TSTP Solution File: RNG103+2 by SPASS---3.9

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%------------------------------------------------------------------------------
% File     : SPASS---3.9
% Problem  : RNG103+2 : TPTP v8.1.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp
% Command  : run_spass %d %s

% Computer : n019.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Mon Jul 18 20:41:29 EDT 2022

% Result   : Theorem 1.12s 1.29s
% Output   : Refutation 1.12s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    4
%            Number of leaves      :    7
% Syntax   : Number of clauses     :   11 (   7 unt;   0 nHn;  11 RR)
%            Number of literals    :   22 (   0 equ;  15 neg)
%            Maximal clause size   :    4 (   2 avg)
%            Maximal term depth    :    3 (   1 avg)
%            Number of predicates  :    3 (   2 usr;   1 prp; 0-2 aty)
%            Number of functors    :   10 (  10 usr;   8 con; 0-2 aty)
%            Number of variables   :    0 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(3,axiom,
    aElement0(xc),
    file('RNG103+2.p',unknown),
    [] ).

cnf(7,axiom,
    aElement0(xu),
    file('RNG103+2.p',unknown),
    [] ).

cnf(8,axiom,
    aElement0(xv),
    file('RNG103+2.p',unknown),
    [] ).

cnf(21,axiom,
    equal(sdtasdt0(xc,xu),xx),
    file('RNG103+2.p',unknown),
    [] ).

cnf(22,axiom,
    equal(sdtasdt0(xc,xv),xy),
    file('RNG103+2.p',unknown),
    [] ).

cnf(39,axiom,
    ~ equal(sdtasdt0(xc,sdtpldt0(xu,xv)),sdtpldt0(xx,xy)),
    file('RNG103+2.p',unknown),
    [] ).

cnf(85,axiom,
    ( ~ aElement0(u)
    | ~ aElement0(v)
    | ~ aElement0(w)
    | equal(sdtasdt0(w,sdtpldt0(v,u)),sdtpldt0(sdtasdt0(w,v),sdtasdt0(w,u))) ),
    file('RNG103+2.p',unknown),
    [] ).

cnf(3796,plain,
    ( ~ aElement0(xv)
    | ~ aElement0(xu)
    | ~ aElement0(xc)
    | ~ equal(sdtpldt0(sdtasdt0(xc,xu),sdtasdt0(xc,xv)),sdtpldt0(xx,xy)) ),
    inference(spl,[status(thm),theory(equality)],[85,39]),
    [iquote('0:SpL:85.3,39.0')] ).

cnf(3797,plain,
    ( ~ aElement0(xv)
    | ~ aElement0(xu)
    | ~ aElement0(xc)
    | ~ equal(sdtpldt0(xx,xy),sdtpldt0(xx,xy)) ),
    inference(rew,[status(thm),theory(equality)],[21,3796,22]),
    [iquote('0:Rew:21.0,3796.3,22.0,3796.3')] ).

cnf(3798,plain,
    ( ~ aElement0(xv)
    | ~ aElement0(xu)
    | ~ aElement0(xc) ),
    inference(obv,[status(thm),theory(equality)],[3797]),
    [iquote('0:Obv:3797.3')] ).

cnf(3799,plain,
    $false,
    inference(ssi,[status(thm)],[3798,3,7,8]),
    [iquote('0:SSi:3798.2,3798.1,3798.0,3.0,7.0,8.0')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.12  % Problem  : RNG103+2 : TPTP v8.1.0. Released v4.0.0.
% 0.07/0.12  % Command  : run_spass %d %s
% 0.13/0.33  % Computer : n019.cluster.edu
% 0.13/0.33  % Model    : x86_64 x86_64
% 0.13/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.33  % Memory   : 8042.1875MB
% 0.13/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.33  % CPULimit : 300
% 0.13/0.33  % WCLimit  : 600
% 0.13/0.33  % DateTime : Mon May 30 12:17:41 EDT 2022
% 0.13/0.33  % CPUTime  : 
% 1.12/1.29  
% 1.12/1.29  SPASS V 3.9 
% 1.12/1.29  SPASS beiseite: Proof found.
% 1.12/1.29  % SZS status Theorem
% 1.12/1.29  Problem: /export/starexec/sandbox2/benchmark/theBenchmark.p 
% 1.12/1.29  SPASS derived 2581 clauses, backtracked 451 clauses, performed 6 splits and kept 1448 clauses.
% 1.12/1.29  SPASS allocated 100949 KBytes.
% 1.12/1.29  SPASS spent	0:00:00.91 on the problem.
% 1.12/1.29  		0:00:00.04 for the input.
% 1.12/1.29  		0:00:00.13 for the FLOTTER CNF translation.
% 1.12/1.29  		0:00:00.03 for inferences.
% 1.12/1.29  		0:00:00.01 for the backtracking.
% 1.12/1.29  		0:00:00.66 for the reduction.
% 1.12/1.29  
% 1.12/1.29  
% 1.12/1.29  Here is a proof with depth 1, length 11 :
% 1.12/1.29  % SZS output start Refutation
% See solution above
% 1.12/1.29  Formulae used in the proof : m__1905 m__1956 m__1979 m__ mAMDistr
% 1.12/1.29  
%------------------------------------------------------------------------------