TSTP Solution File: ROB003-1 by Otter---3.3

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Otter---3.3
% Problem  : ROB003-1 : TPTP v8.1.0. Released v1.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : otter-tptp-script %s

% Computer : n003.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Wed Jul 27 13:12:21 EDT 2022

% Result   : Unsatisfiable 1.67s 1.88s
% Output   : Refutation 1.67s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    9
%            Number of leaves      :    6
% Syntax   : Number of clauses     :   24 (  24 unt;   0 nHn;   6 RR)
%            Number of literals    :   24 (  23 equ;   4 neg)
%            Maximal clause size   :    1 (   1 avg)
%            Maximal term depth    :    7 (   2 avg)
%            Number of predicates  :    2 (   0 usr;   1 prp; 0-2 aty)
%            Number of functors    :    5 (   5 usr;   3 con; 0-2 aty)
%            Number of variables   :   24 (   2 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(1,axiom,
    add(negate(add(a,negate(b))),negate(add(negate(a),negate(b)))) != b,
    file('ROB003-1.p',unknown),
    [] ).

cnf(2,axiom,
    A = A,
    file('ROB003-1.p',unknown),
    [] ).

cnf(3,axiom,
    add(A,B) = add(B,A),
    file('ROB003-1.p',unknown),
    [] ).

cnf(4,axiom,
    add(add(A,B),C) = add(A,add(B,C)),
    file('ROB003-1.p',unknown),
    [] ).

cnf(6,axiom,
    negate(add(negate(add(A,B)),negate(add(A,negate(B))))) = A,
    file('ROB003-1.p',unknown),
    [] ).

cnf(9,axiom,
    add(A,c) = c,
    file('ROB003-1.p',unknown),
    [] ).

cnf(11,plain,
    add(c,A) = c,
    inference(flip,[status(thm),theory(equality)],[inference(para_into,[status(thm),theory(equality)],[3,9])]),
    [iquote('para_into,3.1.1,8.1.1,flip.1')] ).

cnf(13,plain,
    add(negate(add(a,negate(b))),negate(add(negate(b),negate(a)))) != b,
    inference(para_from,[status(thm),theory(equality)],[3,1]),
    [iquote('para_from,3.1.1,1.1.1.2.1')] ).

cnf(18,plain,
    negate(add(negate(c),negate(c))) = c,
    inference(demod,[status(thm),theory(equality)],[inference(para_into,[status(thm),theory(equality)],[6,11]),11]),
    [iquote('para_into,6.1.1.1.1.1,10.1.1,demod,11')] ).

cnf(20,plain,
    negate(add(negate(c),negate(add(A,negate(c))))) = A,
    inference(para_into,[status(thm),theory(equality)],[6,9]),
    [iquote('para_into,6.1.1.1.1.1,8.1.1')] ).

cnf(36,plain,
    negate(add(negate(add(A,add(negate(c),negate(c)))),negate(c))) = A,
    inference(demod,[status(thm),theory(equality)],[inference(para_from,[status(thm),theory(equality)],[18,6]),9]),
    [iquote('para_from,18.1.1,6.1.1.1.2.1.2,demod,9')] ).

cnf(62,plain,
    negate(add(negate(c),negate(add(negate(c),A)))) = A,
    inference(para_into,[status(thm),theory(equality)],[20,3]),
    [iquote('para_into,20.1.1.1.2.1,3.1.1')] ).

cnf(64,plain,
    negate(add(negate(add(A,negate(c))),negate(c))) = A,
    inference(para_into,[status(thm),theory(equality)],[20,3]),
    [iquote('para_into,20.1.1.1,3.1.1')] ).

cnf(88,plain,
    negate(add(negate(c),A)) = negate(add(A,negate(c))),
    inference(para_into,[status(thm),theory(equality)],[62,20]),
    [iquote('para_into,62.1.1.1.2,20.1.1')] ).

cnf(89,plain,
    negate(add(negate(add(negate(c),A)),negate(c))) = A,
    inference(para_into,[status(thm),theory(equality)],[62,3]),
    [iquote('para_into,62.1.1.1,3.1.1')] ).

cnf(91,plain,
    negate(add(A,negate(c))) = negate(add(negate(c),A)),
    inference(flip,[status(thm),theory(equality)],[inference(copy,[status(thm)],[88])]),
    [iquote('copy,88,flip.1')] ).

cnf(98,plain,
    add(negate(add(negate(b),a)),negate(add(negate(b),negate(a)))) != b,
    inference(para_into,[status(thm),theory(equality)],[13,3]),
    [iquote('para_into,13.1.1.1.1,3.1.1')] ).

cnf(100,plain,
    negate(add(negate(add(A,add(B,negate(c)))),negate(c))) = add(A,B),
    inference(para_into,[status(thm),theory(equality)],[64,4]),
    [iquote('para_into,64.1.1.1.1.1,4.1.1')] ).

cnf(102,plain,
    add(A,negate(c)) = A,
    inference(demod,[status(thm),theory(equality)],[inference(back_demod,[status(thm)],[36]),100]),
    [iquote('back_demod,36,demod,100')] ).

cnf(106,plain,
    negate(add(negate(c),A)) = negate(A),
    inference(flip,[status(thm),theory(equality)],[inference(demod,[status(thm),theory(equality)],[inference(back_demod,[status(thm)],[91]),102])]),
    [iquote('back_demod,91,demod,102,flip.1')] ).

cnf(108,plain,
    negate(negate(A)) = A,
    inference(demod,[status(thm),theory(equality)],[inference(back_demod,[status(thm)],[89]),106,102]),
    [iquote('back_demod,89,demod,106,102')] ).

cnf(120,plain,
    add(negate(add(A,B)),negate(add(A,negate(B)))) = negate(A),
    inference(flip,[status(thm),theory(equality)],[inference(para_into,[status(thm),theory(equality)],[108,6])]),
    [iquote('para_into,107.1.1.1,6.1.1,flip.1')] ).

cnf(121,plain,
    b != b,
    inference(demod,[status(thm),theory(equality)],[inference(back_demod,[status(thm)],[98]),120,108]),
    [iquote('back_demod,98,demod,120,108')] ).

cnf(122,plain,
    $false,
    inference(binary,[status(thm)],[121,2]),
    [iquote('binary,121.1,2.1')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.10/0.11  % Problem  : ROB003-1 : TPTP v8.1.0. Released v1.0.0.
% 0.10/0.12  % Command  : otter-tptp-script %s
% 0.12/0.33  % Computer : n003.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit : 300
% 0.12/0.33  % WCLimit  : 300
% 0.12/0.33  % DateTime : Wed Jul 27 04:03:11 EDT 2022
% 0.12/0.33  % CPUTime  : 
% 1.67/1.88  ----- Otter 3.3f, August 2004 -----
% 1.67/1.88  The process was started by sandbox on n003.cluster.edu,
% 1.67/1.88  Wed Jul 27 04:03:11 2022
% 1.67/1.88  The command was "./otter".  The process ID is 30768.
% 1.67/1.88  
% 1.67/1.88  set(prolog_style_variables).
% 1.67/1.88  set(auto).
% 1.67/1.88     dependent: set(auto1).
% 1.67/1.88     dependent: set(process_input).
% 1.67/1.88     dependent: clear(print_kept).
% 1.67/1.88     dependent: clear(print_new_demod).
% 1.67/1.88     dependent: clear(print_back_demod).
% 1.67/1.88     dependent: clear(print_back_sub).
% 1.67/1.88     dependent: set(control_memory).
% 1.67/1.88     dependent: assign(max_mem, 12000).
% 1.67/1.88     dependent: assign(pick_given_ratio, 4).
% 1.67/1.88     dependent: assign(stats_level, 1).
% 1.67/1.88     dependent: assign(max_seconds, 10800).
% 1.67/1.88  clear(print_given).
% 1.67/1.88  
% 1.67/1.88  list(usable).
% 1.67/1.88  0 [] A=A.
% 1.67/1.88  0 [] add(X,Y)=add(Y,X).
% 1.67/1.88  0 [] add(add(X,Y),Z)=add(X,add(Y,Z)).
% 1.67/1.88  0 [] negate(add(negate(add(X,Y)),negate(add(X,negate(Y)))))=X.
% 1.67/1.88  0 [] add(X,c)=c.
% 1.67/1.88  0 [] add(negate(add(a,negate(b))),negate(add(negate(a),negate(b))))!=b.
% 1.67/1.88  end_of_list.
% 1.67/1.88  
% 1.67/1.88  SCAN INPUT: prop=0, horn=1, equality=1, symmetry=0, max_lits=1.
% 1.67/1.88  
% 1.67/1.88  All clauses are units, and equality is present; the
% 1.67/1.88  strategy will be Knuth-Bendix with positive clauses in sos.
% 1.67/1.88  
% 1.67/1.88     dependent: set(knuth_bendix).
% 1.67/1.88     dependent: set(anl_eq).
% 1.67/1.88     dependent: set(para_from).
% 1.67/1.88     dependent: set(para_into).
% 1.67/1.88     dependent: clear(para_from_right).
% 1.67/1.88     dependent: clear(para_into_right).
% 1.67/1.88     dependent: set(para_from_vars).
% 1.67/1.88     dependent: set(eq_units_both_ways).
% 1.67/1.88     dependent: set(dynamic_demod_all).
% 1.67/1.88     dependent: set(dynamic_demod).
% 1.67/1.88     dependent: set(order_eq).
% 1.67/1.88     dependent: set(back_demod).
% 1.67/1.88     dependent: set(lrpo).
% 1.67/1.88  
% 1.67/1.88  ------------> process usable:
% 1.67/1.88  ** KEPT (pick-wt=14): 1 [] add(negate(add(a,negate(b))),negate(add(negate(a),negate(b))))!=b.
% 1.67/1.88  
% 1.67/1.88  ------------> process sos:
% 1.67/1.88  ** KEPT (pick-wt=3): 2 [] A=A.
% 1.67/1.88  ** KEPT (pick-wt=7): 3 [] add(A,B)=add(B,A).
% 1.67/1.88  ** KEPT (pick-wt=11): 4 [] add(add(A,B),C)=add(A,add(B,C)).
% 1.67/1.88  ---> New Demodulator: 5 [new_demod,4] add(add(A,B),C)=add(A,add(B,C)).
% 1.67/1.88  ** KEPT (pick-wt=13): 6 [] negate(add(negate(add(A,B)),negate(add(A,negate(B)))))=A.
% 1.67/1.88  ---> New Demodulator: 7 [new_demod,6] negate(add(negate(add(A,B)),negate(add(A,negate(B)))))=A.
% 1.67/1.88  ** KEPT (pick-wt=5): 8 [] add(A,c)=c.
% 1.67/1.88  ---> New Demodulator: 9 [new_demod,8] add(A,c)=c.
% 1.67/1.88    Following clause subsumed by 2 during input processing: 0 [copy,2,flip.1] A=A.
% 1.67/1.88    Following clause subsumed by 3 during input processing: 0 [copy,3,flip.1] add(A,B)=add(B,A).
% 1.67/1.88  >>>> Starting back demodulation with 5.
% 1.67/1.88  >>>> Starting back demodulation with 7.
% 1.67/1.88  >>>> Starting back demodulation with 9.
% 1.67/1.88  
% 1.67/1.88  ======= end of input processing =======
% 1.67/1.88  
% 1.67/1.88  =========== start of search ===========
% 1.67/1.88  
% 1.67/1.88  -------- PROOF -------- 
% 1.67/1.88  
% 1.67/1.88  ----> UNIT CONFLICT at   0.00 sec ----> 122 [binary,121.1,2.1] $F.
% 1.67/1.88  
% 1.67/1.88  Length of proof is 17.  Level of proof is 8.
% 1.67/1.88  
% 1.67/1.88  ---------------- PROOF ----------------
% 1.67/1.88  % SZS status Unsatisfiable
% 1.67/1.88  % SZS output start Refutation
% See solution above
% 1.67/1.88  ------------ end of proof -------------
% 1.67/1.88  
% 1.67/1.88  
% 1.67/1.88  Search stopped by max_proofs option.
% 1.67/1.88  
% 1.67/1.88  
% 1.67/1.88  Search stopped by max_proofs option.
% 1.67/1.88  
% 1.67/1.88  ============ end of search ============
% 1.67/1.88  
% 1.67/1.88  -------------- statistics -------------
% 1.67/1.88  clauses given                 18
% 1.67/1.88  clauses generated            213
% 1.67/1.88  clauses kept                  81
% 1.67/1.88  clauses forward subsumed     191
% 1.67/1.88  clauses back subsumed          0
% 1.67/1.88  Kbytes malloced             1953
% 1.67/1.88  
% 1.67/1.88  ----------- times (seconds) -----------
% 1.67/1.88  user CPU time          0.01          (0 hr, 0 min, 0 sec)
% 1.67/1.88  system CPU time        0.00          (0 hr, 0 min, 0 sec)
% 1.67/1.88  wall-clock time        2             (0 hr, 0 min, 2 sec)
% 1.67/1.88  
% 1.67/1.88  That finishes the proof of the theorem.
% 1.67/1.88  
% 1.67/1.88  Process 30768 finished Wed Jul 27 04:03:13 2022
% 1.67/1.88  Otter interrupted
% 1.67/1.88  PROOF FOUND
%------------------------------------------------------------------------------