TSTP Solution File: RNG102+2 by SInE---0.4

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : SInE---0.4
% Problem  : RNG102+2 : TPTP v5.0.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : Source/sine.py -e eprover -t %d %s

% Computer : art02.cs.miami.edu
% Model    : i686 i686
% CPU      : Intel(R) Pentium(R) 4 CPU 2.80GHz @ 2793MHz
% Memory   : 2018MB
% OS       : Linux 2.6.26.8-57.fc8
% CPULimit : 300s
% DateTime : Sun Dec 26 02:22:48 EST 2010

% Result   : Theorem 0.18s
% Output   : CNFRefutation 0.18s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    8
%            Number of leaves      :    2
% Syntax   : Number of formulae    :   14 (   6 unt;   0 def)
%            Number of atoms       :   37 (  12 equ)
%            Maximal formula atoms :    7 (   2 avg)
%            Number of connectives :   31 (   8   ~;   3   |;  20   &)
%                                         (   0 <=>;   0  =>;   0  <=;   0 <~>)
%            Maximal formula depth :    7 (   3 avg)
%            Maximal term depth    :    2 (   1 avg)
%            Number of predicates  :    4 (   2 usr;   1 prp; 0-2 aty)
%            Number of functors    :    8 (   8 usr;   6 con; 0-2 aty)
%            Number of variables   :    9 (   0 sgn   2   !;   6   ?)

% Comments : 
%------------------------------------------------------------------------------
fof(9,axiom,
    ( ? [X1] :
        ( aElement0(X1)
        & sdtasdt0(xc,X1) = xx )
    & aElementOf0(xx,slsdtgt0(xc))
    & ? [X1] :
        ( aElement0(X1)
        & sdtasdt0(xc,X1) = xy )
    & aElementOf0(xy,slsdtgt0(xc))
    & aElement0(xz) ),
    file('/tmp/tmpmAKqYG/sel_RNG102+2.p_1',m__1933) ).

fof(40,conjecture,
    ? [X1] :
      ( aElement0(X1)
      & sdtasdt0(xc,X1) = xy ),
    file('/tmp/tmpmAKqYG/sel_RNG102+2.p_1',m__) ).

fof(42,negated_conjecture,
    ~ ? [X1] :
        ( aElement0(X1)
        & sdtasdt0(xc,X1) = xy ),
    inference(assume_negation,[status(cth)],[40]) ).

fof(90,plain,
    ( ? [X2] :
        ( aElement0(X2)
        & sdtasdt0(xc,X2) = xx )
    & aElementOf0(xx,slsdtgt0(xc))
    & ? [X3] :
        ( aElement0(X3)
        & sdtasdt0(xc,X3) = xy )
    & aElementOf0(xy,slsdtgt0(xc))
    & aElement0(xz) ),
    inference(variable_rename,[status(thm)],[9]) ).

fof(91,plain,
    ( aElement0(esk6_0)
    & sdtasdt0(xc,esk6_0) = xx
    & aElementOf0(xx,slsdtgt0(xc))
    & aElement0(esk7_0)
    & sdtasdt0(xc,esk7_0) = xy
    & aElementOf0(xy,slsdtgt0(xc))
    & aElement0(xz) ),
    inference(skolemize,[status(esa)],[90]) ).

cnf(94,plain,
    sdtasdt0(xc,esk7_0) = xy,
    inference(split_conjunct,[status(thm)],[91]) ).

cnf(95,plain,
    aElement0(esk7_0),
    inference(split_conjunct,[status(thm)],[91]) ).

fof(249,negated_conjecture,
    ! [X1] :
      ( ~ aElement0(X1)
      | sdtasdt0(xc,X1) != xy ),
    inference(fof_nnf,[status(thm)],[42]) ).

fof(250,negated_conjecture,
    ! [X2] :
      ( ~ aElement0(X2)
      | sdtasdt0(xc,X2) != xy ),
    inference(variable_rename,[status(thm)],[249]) ).

cnf(251,negated_conjecture,
    ( sdtasdt0(xc,X1) != xy
    | ~ aElement0(X1) ),
    inference(split_conjunct,[status(thm)],[250]) ).

cnf(280,plain,
    ~ aElement0(esk7_0),
    inference(spm,[status(thm)],[251,94,theory(equality)]) ).

cnf(285,plain,
    $false,
    inference(rw,[status(thm)],[280,95,theory(equality)]) ).

cnf(286,plain,
    $false,
    inference(cn,[status(thm)],[285,theory(equality)]) ).

cnf(287,plain,
    $false,
    286,
    [proof] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% % SZS status Started for /home/graph/tptp/TPTP/Problems/RNG/RNG102+2.p
% --creating new selector for []
% -running prover on /tmp/tmpmAKqYG/sel_RNG102+2.p_1 with time limit 29
% -prover status Theorem
% Problem RNG102+2.p solved in phase 0.
% % SZS status Theorem for /home/graph/tptp/TPTP/Problems/RNG/RNG102+2.p
% % SZS status Ended for /home/graph/tptp/TPTP/Problems/RNG/RNG102+2.p
% Solved 1 out of 1.
% # Problem is unsatisfiable (or provable), constructing proof object
% # SZS status Theorem
% # SZS output start CNFRefutation.
% See solution above
% # SZS output end CNFRefutation
% 
%------------------------------------------------------------------------------