%------------------------------------------------------------------------------
% File     : SPASS---3.9
% Problem  : RNG088+1 : TPTP v8.1.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp
% Command  : run_spass %d %s

% Computer : n025.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Mon Jul 18 20:41:26 EDT 2022

% Result   : Theorem 0.20s 0.54s
% Output   : Refutation 0.20s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    6
%            Number of leaves      :    8
% Syntax   : Number of clauses     :   14 (   8 unt;   0 nHn;  14 RR)
%            Number of literals    :   26 (   0 equ;  18 neg)
%            Maximal clause size   :    4 (   1 avg)
%            Maximal term depth    :    2 (   1 avg)
%            Number of predicates  :    3 (   2 usr;   1 prp; 0-2 aty)
%            Number of functors    :   10 (  10 usr;   9 con; 0-2 aty)
%            Number of variables   :    0 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(3,axiom,
    aIdeal0(xI),
    file('RNG088+1.p',unknown),
    [] ).

cnf(4,axiom,
    aIdeal0(xJ),
    file('RNG088+1.p',unknown),
    [] ).

cnf(7,axiom,
    aElementOf0(xk,xI),
    file('RNG088+1.p',unknown),
    [] ).

cnf(8,axiom,
    aElementOf0(xl,xJ),
    file('RNG088+1.p',unknown),
    [] ).

cnf(9,axiom,
    aElementOf0(xm,xI),
    file('RNG088+1.p',unknown),
    [] ).

cnf(10,axiom,
    aElementOf0(xn,xJ),
    file('RNG088+1.p',unknown),
    [] ).

cnf(36,axiom,
    ( ~ aElementOf0(sdtpldt0(xl,xn),xJ)
    | ~ aElementOf0(sdtpldt0(xk,xm),xI) ),
    file('RNG088+1.p',unknown),
    [] ).

cnf(43,axiom,
    ( ~ aIdeal0(u)
    | ~ aElementOf0(v,u)
    | ~ aElementOf0(w,u)
    | aElementOf0(sdtpldt0(w,v),u) ),
    file('RNG088+1.p',unknown),
    [] ).

cnf(220,plain,
    ( ~ aIdeal0(xJ)
    | ~ aElementOf0(xn,xJ)
    | ~ aElementOf0(xl,xJ)
    | ~ aElementOf0(sdtpldt0(xk,xm),xI) ),
    inference(res,[status(thm),theory(equality)],[43,36]),
    [iquote('0:Res:43.3,36.0')] ).

cnf(222,plain,
    ( ~ aElementOf0(xn,xJ)
    | ~ aElementOf0(xl,xJ)
    | ~ aElementOf0(sdtpldt0(xk,xm),xI) ),
    inference(ssi,[status(thm)],[220,4]),
    [iquote('0:SSi:220.0,4.0')] ).

cnf(223,plain,
    ~ aElementOf0(sdtpldt0(xk,xm),xI),
    inference(mrr,[status(thm)],[222,10,8]),
    [iquote('0:MRR:222.0,222.1,10.0,8.0')] ).

cnf(226,plain,
    ( ~ aIdeal0(xI)
    | ~ aElementOf0(xm,xI)
    | ~ aElementOf0(xk,xI) ),
    inference(res,[status(thm),theory(equality)],[43,223]),
    [iquote('0:Res:43.3,223.0')] ).

cnf(227,plain,
    ( ~ aElementOf0(xm,xI)
    | ~ aElementOf0(xk,xI) ),
    inference(ssi,[status(thm)],[226,3]),
    [iquote('0:SSi:226.0,3.0')] ).

cnf(228,plain,
    $false,
    inference(mrr,[status(thm)],[227,9,7]),
    [iquote('0:MRR:227.0,227.1,9.0,7.0')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.13  % Problem  : RNG088+1 : TPTP v8.1.0. Released v4.0.0.
% 0.07/0.13  % Command  : run_spass %d %s
% 0.13/0.35  % Computer : n025.cluster.edu
% 0.13/0.35  % Model    : x86_64 x86_64
% 0.13/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.35  % Memory   : 8042.1875MB
% 0.13/0.35  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.35  % CPULimit : 300
% 0.13/0.35  % WCLimit  : 600
% 0.13/0.35  % DateTime : Mon May 30 22:22:27 EDT 2022
% 0.13/0.35  % CPUTime  : 
% 0.20/0.54  
% 0.20/0.54  SPASS V 3.9 
% 0.20/0.54  SPASS beiseite: Proof found.
% 0.20/0.54  % SZS status Theorem
% 0.20/0.54  Problem: /export/starexec/sandbox2/benchmark/theBenchmark.p 
% 0.20/0.54  SPASS derived 114 clauses, backtracked 0 clauses, performed 0 splits and kept 94 clauses.
% 0.20/0.54  SPASS allocated 98832 KBytes.
% 0.20/0.54  SPASS spent	0:00:00.18 on the problem.
% 0.20/0.54  		0:00:00.04 for the input.
% 0.20/0.54  		0:00:00.11 for the FLOTTER CNF translation.
% 0.20/0.54  		0:00:00.00 for inferences.
% 0.20/0.54  		0:00:00.00 for the backtracking.
% 0.20/0.54  		0:00:00.01 for the reduction.
% 0.20/0.54  
% 0.20/0.54  
% 0.20/0.54  Here is a proof with depth 2, length 14 :
% 0.20/0.54  % SZS output start Refutation
% See solution above
% 0.20/0.54  Formulae used in the proof : m__870 m__934 m__967 m__ mDefIdeal m__901
% 0.20/0.54  
%------------------------------------------------------------------------------