TSTP Solution File: SCT061-1 by Twee---2.4.2
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% File : Twee---2.4.2
% Problem : SCT061-1 : TPTP v8.1.2. Released v4.1.0.
% Transfm : none
% Format : tptp:raw
% Command : parallel-twee %s --tstp --conditional-encoding if --smaller --drop-non-horn --give-up-on-saturation --explain-encoding --formal-proof
% Computer : n010.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Thu Aug 31 14:22:00 EDT 2023
% Result : Unsatisfiable 15.63s 2.38s
% Output : Proof 15.63s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.13 % Problem : SCT061-1 : TPTP v8.1.2. Released v4.1.0.
% 0.00/0.14 % Command : parallel-twee %s --tstp --conditional-encoding if --smaller --drop-non-horn --give-up-on-saturation --explain-encoding --formal-proof
% 0.14/0.35 % Computer : n010.cluster.edu
% 0.14/0.35 % Model : x86_64 x86_64
% 0.14/0.35 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.35 % Memory : 8042.1875MB
% 0.14/0.35 % OS : Linux 3.10.0-693.el7.x86_64
% 0.14/0.35 % CPULimit : 300
% 0.14/0.35 % WCLimit : 300
% 0.14/0.35 % DateTime : Thu Aug 24 16:08:20 EDT 2023
% 0.14/0.35 % CPUTime :
% 15.63/2.38 Command-line arguments: --no-flatten-goal
% 15.63/2.38
% 15.63/2.38 % SZS status Unsatisfiable
% 15.63/2.38
% 15.63/2.38 % SZS output start Proof
% 15.63/2.38 Take the following subset of the input axioms:
% 15.63/2.38 fof(cls_A_I1_J_0, axiom, v_a____!=v_b____).
% 15.63/2.38 fof(cls_conjecture_0, negated_conjecture, v_b____=v_a____).
% 15.63/2.38
% 15.63/2.38 Now clausify the problem and encode Horn clauses using encoding 3 of
% 15.63/2.38 http://www.cse.chalmers.se/~nicsma/papers/horn.pdf.
% 15.63/2.38 We repeatedly replace C & s=t => u=v by the two clauses:
% 15.63/2.38 fresh(y, y, x1...xn) = u
% 15.63/2.38 C => fresh(s, t, x1...xn) = v
% 15.63/2.38 where fresh is a fresh function symbol and x1..xn are the free
% 15.63/2.38 variables of u and v.
% 15.63/2.38 A predicate p(X) is encoded as p(X)=true (this is sound, because the
% 15.63/2.38 input problem has no model of domain size 1).
% 15.63/2.38
% 15.63/2.38 The encoding turns the above axioms into the following unit equations and goals:
% 15.63/2.38
% 15.63/2.38 Axiom 1 (cls_conjecture_0): v_b____ = v_a____.
% 15.63/2.38
% 15.63/2.38 Goal 1 (cls_A_I1_J_0): v_a____ = v_b____.
% 15.63/2.38 Proof:
% 15.63/2.38 v_a____
% 15.63/2.38 = { by axiom 1 (cls_conjecture_0) R->L }
% 15.63/2.38 v_b____
% 15.63/2.38 % SZS output end Proof
% 15.63/2.38
% 15.63/2.38 RESULT: Unsatisfiable (the axioms are contradictory).
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