TSTP Solution File: RNG099+1 by SPASS---3.9

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : SPASS---3.9
% Problem  : RNG099+1 : TPTP v8.1.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp
% Command  : run_spass %d %s

% Computer : n020.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Mon Jul 18 20:41:28 EDT 2022

% Result   : Theorem 0.19s 0.55s
% Output   : Refutation 0.19s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    7
%            Number of leaves      :   15
% Syntax   : Number of clauses     :   28 (  16 unt;   0 nHn;  28 RR)
%            Number of literals    :   52 (   0 equ;  27 neg)
%            Maximal clause size   :    5 (   1 avg)
%            Maximal term depth    :    3 (   1 avg)
%            Number of predicates  :    7 (   6 usr;   1 prp; 0-3 aty)
%            Number of functors    :   13 (  13 usr;  10 con; 0-2 aty)
%            Number of variables   :    0 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(3,axiom,
    aIdeal0(xI),
    file('RNG099+1.p',unknown),
    [] ).

cnf(4,axiom,
    aIdeal0(xJ),
    file('RNG099+1.p',unknown),
    [] ).

cnf(5,axiom,
    aElement0(xx),
    file('RNG099+1.p',unknown),
    [] ).

cnf(6,axiom,
    aElement0(xy),
    file('RNG099+1.p',unknown),
    [] ).

cnf(8,axiom,
    aElementOf0(xa,xI),
    file('RNG099+1.p',unknown),
    [] ).

cnf(9,axiom,
    aElementOf0(xb,xJ),
    file('RNG099+1.p',unknown),
    [] ).

cnf(11,axiom,
    ( ~ aIdeal0(u)
    | aSet0(u) ),
    file('RNG099+1.p',unknown),
    [] ).

cnf(14,axiom,
    aElementOf0(sdtpldt0(xw,smndt0(xx)),xI),
    file('RNG099+1.p',unknown),
    [] ).

cnf(15,axiom,
    aElementOf0(sdtpldt0(xw,smndt0(xy)),xJ),
    file('RNG099+1.p',unknown),
    [] ).

cnf(26,axiom,
    ( ~ aSet0(u)
    | ~ aElementOf0(v,u)
    | aElement0(v) ),
    file('RNG099+1.p',unknown),
    [] ).

cnf(29,axiom,
    equal(sdtpldt0(sdtasdt0(xy,xa),sdtasdt0(xx,xb)),xw),
    file('RNG099+1.p',unknown),
    [] ).

cnf(30,axiom,
    ( ~ aElement0(u)
    | ~ aElement0(v)
    | aElement0(sdtpldt0(v,u)) ),
    file('RNG099+1.p',unknown),
    [] ).

cnf(31,axiom,
    ( ~ aElement0(u)
    | ~ aElement0(v)
    | aElement0(sdtasdt0(v,u)) ),
    file('RNG099+1.p',unknown),
    [] ).

cnf(38,axiom,
    ( ~ aElement0(u)
    | ~ sdteqdtlpzmzozddtrp0(u,xy,xJ)
    | ~ sdteqdtlpzmzozddtrp0(u,xx,xI) ),
    file('RNG099+1.p',unknown),
    [] ).

cnf(52,axiom,
    ( ~ aIdeal0(u)
    | ~ aElement0(v)
    | ~ aElement0(w)
    | ~ aElementOf0(sdtpldt0(w,smndt0(v)),u)
    | sdteqdtlpzmzozddtrp0(w,v,u) ),
    file('RNG099+1.p',unknown),
    [] ).

cnf(94,plain,
    ( ~ aSet0(xJ)
    | aElement0(xb) ),
    inference(res,[status(thm),theory(equality)],[9,26]),
    [iquote('0:Res:9.0,26.1')] ).

cnf(96,plain,
    ( ~ aSet0(xI)
    | aElement0(xa) ),
    inference(res,[status(thm),theory(equality)],[8,26]),
    [iquote('0:Res:8.0,26.1')] ).

cnf(101,plain,
    aElement0(xb),
    inference(ssi,[status(thm)],[94,11,4]),
    [iquote('0:SSi:94.0,11.0,4.1')] ).

cnf(102,plain,
    aElement0(xa),
    inference(ssi,[status(thm)],[96,11,3]),
    [iquote('0:SSi:96.0,11.0,3.1')] ).

cnf(129,plain,
    ( ~ aElement0(sdtasdt0(xx,xb))
    | ~ aElement0(sdtasdt0(xy,xa))
    | aElement0(xw) ),
    inference(spr,[status(thm),theory(equality)],[29,30]),
    [iquote('0:SpR:29.0,30.2')] ).

cnf(132,plain,
    aElement0(xw),
    inference(ssi,[status(thm)],[129,31,6,102,5,101]),
    [iquote('0:SSi:129.1,129.0,31.0,6.0,102.2,31.0,5.0,101.2')] ).

cnf(660,plain,
    ( ~ aIdeal0(xJ)
    | ~ aElement0(xy)
    | ~ aElement0(xw)
    | sdteqdtlpzmzozddtrp0(xw,xy,xJ) ),
    inference(res,[status(thm),theory(equality)],[15,52]),
    [iquote('0:Res:15.0,52.3')] ).

cnf(661,plain,
    ( ~ aIdeal0(xI)
    | ~ aElement0(xx)
    | ~ aElement0(xw)
    | sdteqdtlpzmzozddtrp0(xw,xx,xI) ),
    inference(res,[status(thm),theory(equality)],[14,52]),
    [iquote('0:Res:14.0,52.3')] ).

cnf(664,plain,
    sdteqdtlpzmzozddtrp0(xw,xy,xJ),
    inference(ssi,[status(thm)],[660,132,6,4]),
    [iquote('0:SSi:660.2,660.1,660.0,132.0,6.0,4.0')] ).

cnf(665,plain,
    sdteqdtlpzmzozddtrp0(xw,xx,xI),
    inference(ssi,[status(thm)],[661,132,5,3]),
    [iquote('0:SSi:661.2,661.1,661.0,132.0,5.0,3.0')] ).

cnf(677,plain,
    ( ~ aElement0(xw)
    | ~ sdteqdtlpzmzozddtrp0(xw,xx,xI) ),
    inference(res,[status(thm),theory(equality)],[664,38]),
    [iquote('0:Res:664.0,38.1')] ).

cnf(678,plain,
    ~ sdteqdtlpzmzozddtrp0(xw,xx,xI),
    inference(ssi,[status(thm)],[677,132]),
    [iquote('0:SSi:677.0,132.0')] ).

cnf(679,plain,
    $false,
    inference(mrr,[status(thm)],[678,665]),
    [iquote('0:MRR:678.0,665.0')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.10/0.11  % Problem  : RNG099+1 : TPTP v8.1.0. Released v4.0.0.
% 0.10/0.12  % Command  : run_spass %d %s
% 0.13/0.33  % Computer : n020.cluster.edu
% 0.13/0.33  % Model    : x86_64 x86_64
% 0.13/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.33  % Memory   : 8042.1875MB
% 0.13/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.33  % CPULimit : 300
% 0.13/0.33  % WCLimit  : 600
% 0.13/0.33  % DateTime : Mon May 30 08:25:54 EDT 2022
% 0.13/0.33  % CPUTime  : 
% 0.19/0.55  
% 0.19/0.55  SPASS V 3.9 
% 0.19/0.55  SPASS beiseite: Proof found.
% 0.19/0.55  % SZS status Theorem
% 0.19/0.55  Problem: /export/starexec/sandbox2/benchmark/theBenchmark.p 
% 0.19/0.55  SPASS derived 417 clauses, backtracked 0 clauses, performed 1 splits and kept 216 clauses.
% 0.19/0.55  SPASS allocated 98815 KBytes.
% 0.19/0.55  SPASS spent	0:00:00.20 on the problem.
% 0.19/0.55  		0:00:00.03 for the input.
% 0.19/0.55  		0:00:00.10 for the FLOTTER CNF translation.
% 0.19/0.55  		0:00:00.01 for inferences.
% 0.19/0.55  		0:00:00.00 for the backtracking.
% 0.19/0.55  		0:00:00.03 for the reduction.
% 0.19/0.55  
% 0.19/0.55  
% 0.19/0.55  Here is a proof with depth 2, length 28 :
% 0.19/0.55  % SZS output start Refutation
% See solution above
% 0.19/0.55  Formulae used in the proof : m__1205 m__1217 m__1294 mDefIdeal m__1332 m__1409 mEOfElem m__1319 mSortsB mSortsB_02 m__ mDefMod
% 0.19/0.55  
%------------------------------------------------------------------------------