TSTP Solution File: RNG005-2 by SPASS---3.9

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : SPASS---3.9
% Problem  : RNG005-2 : TPTP v8.1.0. Released v1.0.0.
% Transfm  : none
% Format   : tptp
% Command  : run_spass %d %s

% Computer : n029.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Mon Jul 18 20:41:10 EDT 2022

% Result   : Unsatisfiable 4.80s 5.00s
% Output   : Refutation 4.84s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    5
%            Number of leaves      :    6
% Syntax   : Number of clauses     :   11 (   7 unt;   0 nHn;  11 RR)
%            Number of literals    :   21 (   0 equ;  15 neg)
%            Maximal clause size   :    5 (   1 avg)
%            Maximal term depth    :    2 (   1 avg)
%            Number of predicates  :    3 (   2 usr;   1 prp; 0-3 aty)
%            Number of functors    :   13 (  13 usr;  12 con; 0-1 aty)
%            Number of variables   :    0 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(14,axiom,
    sum__dfg(additive_inverse(u),u,additive_identity),
    file('RNG005-2.p',unknown),
    [] ).

cnf(23,axiom,
    ( ~ product(u,v,w)
    | ~ sum__dfg(x,y,u)
    | ~ product(y,v,z)
    | ~ product(x,v,x1)
    | sum__dfg(x1,z,w) ),
    file('RNG005-2.p',unknown),
    [] ).

cnf(27,axiom,
    product(additive_identity,u,additive_identity),
    file('RNG005-2.p',unknown),
    [] ).

cnf(29,axiom,
    product(a,b,d),
    file('RNG005-2.p',unknown),
    [] ).

cnf(30,axiom,
    product(additive_inverse(a),b,c),
    file('RNG005-2.p',unknown),
    [] ).

cnf(31,axiom,
    ~ sum__dfg(c,d,additive_identity),
    file('RNG005-2.p',unknown),
    [] ).

cnf(38,plain,
    ( ~ sum__dfg(u,v,w)
    | ~ product(w,x,additive_identity)
    | ~ product(v,x,d)
    | ~ product(u,x,c) ),
    inference(res,[status(thm),theory(equality)],[23,31]),
    [iquote('0:Res:23.4,31.0')] ).

cnf(2834,plain,
    ( ~ product(additive_identity,u,additive_identity)
    | ~ product(v,u,d)
    | ~ product(additive_inverse(v),u,c) ),
    inference(res,[status(thm),theory(equality)],[14,38]),
    [iquote('0:Res:14.0,38.0')] ).

cnf(2875,plain,
    ( ~ product(u,v,d)
    | ~ product(additive_inverse(u),v,c) ),
    inference(mrr,[status(thm)],[2834,27]),
    [iquote('0:MRR:2834.0,27.0')] ).

cnf(8220,plain,
    ~ product(a,b,d),
    inference(res,[status(thm),theory(equality)],[30,2875]),
    [iquote('0:Res:30.0,2875.1')] ).

cnf(8227,plain,
    $false,
    inference(mrr,[status(thm)],[8220,29]),
    [iquote('0:MRR:8220.0,29.0')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.11/0.12  % Problem  : RNG005-2 : TPTP v8.1.0. Released v1.0.0.
% 0.11/0.13  % Command  : run_spass %d %s
% 0.14/0.34  % Computer : n029.cluster.edu
% 0.14/0.34  % Model    : x86_64 x86_64
% 0.14/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.34  % Memory   : 8042.1875MB
% 0.14/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.14/0.34  % CPULimit : 300
% 0.14/0.34  % WCLimit  : 600
% 0.14/0.34  % DateTime : Mon May 30 17:54:59 EDT 2022
% 0.14/0.34  % CPUTime  : 
% 4.80/5.00  
% 4.80/5.00  SPASS V 3.9 
% 4.80/5.00  SPASS beiseite: Proof found.
% 4.80/5.00  % SZS status Theorem
% 4.80/5.00  Problem: /export/starexec/sandbox2/benchmark/theBenchmark.p 
% 4.80/5.00  SPASS derived 8008 clauses, backtracked 0 clauses, performed 0 splits and kept 5299 clauses.
% 4.80/5.00  SPASS allocated 68615 KBytes.
% 4.80/5.00  SPASS spent	0:00:04.60 on the problem.
% 4.80/5.00  		0:00:00.03 for the input.
% 4.80/5.00  		0:00:00.00 for the FLOTTER CNF translation.
% 4.80/5.00  		0:00:00.06 for inferences.
% 4.80/5.00  		0:00:00.00 for the backtracking.
% 4.80/5.00  		0:00:04.45 for the reduction.
% 4.80/5.00  
% 4.80/5.00  
% 4.80/5.00  Here is a proof with depth 3, length 11 :
% 4.80/5.00  % SZS output start Refutation
% See solution above
% 4.84/5.00  Formulae used in the proof : left_inverse distributivity3 multiplicative_identity1 a_times_b a_inverse_times_b prove_sum_is_additive_identity
% 4.84/5.00  
%------------------------------------------------------------------------------