TSTP Solution File: RNG074+1 by Duper---1.0

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : RNG074+1 : TPTP v8.1.2. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n021.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 13:51:17 EDT 2023

% Result   : Theorem 6.58s 6.76s
% Output   : Proof 6.58s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.11  % Problem    : RNG074+1 : TPTP v8.1.2. Released v4.0.0.
% 0.00/0.12  % Command    : duper %s
% 0.10/0.32  % Computer : n021.cluster.edu
% 0.10/0.32  % Model    : x86_64 x86_64
% 0.10/0.32  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.10/0.32  % Memory   : 8042.1875MB
% 0.10/0.32  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.10/0.32  % CPULimit   : 300
% 0.10/0.32  % WCLimit    : 300
% 0.10/0.32  % DateTime   : Sun Aug 27 02:06:57 EDT 2023
% 0.10/0.32  % CPUTime    : 
% 6.58/6.76  SZS status Theorem for theBenchmark.p
% 6.58/6.76  SZS output start Proof for theBenchmark.p
% 6.58/6.76  Clause #59 (by assumption #[]): Eq (Not (sdtlseqdt0 (sdtpldt0 xP xP) (sdtpldt0 xR xS))) True
% 6.58/6.76  Clause #60 (by assumption #[]): Eq (sdtlseqdt0 (sdtpldt0 xR xS) (sdtpldt0 xP xP)) True
% 6.58/6.76  Clause #63 (by assumption #[]): Eq (Eq (sdtpldt0 xR xS) (sdtpldt0 xP xP)) True
% 6.58/6.76  Clause #406 (by clausification #[59]): Eq (sdtlseqdt0 (sdtpldt0 xP xP) (sdtpldt0 xR xS)) False
% 6.58/6.76  Clause #407 (by clausification #[63]): Eq (sdtpldt0 xR xS) (sdtpldt0 xP xP)
% 6.58/6.76  Clause #408 (by backward demodulation #[407, 60]): Eq (sdtlseqdt0 (sdtpldt0 xP xP) (sdtpldt0 xP xP)) True
% 6.58/6.76  Clause #409 (by backward demodulation #[407, 406]): Eq (sdtlseqdt0 (sdtpldt0 xP xP) (sdtpldt0 xP xP)) False
% 6.58/6.76  Clause #410 (by superposition #[408, 409]): Eq False True
% 6.58/6.76  Clause #417 (by clausification #[410]): False
% 6.58/6.76  SZS output end Proof for theBenchmark.p
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