TSTP Solution File: SET019+4 by Metis---2.4

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%------------------------------------------------------------------------------
% File     : Metis---2.4
% Problem  : SET019+4 : TPTP v8.1.0. Released v2.2.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : metis --show proof --show saturation %s

% Computer : n008.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Tue Jul 19 03:31:19 EDT 2022

% Result   : Theorem 0.12s 0.35s
% Output   : CNFRefutation 0.12s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    5
%            Number of leaves      :    2
% Syntax   : Number of formulae    :    9 (   2 unt;   0 def)
%            Number of atoms       :   23 (   0 equ)
%            Maximal formula atoms :    3 (   2 avg)
%            Number of connectives :   22 (   8   ~;   2   |;   6   &)
%                                         (   3 <=>;   3  =>;   0  <=;   0 <~>)
%            Maximal formula depth :    6 (   4 avg)
%            Maximal term depth    :    1 (   1 avg)
%            Number of predicates  :    3 (   2 usr;   1 prp; 0-2 aty)
%            Number of functors    :    0 (   0 usr;   0 con; --- aty)
%            Number of variables   :   14 (   0 sgn  12   !;   2   ?)

% Comments : 
%------------------------------------------------------------------------------
fof(equal_set,axiom,
    ! [A,B] :
      ( equal_set(A,B)
    <=> ( subset(A,B)
        & subset(B,A) ) ) ).

fof(thI02,conjecture,
    ! [A,B] :
      ( ( subset(A,B)
        & subset(B,A) )
     => equal_set(A,B) ) ).

fof(subgoal_0,plain,
    ! [A,B] :
      ( ( subset(A,B)
        & subset(B,A) )
     => equal_set(A,B) ),
    inference(strip,[],[thI02]) ).

fof(negate_0_0,plain,
    ~ ! [A,B] :
        ( ( subset(A,B)
          & subset(B,A) )
       => equal_set(A,B) ),
    inference(negate,[],[subgoal_0]) ).

fof(normalize_0_0,plain,
    ? [A,B] :
      ( ~ equal_set(A,B)
      & subset(A,B)
      & subset(B,A) ),
    inference(canonicalize,[],[negate_0_0]) ).

fof(normalize_0_1,plain,
    ! [A,B] :
      ( ~ equal_set(A,B)
    <=> ( ~ subset(A,B)
        | ~ subset(B,A) ) ),
    inference(canonicalize,[],[equal_set]) ).

fof(normalize_0_2,plain,
    ! [A,B] :
      ( ~ equal_set(A,B)
    <=> ( ~ subset(A,B)
        | ~ subset(B,A) ) ),
    inference(specialize,[],[normalize_0_1]) ).

fof(normalize_0_3,plain,
    $false,
    inference(simplify,[],[normalize_0_0,normalize_0_2]) ).

cnf(refute_0_0,plain,
    $false,
    inference(canonicalize,[],[normalize_0_3]) ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.12  % Problem  : SET019+4 : TPTP v8.1.0. Released v2.2.0.
% 0.03/0.13  % Command  : metis --show proof --show saturation %s
% 0.12/0.33  % Computer : n008.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit : 300
% 0.12/0.33  % WCLimit  : 600
% 0.12/0.33  % DateTime : Mon Jul 11 08:34:53 EDT 2022
% 0.12/0.34  % CPUTime  : 
% 0.12/0.34  %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
% 0.12/0.35  % SZS status Theorem for /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.12/0.35  
% 0.12/0.35  % SZS output start CNFRefutation for /export/starexec/sandbox2/benchmark/theBenchmark.p
% See solution above
% 0.12/0.35  
%------------------------------------------------------------------------------