TSTP Solution File: RNG125+1 by SPASS---3.9
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%------------------------------------------------------------------------------
% File : SPASS---3.9
% Problem : RNG125+1 : TPTP v8.1.0. Released v4.0.0.
% Transfm : none
% Format : tptp
% Command : run_spass %d %s
% Computer : n021.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Mon Jul 18 20:41:33 EDT 2022
% Result : Theorem 0.19s 0.54s
% Output : Refutation 0.19s
% Verified :
% SZS Type : Refutation
% Derivation depth : 7
% Number of leaves : 10
% Syntax : Number of clauses : 18 ( 10 unt; 0 nHn; 18 RR)
% Number of literals : 32 ( 0 equ; 20 neg)
% Maximal clause size : 4 ( 1 avg)
% Maximal term depth : 1 ( 1 avg)
% Number of predicates : 7 ( 6 usr; 1 prp; 0-2 aty)
% Number of functors : 6 ( 6 usr; 6 con; 0-0 aty)
% Number of variables : 0 ( 0 sgn)
% Comments :
%------------------------------------------------------------------------------
cnf(3,axiom,
aElement0(xa),
file('RNG125+1.p',unknown),
[] ).
cnf(4,axiom,
aElement0(xb),
file('RNG125+1.p',unknown),
[] ).
cnf(5,axiom,
aIdeal0(xI),
file('RNG125+1.p',unknown),
[] ).
cnf(9,axiom,
aElementOf0(xu,xI),
file('RNG125+1.p',unknown),
[] ).
cnf(10,axiom,
doDivides0(xu,xa),
file('RNG125+1.p',unknown),
[] ).
cnf(11,axiom,
doDivides0(xu,xb),
file('RNG125+1.p',unknown),
[] ).
cnf(25,axiom,
( ~ aIdeal0(u)
| aSet0(u) ),
file('RNG125+1.p',unknown),
[] ).
cnf(39,axiom,
( ~ aDivisorOf0(xu,xb)
| ~ aDivisorOf0(xu,xa) ),
file('RNG125+1.p',unknown),
[] ).
cnf(42,axiom,
( ~ aSet0(u)
| ~ aElementOf0(v,u)
| aElement0(v) ),
file('RNG125+1.p',unknown),
[] ).
cnf(63,axiom,
( ~ aElement0(u)
| ~ aElement0(v)
| ~ doDivides0(v,u)
| aDivisorOf0(v,u) ),
file('RNG125+1.p',unknown),
[] ).
cnf(131,plain,
( ~ aSet0(xI)
| aElement0(xu) ),
inference(res,[status(thm),theory(equality)],[9,42]),
[iquote('0:Res:9.0,42.1')] ).
cnf(139,plain,
aElement0(xu),
inference(ssi,[status(thm)],[131,25,5]),
[iquote('0:SSi:131.0,25.0,5.1')] ).
cnf(223,plain,
( ~ aElement0(xb)
| ~ aElement0(xu)
| ~ doDivides0(xu,xb)
| ~ aDivisorOf0(xu,xa) ),
inference(res,[status(thm),theory(equality)],[63,39]),
[iquote('0:Res:63.3,39.0')] ).
cnf(226,plain,
( ~ doDivides0(xu,xb)
| ~ aDivisorOf0(xu,xa) ),
inference(ssi,[status(thm)],[223,139,4]),
[iquote('0:SSi:223.1,223.0,139.0,4.0')] ).
cnf(227,plain,
~ aDivisorOf0(xu,xa),
inference(mrr,[status(thm)],[226,11]),
[iquote('0:MRR:226.0,11.0')] ).
cnf(228,plain,
( ~ aElement0(xa)
| ~ aElement0(xu)
| ~ doDivides0(xu,xa) ),
inference(res,[status(thm),theory(equality)],[63,227]),
[iquote('0:Res:63.3,227.0')] ).
cnf(229,plain,
~ doDivides0(xu,xa),
inference(ssi,[status(thm)],[228,139,3]),
[iquote('0:SSi:228.1,228.0,139.0,3.0')] ).
cnf(230,plain,
$false,
inference(mrr,[status(thm)],[229,10]),
[iquote('0:MRR:229.0,10.0')] ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.06/0.12 % Problem : RNG125+1 : TPTP v8.1.0. Released v4.0.0.
% 0.06/0.13 % Command : run_spass %d %s
% 0.13/0.33 % Computer : n021.cluster.edu
% 0.13/0.33 % Model : x86_64 x86_64
% 0.13/0.33 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.33 % Memory : 8042.1875MB
% 0.13/0.33 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.33 % CPULimit : 300
% 0.13/0.33 % WCLimit : 600
% 0.13/0.33 % DateTime : Mon May 30 04:47:58 EDT 2022
% 0.13/0.34 % CPUTime :
% 0.19/0.54
% 0.19/0.54 SPASS V 3.9
% 0.19/0.54 SPASS beiseite: Proof found.
% 0.19/0.54 % SZS status Theorem
% 0.19/0.54 Problem: /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.19/0.54 SPASS derived 87 clauses, backtracked 0 clauses, performed 0 splits and kept 119 clauses.
% 0.19/0.54 SPASS allocated 99381 KBytes.
% 0.19/0.54 SPASS spent 0:00:00.19 on the problem.
% 0.19/0.54 0:00:00.04 for the input.
% 0.19/0.54 0:00:00.12 for the FLOTTER CNF translation.
% 0.19/0.54 0:00:00.00 for inferences.
% 0.19/0.54 0:00:00.00 for the backtracking.
% 0.19/0.54 0:00:00.01 for the reduction.
% 0.19/0.54
% 0.19/0.54
% 0.19/0.54 Here is a proof with depth 2, length 18 :
% 0.19/0.54 % SZS output start Refutation
% See solution above
% 0.19/0.54 Formulae used in the proof : m__2091 m__2174 m__2273 m__2479 m__2612 mDefIdeal m__2416 m__2383 mEOfElem mDefDvs
% 0.19/0.54
%------------------------------------------------------------------------------