Number of leaves : 5
% Syntax : Number of clauses : 13 ( 7 unt; 0 nHn; 13 RR)
% Number of literals : 21 ( 0 equ; 12 neg)
% Maximal clause size : 3 ( 1 avg)
% Maximal term depth : 3 ( 1 avg)
% Number of predicates : 3 ( 2 usr; 1 prp; 0-2 aty)
% Number of functors : 8 ( 8 usr; 5 con; 0-2 aty)
% Number of variables : 0 ( 0 sgn)
% Comments :
%------------------------------------------------------------------------------
cnf(3,axiom,
member(skc5,universal_class),
file('SET020+1.p',unknown),
[] ).
cnf(4,axiom,
member(skc4,universal_class),
file('SET020+1.p',unknown),
[] ).
cnf(78,axiom,
( ~ equal(first(ordered_pair(skc5,skc4)),skc5)
| ~ equal(second(ordered_pair(skc5,skc4)),skc4) ),
file('SET020+1.p',unknown),
[] ).
cnf(79,axiom,
( ~ member(u,universal_class)
| ~ member(v,universal_class)
| equal(first(ordered_pair(v,u)),v) ),
file('SET020+1.p',unknown),
[] ).
cnf(80,axiom,
( ~ member(u,universal_class)
| ~ member(v,universal_class)
| equal(second(ordered_pair(v,u)),u) ),
file('SET020+1.p',unknown),
[] ).
cnf(106,plain,
( ~ member(u,universal_class)
| equal(first(ordered_pair(u,skc4)),u) ),
inference(res,[status(thm),theory(equality)],[4,79]),
[iquote('0:Res:4.0,79.1')] ).
cnf(107,plain,
( ~ member(u,universal_class)
| equal(second(ordered_pair(u,skc4)),skc4) ),
inference(res,[status(thm),theory(equality)],[4,80]),
[iquote('0:Res:4.0,80.1')] ).
cnf(163,plain,
equal(second(ordered_pair(skc5,skc4)),skc4),
inference(res,[status(thm),theory(equality)],[3,107]),
[iquote('0:Res:3.0,107.0')] ).
cnf(164,plain,
equal(first(ordered_pair(skc5,skc4)),skc5),
inference(res,[status(thm),theory(equality)],[3,106]),
[iquote('0:Res:3.0,106.0')] ).
cnf(195,plain,
( ~ equal(first(ordered_pair(skc5,skc4)),skc5)
| ~ equal(skc4,skc4) ),
inference(rew,[status(thm),theory(equality)],[163,78]),
[iquote('0:Rew:163.0,78.1')] ).
cnf(196,plain,
~ equal(first(ordered_pair(skc5,skc4)),skc5),
inference(obv,[status(thm),theory(equality)],[195]),
[iquote('0:Obv:195.1')] ).
cnf(197,plain,
~ equal(skc5,skc5),
inference(rew,[status(thm),theory(equality)],[164,196]),
[iquote('0:Rew:164.0,196.0')] ).
cnf(198,plain,
$false,
inference(obv,[status(thm),theory(equality)],[197]),
[iquote('0:Obv:197.0')] ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.12 % Problem : SET020+1 : TPTP v8.1.0. Bugfixed v5.4.0.
% 0.03/0.13 % Command : run_spass %d %s
% 0.14/0.34 % Computer : n025.cluster.edu
% 0.14/0.34 % Model : x86_64 x86_64
% 0.14/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.34 % Memory : 8042.1875MB
% 0.14/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.14/0.34 % CPULimit : 300
% 0.14/0.34 % WCLimit : 600
% 0.14/0.34 % DateTime : Mon Jul 11 01:32:47 EDT 2022
% 0.14/0.34 % CPUTime :
% 0.20/0.48
% 0.20/0.48 SPASS V 3.9
% 0.20/0.48 SPASS beiseite: Proof found.
% 0.20/0.48 % SZS status Theorem
% 0.20/0.48 Problem: /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.20/0.48 SPASS derived 103 clauses, backtracked 0 clauses, performed 0 splits and kept 173 clauses.
% 0.20/0.48 SPASS allocated 98319 KBytes.
% 0.20/0.48 SPASS spent 0:00:00.13 on the problem.
% 0.20/0.48 0:00:00.04 for the input.
% 0.20/0.48 0:00:00.06 for the FLOTTER CNF translation.
% 0.20/0.48 0:00:00.00 for inferences.
% 0.20/0.48 0:00:00.00 for the backtracking.
% 0.20/0.48 0:00:00.00 for the reduction.
% 0.20/0.48
% 0.20/0.48
% 0.20/0.48 Here is a proof with depth 2, length 13 :
% 0.20/0.48 % SZS output start Refutation
% See solution above
% 0.20/0.48 Formulae used in the proof : unique_1st_and_2nd_in_pair_of_sets1 first_second
% 0.20/0.48
%------------------------------------------------------------------------------