TSTP Solution File: RNG125+4 by SuperZenon---0.0.1

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : SuperZenon---0.0.1
% Problem  : RNG125+4 : TPTP v8.1.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : run_super_zenon -p0 -itptp -om -max-time %d %s

% Computer : n021.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Mon Jul 18 20:42:03 EDT 2022

% Result   : Theorem 2.43s 2.60s
% Output   : Proof 2.43s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.10/0.12  % Problem  : RNG125+4 : TPTP v8.1.0. Released v4.0.0.
% 0.10/0.13  % Command  : run_super_zenon -p0 -itptp -om -max-time %d %s
% 0.13/0.34  % Computer : n021.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit : 300
% 0.13/0.34  % WCLimit  : 600
% 0.13/0.34  % DateTime : Mon May 30 14:42:59 EDT 2022
% 0.13/0.34  % CPUTime  : 
% 2.43/2.60  % SZS status Theorem
% 2.43/2.60  (* PROOF-FOUND *)
% 2.43/2.60  (* BEGIN-PROOF *)
% 2.43/2.60  % SZS output start Proof
% 2.43/2.60  1. (Ex W0, ((aElement0 W0) /\ ((sdtasdt0 (xu) W0) = (xa)))) (-. (Ex W0, ((aElement0 W0) /\ ((sdtasdt0 (xu) W0) = (xa)))))   ### Axiom
% 2.43/2.60  2. (-. ((Ex W0, ((aElement0 W0) /\ ((sdtasdt0 (xu) W0) = (xa)))) \/ ((doDivides0 (xu) (xa)) \/ (aDivisorOf0 (xu) (xa))))) (Ex W0, ((aElement0 W0) /\ ((sdtasdt0 (xu) W0) = (xa))))   ### ConjTree 1
% 2.43/2.60  3. (Ex W0, ((aElement0 W0) /\ ((sdtasdt0 (xu) W0) = (xb)))) (-. (Ex W0, ((aElement0 W0) /\ ((sdtasdt0 (xu) W0) = (xb)))))   ### Axiom
% 2.43/2.60  4. (-. ((Ex W0, ((aElement0 W0) /\ ((sdtasdt0 (xu) W0) = (xb)))) \/ ((doDivides0 (xu) (xb)) \/ (aDivisorOf0 (xu) (xb))))) (Ex W0, ((aElement0 W0) /\ ((sdtasdt0 (xu) W0) = (xb))))   ### ConjTree 3
% 2.43/2.60  5. (-. (((Ex W0, ((aElement0 W0) /\ ((sdtasdt0 (xu) W0) = (xa)))) \/ ((doDivides0 (xu) (xa)) \/ (aDivisorOf0 (xu) (xa)))) /\ ((Ex W0, ((aElement0 W0) /\ ((sdtasdt0 (xu) W0) = (xb)))) \/ ((doDivides0 (xu) (xb)) \/ (aDivisorOf0 (xu) (xb)))))) (Ex W0, ((aElement0 W0) /\ ((sdtasdt0 (xu) W0) = (xb)))) (Ex W0, ((aElement0 W0) /\ ((sdtasdt0 (xu) W0) = (xa))))   ### NotAnd 2 4
% 2.43/2.60  6. ((Ex W0, ((aElement0 W0) /\ ((sdtasdt0 (xu) W0) = (xa)))) /\ (doDivides0 (xu) (xa))) (Ex W0, ((aElement0 W0) /\ ((sdtasdt0 (xu) W0) = (xb)))) (-. (((Ex W0, ((aElement0 W0) /\ ((sdtasdt0 (xu) W0) = (xa)))) \/ ((doDivides0 (xu) (xa)) \/ (aDivisorOf0 (xu) (xa)))) /\ ((Ex W0, ((aElement0 W0) /\ ((sdtasdt0 (xu) W0) = (xb)))) \/ ((doDivides0 (xu) (xb)) \/ (aDivisorOf0 (xu) (xb))))))   ### And 5
% 2.43/2.60  7. (-. (-. ((Ex W0, ((aElement0 W0) /\ ((sdtasdt0 (xu) W0) = (xa)))) /\ (doDivides0 (xu) (xa))))) (-. (((Ex W0, ((aElement0 W0) /\ ((sdtasdt0 (xu) W0) = (xa)))) \/ ((doDivides0 (xu) (xa)) \/ (aDivisorOf0 (xu) (xa)))) /\ ((Ex W0, ((aElement0 W0) /\ ((sdtasdt0 (xu) W0) = (xb)))) \/ ((doDivides0 (xu) (xb)) \/ (aDivisorOf0 (xu) (xb)))))) (Ex W0, ((aElement0 W0) /\ ((sdtasdt0 (xu) W0) = (xb))))   ### NotNot 6
% 2.43/2.60  8. ((Ex W0, ((aElement0 W0) /\ ((sdtasdt0 (xu) W0) = (xb)))) /\ (doDivides0 (xu) (xb))) (-. (((Ex W0, ((aElement0 W0) /\ ((sdtasdt0 (xu) W0) = (xa)))) \/ ((doDivides0 (xu) (xa)) \/ (aDivisorOf0 (xu) (xa)))) /\ ((Ex W0, ((aElement0 W0) /\ ((sdtasdt0 (xu) W0) = (xb)))) \/ ((doDivides0 (xu) (xb)) \/ (aDivisorOf0 (xu) (xb)))))) (-. (-. ((Ex W0, ((aElement0 W0) /\ ((sdtasdt0 (xu) W0) = (xa)))) /\ (doDivides0 (xu) (xa)))))   ### And 7
% 2.43/2.60  9. (-. (-. ((Ex W0, ((aElement0 W0) /\ ((sdtasdt0 (xu) W0) = (xb)))) /\ (doDivides0 (xu) (xb))))) (-. (-. ((Ex W0, ((aElement0 W0) /\ ((sdtasdt0 (xu) W0) = (xa)))) /\ (doDivides0 (xu) (xa))))) (-. (((Ex W0, ((aElement0 W0) /\ ((sdtasdt0 (xu) W0) = (xa)))) \/ ((doDivides0 (xu) (xa)) \/ (aDivisorOf0 (xu) (xa)))) /\ ((Ex W0, ((aElement0 W0) /\ ((sdtasdt0 (xu) W0) = (xb)))) \/ ((doDivides0 (xu) (xb)) \/ (aDivisorOf0 (xu) (xb))))))   ### NotNot 8
% 2.43/2.60  % SZS output end Proof
% 2.43/2.60  (* END-PROOF *)
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