%------------------------------------------------------------------------------
% File     : SPASS---3.9
% Problem  : RNG089+2 : TPTP v8.1.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp
% Command  : run_spass %d %s

% Computer : n020.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Mon Jul 18 20:41:26 EDT 2022

% Result   : Theorem 0.20s 0.52s
% Output   : Refutation 0.20s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    6
%            Number of leaves      :    6
% Syntax   : Number of clauses     :   12 (   6 unt;   0 nHn;  12 RR)
%            Number of literals    :   21 (   0 equ;  15 neg)
%            Maximal clause size   :    3 (   1 avg)
%            Maximal term depth    :    2 (   1 avg)
%            Number of predicates  :    3 (   2 usr;   1 prp; 0-2 aty)
%            Number of functors    :    8 (   8 usr;   7 con; 0-2 aty)
%            Number of variables   :    0 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(7,axiom,
    aElement0(xz),
    file('RNG089+2.p',unknown),
    [] ).

cnf(13,axiom,
    aElementOf0(xk,xI),
    file('RNG089+2.p',unknown),
    [] ).

cnf(14,axiom,
    aElementOf0(xl,xJ),
    file('RNG089+2.p',unknown),
    [] ).

cnf(46,axiom,
    ( ~ aElementOf0(sdtasdt0(xz,xl),xJ)
    | ~ aElementOf0(sdtasdt0(xz,xk),xI) ),
    file('RNG089+2.p',unknown),
    [] ).

cnf(47,axiom,
    ( ~ aElement0(u)
    | ~ aElementOf0(v,xI)
    | aElementOf0(sdtasdt0(u,v),xI) ),
    file('RNG089+2.p',unknown),
    [] ).

cnf(48,axiom,
    ( ~ aElement0(u)
    | ~ aElementOf0(v,xJ)
    | aElementOf0(sdtasdt0(u,v),xJ) ),
    file('RNG089+2.p',unknown),
    [] ).

cnf(163,plain,
    ( ~ aElement0(xz)
    | ~ aElementOf0(xl,xJ)
    | ~ aElementOf0(sdtasdt0(xz,xk),xI) ),
    inference(res,[status(thm),theory(equality)],[48,46]),
    [iquote('0:Res:48.2,46.0')] ).

cnf(167,plain,
    ( ~ aElementOf0(xl,xJ)
    | ~ aElementOf0(sdtasdt0(xz,xk),xI) ),
    inference(ssi,[status(thm)],[163,7]),
    [iquote('0:SSi:163.0,7.0')] ).

cnf(168,plain,
    ~ aElementOf0(sdtasdt0(xz,xk),xI),
    inference(mrr,[status(thm)],[167,14]),
    [iquote('0:MRR:167.0,14.0')] ).

cnf(187,plain,
    ( ~ aElement0(xz)
    | ~ aElementOf0(xk,xI) ),
    inference(res,[status(thm),theory(equality)],[47,168]),
    [iquote('0:Res:47.2,168.0')] ).

cnf(189,plain,
    ~ aElementOf0(xk,xI),
    inference(ssi,[status(thm)],[187,7]),
    [iquote('0:SSi:187.0,7.0')] ).

cnf(190,plain,
    $false,
    inference(mrr,[status(thm)],[189,13]),
    [iquote('0:MRR:189.0,13.0')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.11/0.12  % Problem  : RNG089+2 : TPTP v8.1.0. Released v4.0.0.
% 0.11/0.13  % Command  : run_spass %d %s
% 0.13/0.34  % Computer : n020.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit : 300
% 0.13/0.34  % WCLimit  : 600
% 0.13/0.34  % DateTime : Mon May 30 10:09:54 EDT 2022
% 0.13/0.35  % CPUTime  : 
% 0.20/0.52  
% 0.20/0.52  SPASS V 3.9 
% 0.20/0.52  SPASS beiseite: Proof found.
% 0.20/0.52  % SZS status Theorem
% 0.20/0.52  Problem: /export/starexec/sandbox2/benchmark/theBenchmark.p 
% 0.20/0.52  SPASS derived 85 clauses, backtracked 0 clauses, performed 0 splits and kept 109 clauses.
% 0.20/0.52  SPASS allocated 98763 KBytes.
% 0.20/0.52  SPASS spent	0:00:00.16 on the problem.
% 0.20/0.52  		0:00:00.04 for the input.
% 0.20/0.52  		0:00:00.09 for the FLOTTER CNF translation.
% 0.20/0.52  		0:00:00.00 for inferences.
% 0.20/0.52  		0:00:00.00 for the backtracking.
% 0.20/0.52  		0:00:00.01 for the reduction.
% 0.20/0.52  
% 0.20/0.52  
% 0.20/0.52  Here is a proof with depth 2, length 12 :
% 0.20/0.52  % SZS output start Refutation
% See solution above
% 0.20/0.52  Formulae used in the proof : m__901 m__934 m__ m__870
% 0.20/0.52  
%------------------------------------------------------------------------------