TSTP Solution File: RNG101+2 by SnakeForV---1.0
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- Process Solution
%------------------------------------------------------------------------------
% File : SnakeForV---1.0
% Problem : RNG101+2 : TPTP v8.1.0. Released v4.0.0.
% Transfm : none
% Format : tptp:raw
% Command : vampire --input_syntax tptp --proof tptp --output_axiom_names on --mode portfolio --schedule snake_tptp_uns --cores 0 -t %d %s
% Computer : n001.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Wed Aug 31 18:15:00 EDT 2022
% Result : Theorem 1.44s 0.56s
% Output : Refutation 1.44s
% Verified :
% SZS Type : Refutation
% Derivation depth : 6
% Number of leaves : 4
% Syntax : Number of formulae : 14 ( 4 unt; 0 def)
% Number of atoms : 43 ( 16 equ)
% Maximal formula atoms : 7 ( 3 avg)
% Number of connectives : 37 ( 8 ~; 3 |; 24 &)
% ( 0 <=>; 2 =>; 0 <=; 0 <~>)
% Maximal formula depth : 7 ( 4 avg)
% Maximal term depth : 2 ( 1 avg)
% Number of predicates : 4 ( 2 usr; 1 prp; 0-2 aty)
% Number of functors : 8 ( 8 usr; 6 con; 0-2 aty)
% Number of variables : 10 ( 2 !; 8 ?)
% Comments :
%------------------------------------------------------------------------------
fof(f108,plain,
$false,
inference(subsumption_resolution,[],[f107,f92]) ).
fof(f92,plain,
aElement0(sK4),
inference(cnf_transformation,[],[f71]) ).
fof(f71,plain,
( xy = sdtasdt0(xc,sK3)
& aElement0(sK3)
& aElement0(sK4)
& xx = sdtasdt0(xc,sK4)
& aElementOf0(xx,slsdtgt0(xc))
& aElement0(xz)
& aElementOf0(xy,slsdtgt0(xc)) ),
inference(skolemisation,[status(esa),new_symbols(skolem,[sK3,sK4])],[f42,f70,f69]) ).
fof(f69,plain,
( ? [X0] :
( sdtasdt0(xc,X0) = xy
& aElement0(X0) )
=> ( xy = sdtasdt0(xc,sK3)
& aElement0(sK3) ) ),
introduced(choice_axiom,[]) ).
fof(f70,plain,
( ? [X1] :
( aElement0(X1)
& xx = sdtasdt0(xc,X1) )
=> ( aElement0(sK4)
& xx = sdtasdt0(xc,sK4) ) ),
introduced(choice_axiom,[]) ).
fof(f42,plain,
( ? [X0] :
( sdtasdt0(xc,X0) = xy
& aElement0(X0) )
& ? [X1] :
( aElement0(X1)
& xx = sdtasdt0(xc,X1) )
& aElementOf0(xx,slsdtgt0(xc))
& aElement0(xz)
& aElementOf0(xy,slsdtgt0(xc)) ),
inference(rectify,[],[f39]) ).
fof(f39,axiom,
( ? [X0] :
( sdtasdt0(xc,X0) = xy
& aElement0(X0) )
& aElement0(xz)
& ? [X0] :
( sdtasdt0(xc,X0) = xx
& aElement0(X0) )
& aElementOf0(xy,slsdtgt0(xc))
& aElementOf0(xx,slsdtgt0(xc)) ),
file('/export/starexec/sandbox2/benchmark/theBenchmark.p',m__1933) ).
fof(f107,plain,
~ aElement0(sK4),
inference(trivial_inequality_removal,[],[f106]) ).
fof(f106,plain,
( xx != xx
| ~ aElement0(sK4) ),
inference(superposition,[],[f100,f91]) ).
fof(f91,plain,
xx = sdtasdt0(xc,sK4),
inference(cnf_transformation,[],[f71]) ).
fof(f100,plain,
! [X0] :
( sdtasdt0(xc,X0) != xx
| ~ aElement0(X0) ),
inference(cnf_transformation,[],[f49]) ).
fof(f49,plain,
! [X0] :
( ~ aElement0(X0)
| sdtasdt0(xc,X0) != xx ),
inference(ennf_transformation,[],[f41]) ).
fof(f41,negated_conjecture,
~ ? [X0] :
( sdtasdt0(xc,X0) = xx
& aElement0(X0) ),
inference(negated_conjecture,[],[f40]) ).
fof(f40,conjecture,
? [X0] :
( sdtasdt0(xc,X0) = xx
& aElement0(X0) ),
file('/export/starexec/sandbox2/benchmark/theBenchmark.p',m__) ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.12 % Problem : RNG101+2 : TPTP v8.1.0. Released v4.0.0.
% 0.07/0.13 % Command : vampire --input_syntax tptp --proof tptp --output_axiom_names on --mode portfolio --schedule snake_tptp_uns --cores 0 -t %d %s
% 0.14/0.34 % Computer : n001.cluster.edu
% 0.14/0.34 % Model : x86_64 x86_64
% 0.14/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.34 % Memory : 8042.1875MB
% 0.14/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.14/0.34 % CPULimit : 300
% 0.14/0.34 % WCLimit : 300
% 0.14/0.34 % DateTime : Tue Aug 30 12:29:46 EDT 2022
% 0.14/0.34 % CPUTime :
% 1.44/0.55 % (24380)dis+1010_1:1_bs=on:ep=RS:erd=off:newcnf=on:nwc=10.0:s2a=on:sgt=32:ss=axioms:i=30:si=on:rawr=on:rtra=on_0 on theBenchmark for (2999ds/30Mi)
% 1.44/0.55 % (24384)dis+21_1:1_ep=RS:nwc=10.0:s2a=on:s2at=1.5:i=50:si=on:rawr=on:rtra=on_0 on theBenchmark for (2999ds/50Mi)
% 1.44/0.55 % (24382)dis+1010_2:3_fs=off:fsr=off:nm=0:nwc=5.0:s2a=on:s2agt=32:i=82:si=on:rawr=on:rtra=on_0 on theBenchmark for (2999ds/82Mi)
% 1.44/0.55 % (24366)dis+1010_1:50_awrs=decay:awrsf=128:nwc=10.0:s2pl=no:sp=frequency:ss=axioms:i=39:si=on:rawr=on:rtra=on_0 on theBenchmark for (2999ds/39Mi)
% 1.44/0.55 % (24388)dis+2_3:1_aac=none:abs=on:ep=R:lcm=reverse:nwc=10.0:sos=on:sp=const_frequency:spb=units:urr=ec_only:i=8:si=on:rawr=on:rtra=on_0 on theBenchmark for (2999ds/8Mi)
% 1.44/0.55 % (24366)First to succeed.
% 1.44/0.55 % (24374)lrs+10_1:1_ins=3:sp=reverse_frequency:spb=goal:to=lpo:i=3:si=on:rawr=on:rtra=on_0 on theBenchmark for (2999ds/3Mi)
% 1.44/0.55 % (24376)lrs+1011_1:1_fd=preordered:fsd=on:sos=on:thsq=on:thsqc=64:thsqd=32:uwa=ground:i=50:si=on:rawr=on:rtra=on_0 on theBenchmark for (2999ds/50Mi)
% 1.44/0.56 % (24374)Instruction limit reached!
% 1.44/0.56 % (24374)------------------------------
% 1.44/0.56 % (24374)Version: Vampire 4.7 (commit 807e37dd9 on 2022-08-23 09:55:27 +0200)
% 1.44/0.56 % (24368)dis+10_1:1_newcnf=on:sgt=8:sos=on:ss=axioms:to=lpo:urr=on:i=49:si=on:rawr=on:rtra=on_0 on theBenchmark for (2999ds/49Mi)
% 1.44/0.56 % (24372)lrs+10_1:4_av=off:bs=unit_only:bsr=unit_only:ep=RS:s2a=on:sos=on:sp=frequency:to=lpo:i=16:si=on:rawr=on:rtra=on_0 on theBenchmark for (2999ds/16Mi)
% 1.44/0.56 % (24366)Refutation found. Thanks to Tanya!
% 1.44/0.56 % SZS status Theorem for theBenchmark
% 1.44/0.56 % SZS output start Proof for theBenchmark
% See solution above
% 1.44/0.56 % (24366)------------------------------
% 1.44/0.56 % (24366)Version: Vampire 4.7 (commit 807e37dd9 on 2022-08-23 09:55:27 +0200)
% 1.44/0.56 % (24366)Linked with Z3 4.8.13.0 f03d756e086f81f2596157241e0decfb1c982299 z3-4.8.4-5390-gf03d756e0
% 1.44/0.56 % (24366)Termination reason: Refutation
% 1.44/0.56
% 1.44/0.56 % (24366)Memory used [KB]: 6012
% 1.44/0.56 % (24366)Time elapsed: 0.134 s
% 1.44/0.56 % (24366)Instructions burned: 3 (million)
% 1.44/0.56 % (24366)------------------------------
% 1.44/0.56 % (24366)------------------------------
% 1.44/0.56 % (24358)Success in time 0.2 s
%------------------------------------------------------------------------------