TSTP Solution File: RNG070+2 by SPASS---3.9

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : SPASS---3.9
% Problem  : RNG070+2 : TPTP v8.1.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp
% Command  : run_spass %d %s

% Computer : n018.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Mon Jul 18 20:41:23 EDT 2022

% Result   : Theorem 0.19s 0.45s
% Output   : Refutation 0.19s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    5
%            Number of leaves      :    7
% Syntax   : Number of clauses     :   12 (   6 unt;   1 nHn;  12 RR)
%            Number of literals    :   23 (   0 equ;  15 neg)
%            Maximal clause size   :    4 (   1 avg)
%            Maximal term depth    :    2 (   1 avg)
%            Number of predicates  :    3 (   2 usr;   1 prp; 0-2 aty)
%            Number of functors    :    6 (   6 usr;   5 con; 0-2 aty)
%            Number of variables   :    0 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(15,axiom,
    aScalar0(xR),
    file('RNG070+2.p',unknown),
    [] ).

cnf(16,axiom,
    aScalar0(xP),
    file('RNG070+2.p',unknown),
    [] ).

cnf(17,axiom,
    aScalar0(xS),
    file('RNG070+2.p',unknown),
    [] ).

cnf(47,axiom,
    ~ sdtlseqdt0(sdtpldt0(xR,xS),sdtpldt0(xP,xP)),
    file('RNG070+2.p',unknown),
    [] ).

cnf(56,axiom,
    ~ sdtlseqdt0(sdtpldt0(xP,xP),sdtpldt0(xR,xS)),
    file('RNG070+2.p',unknown),
    [] ).

cnf(59,axiom,
    ( ~ aScalar0(u)
    | ~ aScalar0(v)
    | aScalar0(sdtpldt0(v,u)) ),
    file('RNG070+2.p',unknown),
    [] ).

cnf(65,axiom,
    ( ~ aScalar0(u)
    | ~ aScalar0(v)
    | sdtlseqdt0(u,v)
    | sdtlseqdt0(v,u) ),
    file('RNG070+2.p',unknown),
    [] ).

cnf(97,plain,
    ( ~ aScalar0(sdtpldt0(xR,xS))
    | ~ aScalar0(sdtpldt0(xP,xP))
    | sdtlseqdt0(sdtpldt0(xP,xP),sdtpldt0(xR,xS)) ),
    inference(res,[status(thm),theory(equality)],[65,47]),
    [iquote('0:Res:65.2,47.0')] ).

cnf(101,plain,
    ( ~ aScalar0(sdtpldt0(xP,xP))
    | ~ aScalar0(sdtpldt0(xR,xS)) ),
    inference(mrr,[status(thm)],[97,56]),
    [iquote('0:MRR:97.2,56.0')] ).

cnf(200,plain,
    ( ~ aScalar0(sdtpldt0(xR,xS))
    | ~ aScalar0(xP)
    | ~ aScalar0(xP) ),
    inference(sor,[status(thm)],[101,59]),
    [iquote('0:SoR:101.0,59.2')] ).

cnf(206,plain,
    ( ~ aScalar0(sdtpldt0(xR,xS))
    | ~ aScalar0(xP) ),
    inference(obv,[status(thm),theory(equality)],[200]),
    [iquote('0:Obv:200.1')] ).

cnf(207,plain,
    $false,
    inference(ssi,[status(thm)],[206,16,59,15,17]),
    [iquote('0:SSi:206.1,206.0,16.0,59.0,15.2,17.0')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.12  % Problem  : RNG070+2 : TPTP v8.1.0. Released v4.0.0.
% 0.03/0.12  % Command  : run_spass %d %s
% 0.12/0.33  % Computer : n018.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit : 300
% 0.12/0.33  % WCLimit  : 600
% 0.12/0.33  % DateTime : Mon May 30 08:29:56 EDT 2022
% 0.12/0.33  % CPUTime  : 
% 0.19/0.45  
% 0.19/0.45  SPASS V 3.9 
% 0.19/0.45  SPASS beiseite: Proof found.
% 0.19/0.45  % SZS status Theorem
% 0.19/0.45  Problem: /export/starexec/sandbox2/benchmark/theBenchmark.p 
% 0.19/0.45  SPASS derived 91 clauses, backtracked 0 clauses, performed 0 splits and kept 110 clauses.
% 0.19/0.45  SPASS allocated 97883 KBytes.
% 0.19/0.45  SPASS spent	0:00:00.11 on the problem.
% 0.19/0.45  		0:00:00.03 for the input.
% 0.19/0.45  		0:00:00.04 for the FLOTTER CNF translation.
% 0.19/0.45  		0:00:00.00 for inferences.
% 0.19/0.45  		0:00:00.00 for the backtracking.
% 0.19/0.45  		0:00:00.01 for the reduction.
% 0.19/0.45  
% 0.19/0.45  
% 0.19/0.45  Here is a proof with depth 2, length 12 :
% 0.19/0.45  % SZS output start Refutation
% See solution above
% 0.19/0.45  Formulae used in the proof : m__1892 m__1911 m__1930 m__ m__2590 mSumSc mLETot
% 0.19/0.45  
%------------------------------------------------------------------------------