TSTP Solution File: RNG121+4 by SPASS---3.9
View Problem
- Process Solution
%------------------------------------------------------------------------------
% File : SPASS---3.9
% Problem : RNG121+4 : TPTP v8.1.0. Released v4.0.0.
% Transfm : none
% Format : tptp
% Command : run_spass %d %s
% Computer : n022.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Mon Jul 18 20:41:32 EDT 2022
% Result : Theorem 0.48s 0.68s
% Output : Refutation 0.48s
% Verified :
% SZS Type : Refutation
% Derivation depth : 5
% Number of leaves : 8
% Syntax : Number of clauses : 15 ( 6 unt; 0 nHn; 15 RR)
% Number of literals : 29 ( 0 equ; 19 neg)
% Maximal clause size : 4 ( 1 avg)
% Maximal term depth : 3 ( 1 avg)
% Number of predicates : 4 ( 3 usr; 1 prp; 0-2 aty)
% Number of functors : 9 ( 9 usr; 5 con; 0-2 aty)
% Number of variables : 0 ( 0 sgn)
% Comments :
%------------------------------------------------------------------------------
cnf(4,axiom,
aElement0(xb),
file('RNG121+4.p',unknown),
[] ).
cnf(28,axiom,
aElement0(skf47(u)),
file('RNG121+4.p',unknown),
[] ).
cnf(39,axiom,
aElementOf0(sz00,slsdtgt0(xa)),
file('RNG121+4.p',unknown),
[] ).
cnf(42,axiom,
aElementOf0(xb,slsdtgt0(xb)),
file('RNG121+4.p',unknown),
[] ).
cnf(79,axiom,
( ~ aElement0(u)
| equal(sdtpldt0(sz00,u),u) ),
file('RNG121+4.p',unknown),
[] ).
cnf(102,axiom,
( ~ aElement0(u)
| ~ aElement0(v)
| aElement0(sdtasdt0(v,u)) ),
file('RNG121+4.p',unknown),
[] ).
cnf(116,axiom,
( ~ aElementOf0(u,slsdtgt0(xb))
| equal(sdtasdt0(xb,skf47(u)),u) ),
file('RNG121+4.p',unknown),
[] ).
cnf(140,axiom,
( ~ aElementOf0(u,slsdtgt0(xb))
| ~ aElementOf0(v,slsdtgt0(xa))
| ~ equal(sdtpldt0(v,u),xb) ),
file('RNG121+4.p',unknown),
[] ).
cnf(194,plain,
( ~ aElementOf0(u,slsdtgt0(xb))
| ~ equal(sdtpldt0(sz00,u),xb) ),
inference(res,[status(thm),theory(equality)],[39,140]),
[iquote('0:Res:39.0,140.0')] ).
cnf(359,plain,
( ~ aElement0(skf47(u))
| ~ aElement0(xb)
| ~ aElementOf0(u,slsdtgt0(xb))
| aElement0(u) ),
inference(spr,[status(thm),theory(equality)],[116,102]),
[iquote('0:SpR:116.1,102.2')] ).
cnf(360,plain,
( ~ aElementOf0(u,slsdtgt0(xb))
| aElement0(u) ),
inference(ssi,[status(thm)],[359,4,28]),
[iquote('0:SSi:359.1,359.0,4.0,28.0')] ).
cnf(374,plain,
( ~ aElement0(u)
| ~ aElementOf0(u,slsdtgt0(xb))
| ~ equal(u,xb) ),
inference(spl,[status(thm),theory(equality)],[79,194]),
[iquote('0:SpL:79.1,194.1')] ).
cnf(377,plain,
( ~ aElementOf0(u,slsdtgt0(xb))
| ~ equal(u,xb) ),
inference(mrr,[status(thm)],[374,360]),
[iquote('0:MRR:374.0,360.1')] ).
cnf(384,plain,
~ equal(xb,xb),
inference(res,[status(thm),theory(equality)],[42,377]),
[iquote('0:Res:42.0,377.0')] ).
cnf(388,plain,
$false,
inference(obv,[status(thm),theory(equality)],[384]),
[iquote('0:Obv:384.0')] ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.08/0.13 % Problem : RNG121+4 : TPTP v8.1.0. Released v4.0.0.
% 0.08/0.14 % Command : run_spass %d %s
% 0.15/0.35 % Computer : n022.cluster.edu
% 0.15/0.35 % Model : x86_64 x86_64
% 0.15/0.35 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.15/0.35 % Memory : 8042.1875MB
% 0.15/0.35 % OS : Linux 3.10.0-693.el7.x86_64
% 0.15/0.35 % CPULimit : 300
% 0.15/0.35 % WCLimit : 600
% 0.15/0.35 % DateTime : Mon May 30 18:35:52 EDT 2022
% 0.15/0.35 % CPUTime :
% 0.48/0.68
% 0.48/0.68 SPASS V 3.9
% 0.48/0.68 SPASS beiseite: Proof found.
% 0.48/0.68 % SZS status Theorem
% 0.48/0.68 Problem: /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.48/0.68 SPASS derived 169 clauses, backtracked 0 clauses, performed 0 splits and kept 246 clauses.
% 0.48/0.68 SPASS allocated 100382 KBytes.
% 0.48/0.68 SPASS spent 0:00:00.31 on the problem.
% 0.48/0.68 0:00:00.04 for the input.
% 0.48/0.68 0:00:00.23 for the FLOTTER CNF translation.
% 0.48/0.68 0:00:00.00 for inferences.
% 0.48/0.68 0:00:00.00 for the backtracking.
% 0.48/0.68 0:00:00.02 for the reduction.
% 0.48/0.68
% 0.48/0.68
% 0.48/0.68 Here is a proof with depth 3, length 15 :
% 0.48/0.68 % SZS output start Refutation
% See solution above
% 0.48/0.68 Formulae used in the proof : m__2091 m__2228 m__2666 m__2203 mAddZero mSortsB_02 m__
% 0.48/0.68
%------------------------------------------------------------------------------