TSTP Solution File: RNG112+4 by SPASS---3.9

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%------------------------------------------------------------------------------
% File     : SPASS---3.9
% Problem  : RNG112+4 : TPTP v8.1.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp
% Command  : run_spass %d %s

% Computer : n017.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Mon Jul 18 20:41:31 EDT 2022

% Result   : Theorem 0.49s 0.64s
% Output   : Refutation 0.49s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    8
%            Number of leaves      :   11
% Syntax   : Number of clauses     :   27 (  14 unt;   3 nHn;  27 RR)
%            Number of literals    :   43 (   0 equ;  19 neg)
%            Maximal clause size   :    3 (   1 avg)
%            Maximal term depth    :    3 (   1 avg)
%            Number of predicates  :    6 (   5 usr;   1 prp; 0-2 aty)
%            Number of functors    :   11 (  11 usr;   7 con; 0-2 aty)
%            Number of variables   :    0 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(37,axiom,
    ~ equal(sz00,skc55),
    file('RNG112+4.p',unknown),
    [] ).

cnf(40,axiom,
    ~ equal(sz00,skc58),
    file('RNG112+4.p',unknown),
    [] ).

cnf(43,axiom,
    ~ equal(skf27(u),sz00),
    file('RNG112+4.p',unknown),
    [] ).

cnf(54,axiom,
    ( ~ aElementOf0(u,xI)
    | skP6(u) ),
    file('RNG112+4.p',unknown),
    [] ).

cnf(60,axiom,
    ( ~ skP5(u)
    | aElementOf0(skc58,xI) ),
    file('RNG112+4.p',unknown),
    [] ).

cnf(61,axiom,
    equal(sdtpldt1(slsdtgt0(xa),slsdtgt0(xb)),xI),
    file('RNG112+4.p',unknown),
    [] ).

cnf(62,axiom,
    aElementOf0(skc55,sdtpldt1(slsdtgt0(xa),slsdtgt0(xb))),
    file('RNG112+4.p',unknown),
    [] ).

cnf(83,axiom,
    ( ~ skP5(u)
    | ~ iLess0(sbrdtbr0(u),sbrdtbr0(skc58)) ),
    file('RNG112+4.p',unknown),
    [] ).

cnf(84,axiom,
    ( ~ aElementOf0(u,xI)
    | skP5(u)
    | equal(u,sz00) ),
    file('RNG112+4.p',unknown),
    [] ).

cnf(85,axiom,
    ( ~ skP6(u)
    | equal(u,sz00)
    | aElementOf0(skf27(u),xI) ),
    file('RNG112+4.p',unknown),
    [] ).

cnf(102,axiom,
    ( ~ skP6(u)
    | equal(u,sz00)
    | iLess0(sbrdtbr0(skf27(u)),sbrdtbr0(u)) ),
    file('RNG112+4.p',unknown),
    [] ).

cnf(163,plain,
    aElementOf0(skc55,xI),
    inference(rew,[status(thm),theory(equality)],[61,62]),
    [iquote('0:Rew:61.0,62.0')] ).

cnf(169,plain,
    ( ~ aElementOf0(skf27(u),xI)
    | skP5(skf27(u)) ),
    inference(res,[status(thm),theory(equality)],[84,43]),
    [iquote('0:Res:84.1,43.0')] ).

cnf(210,plain,
    skP6(skc55),
    inference(res,[status(thm),theory(equality)],[163,54]),
    [iquote('0:Res:163.0,54.0')] ).

cnf(212,plain,
    ( ~ skP6(skc58)
    | aElementOf0(skf27(skc58),xI) ),
    inference(res,[status(thm),theory(equality)],[85,40]),
    [iquote('0:Res:85.2,40.0')] ).

cnf(213,plain,
    ( ~ skP6(skc55)
    | aElementOf0(skf27(skc55),xI) ),
    inference(res,[status(thm),theory(equality)],[85,37]),
    [iquote('0:Res:85.2,37.0')] ).

cnf(216,plain,
    ( ~ skP6(skc58)
    | iLess0(sbrdtbr0(skf27(skc58)),sbrdtbr0(skc58)) ),
    inference(res,[status(thm),theory(equality)],[102,40]),
    [iquote('0:Res:102.2,40.0')] ).

cnf(236,plain,
    aElementOf0(skf27(skc55),xI),
    inference(mrr,[status(thm)],[213,210]),
    [iquote('0:MRR:213.0,210.0')] ).

cnf(273,plain,
    ( ~ aElementOf0(skc58,xI)
    | aElementOf0(skf27(skc58),xI) ),
    inference(sor,[status(thm)],[212,54]),
    [iquote('0:SoR:212.0,54.1')] ).

cnf(285,plain,
    ( ~ aElementOf0(skf27(u),xI)
    | aElementOf0(skc58,xI) ),
    inference(ems,[status(thm)],[60,169]),
    [iquote('0:EmS:60.0,169.1')] ).

cnf(286,plain,
    aElementOf0(skc58,xI),
    inference(res,[status(thm),theory(equality)],[236,285]),
    [iquote('0:Res:236.0,285.0')] ).

cnf(289,plain,
    aElementOf0(skf27(skc58),xI),
    inference(mrr,[status(thm)],[273,286]),
    [iquote('0:MRR:273.0,286.0')] ).

cnf(297,plain,
    ( ~ aElementOf0(skc58,xI)
    | iLess0(sbrdtbr0(skf27(skc58)),sbrdtbr0(skc58)) ),
    inference(sor,[status(thm)],[216,54]),
    [iquote('0:SoR:216.0,54.1')] ).

cnf(298,plain,
    iLess0(sbrdtbr0(skf27(skc58)),sbrdtbr0(skc58)),
    inference(mrr,[status(thm)],[297,286]),
    [iquote('0:MRR:297.0,286.0')] ).

cnf(299,plain,
    ~ skP5(skf27(skc58)),
    inference(res,[status(thm),theory(equality)],[298,83]),
    [iquote('0:Res:298.0,83.1')] ).

cnf(300,plain,
    ~ aElementOf0(skf27(skc58),xI),
    inference(sor,[status(thm)],[299,169]),
    [iquote('0:SoR:299.0,169.1')] ).

cnf(301,plain,
    $false,
    inference(mrr,[status(thm)],[300,289]),
    [iquote('0:MRR:300.0,289.0')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.13/0.12  % Problem  : RNG112+4 : TPTP v8.1.0. Released v4.0.0.
% 0.13/0.13  % Command  : run_spass %d %s
% 0.14/0.35  % Computer : n017.cluster.edu
% 0.14/0.35  % Model    : x86_64 x86_64
% 0.14/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.35  % Memory   : 8042.1875MB
% 0.14/0.35  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.14/0.35  % CPULimit : 300
% 0.14/0.35  % WCLimit  : 600
% 0.14/0.35  % DateTime : Mon May 30 04:45:24 EDT 2022
% 0.14/0.35  % CPUTime  : 
% 0.49/0.64  
% 0.49/0.64  SPASS V 3.9 
% 0.49/0.64  SPASS beiseite: Proof found.
% 0.49/0.64  % SZS status Theorem
% 0.49/0.64  Problem: /export/starexec/sandbox2/benchmark/theBenchmark.p 
% 0.49/0.64  SPASS derived 71 clauses, backtracked 0 clauses, performed 0 splits and kept 203 clauses.
% 0.49/0.64  SPASS allocated 100382 KBytes.
% 0.49/0.64  SPASS spent	0:00:00.28 on the problem.
% 0.49/0.64  		0:00:00.04 for the input.
% 0.49/0.64  		0:00:00.20 for the FLOTTER CNF translation.
% 0.49/0.64  		0:00:00.00 for inferences.
% 0.49/0.64  		0:00:00.00 for the backtracking.
% 0.49/0.64  		0:00:00.01 for the reduction.
% 0.49/0.64  
% 0.49/0.64  
% 0.49/0.64  Here is a proof with depth 4, length 27 :
% 0.49/0.64  % SZS output start Refutation
% See solution above
% 0.49/0.64  Formulae used in the proof : m__2228 m__2203 m__2351 m__ m__2174
% 0.49/0.64  
%------------------------------------------------------------------------------