TSTP Solution File: RNG072+2 by SPASS---3.9
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%------------------------------------------------------------------------------
% File : SPASS---3.9
% Problem : RNG072+2 : TPTP v8.1.0. Released v4.0.0.
% Transfm : none
% Format : tptp
% Command : run_spass %d %s
% Computer : n027.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Mon Jul 18 20:41:23 EDT 2022
% Result : Theorem 0.18s 0.44s
% Output : Refutation 0.18s
% Verified :
% SZS Type : Refutation
% Derivation depth : 6
% Number of leaves : 8
% Syntax : Number of clauses : 14 ( 7 unt; 0 nHn; 14 RR)
% Number of literals : 36 ( 0 equ; 28 neg)
% Maximal clause size : 8 ( 2 avg)
% Maximal term depth : 3 ( 1 avg)
% Number of predicates : 3 ( 2 usr; 1 prp; 0-2 aty)
% Number of functors : 10 ( 10 usr; 8 con; 0-2 aty)
% Number of variables : 0 ( 0 sgn)
% Comments :
%------------------------------------------------------------------------------
cnf(15,axiom,
aScalar0(xR),
file('RNG072+2.p',unknown),
[] ).
cnf(16,axiom,
aScalar0(xP),
file('RNG072+2.p',unknown),
[] ).
cnf(17,axiom,
aScalar0(xS),
file('RNG072+2.p',unknown),
[] ).
cnf(36,axiom,
sdtlseqdt0(sz0z00,sdtpldt0(xR,xS)),
file('RNG072+2.p',unknown),
[] ).
cnf(49,axiom,
sdtlseqdt0(sdtpldt0(xR,xS),sdtpldt0(xP,xP)),
file('RNG072+2.p',unknown),
[] ).
cnf(61,axiom,
( ~ aScalar0(u)
| ~ aScalar0(v)
| aScalar0(sdtpldt0(v,u)) ),
file('RNG072+2.p',unknown),
[] ).
cnf(77,axiom,
~ sdtlseqdt0(sdtasdt0(sdtpldt0(xR,xS),sdtpldt0(xR,xS)),sdtasdt0(sdtpldt0(xP,xP),sdtpldt0(xP,xP))),
file('RNG072+2.p',unknown),
[] ).
cnf(93,axiom,
( ~ aScalar0(u)
| ~ aScalar0(v)
| ~ aScalar0(w)
| ~ aScalar0(x)
| ~ sdtlseqdt0(x,w)
| ~ sdtlseqdt0(v,u)
| ~ sdtlseqdt0(sz0z00,v)
| sdtlseqdt0(sdtasdt0(x,v),sdtasdt0(w,u)) ),
file('RNG072+2.p',unknown),
[] ).
cnf(100,plain,
( ~ aScalar0(sdtpldt0(xR,xS))
| ~ aScalar0(sdtpldt0(xP,xP))
| ~ aScalar0(sdtpldt0(xR,xS))
| ~ aScalar0(sdtpldt0(xP,xP))
| ~ sdtlseqdt0(sz0z00,sdtpldt0(xR,xS))
| ~ sdtlseqdt0(sdtpldt0(xR,xS),sdtpldt0(xP,xP))
| ~ sdtlseqdt0(sdtpldt0(xR,xS),sdtpldt0(xP,xP)) ),
inference(res,[status(thm),theory(equality)],[93,77]),
[iquote('0:Res:93.7,77.0')] ).
cnf(104,plain,
( ~ aScalar0(sdtpldt0(xR,xS))
| ~ aScalar0(sdtpldt0(xP,xP))
| ~ sdtlseqdt0(sz0z00,sdtpldt0(xR,xS))
| ~ sdtlseqdt0(sdtpldt0(xR,xS),sdtpldt0(xP,xP)) ),
inference(obv,[status(thm),theory(equality)],[100]),
[iquote('0:Obv:100.5')] ).
cnf(105,plain,
( ~ aScalar0(sdtpldt0(xP,xP))
| ~ aScalar0(sdtpldt0(xR,xS)) ),
inference(mrr,[status(thm)],[104,36,49]),
[iquote('0:MRR:104.2,104.3,36.0,49.0')] ).
cnf(202,plain,
( ~ aScalar0(sdtpldt0(xR,xS))
| ~ aScalar0(xP)
| ~ aScalar0(xP) ),
inference(sor,[status(thm)],[105,61]),
[iquote('0:SoR:105.0,61.2')] ).
cnf(208,plain,
( ~ aScalar0(sdtpldt0(xR,xS))
| ~ aScalar0(xP) ),
inference(obv,[status(thm),theory(equality)],[202]),
[iquote('0:Obv:202.1')] ).
cnf(209,plain,
$false,
inference(ssi,[status(thm)],[208,16,61,15,17]),
[iquote('0:SSi:208.1,208.0,16.0,61.0,15.2,17.0')] ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.11 % Problem : RNG072+2 : TPTP v8.1.0. Released v4.0.0.
% 0.00/0.12 % Command : run_spass %d %s
% 0.12/0.33 % Computer : n027.cluster.edu
% 0.12/0.33 % Model : x86_64 x86_64
% 0.12/0.33 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33 % Memory : 8042.1875MB
% 0.12/0.33 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33 % CPULimit : 300
% 0.12/0.33 % WCLimit : 600
% 0.12/0.33 % DateTime : Mon May 30 08:35:46 EDT 2022
% 0.12/0.33 % CPUTime :
% 0.18/0.44
% 0.18/0.44 SPASS V 3.9
% 0.18/0.44 SPASS beiseite: Proof found.
% 0.18/0.44 % SZS status Theorem
% 0.18/0.44 Problem: /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.18/0.44 SPASS derived 91 clauses, backtracked 0 clauses, performed 0 splits and kept 113 clauses.
% 0.18/0.44 SPASS allocated 97891 KBytes.
% 0.18/0.44 SPASS spent 0:00:00.10 on the problem.
% 0.18/0.44 0:00:00.04 for the input.
% 0.18/0.44 0:00:00.03 for the FLOTTER CNF translation.
% 0.18/0.44 0:00:00.00 for inferences.
% 0.18/0.44 0:00:00.00 for the backtracking.
% 0.18/0.44 0:00:00.01 for the reduction.
% 0.18/0.44
% 0.18/0.44
% 0.18/0.44 Here is a proof with depth 2, length 14 :
% 0.18/0.44 % SZS output start Refutation
% See solution above
% 0.18/0.44 Formulae used in the proof : m__1892 m__1911 m__1930 m__2628 m__2610 mSumSc m__ mLEMonM
% 0.18/0.44
%------------------------------------------------------------------------------