TSTP Solution File: PUZ132+1 by Otter---3.3

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Otter---3.3
% Problem  : PUZ132+1 : TPTP v8.1.0. Released v4.1.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : otter-tptp-script %s

% Computer : n007.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Wed Jul 27 13:11:40 EDT 2022

% Result   : Theorem 1.72s 1.90s
% Output   : Refutation 1.72s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    3
%            Number of leaves      :    7
% Syntax   : Number of clauses     :   11 (   7 unt;   0 nHn;  11 RR)
%            Number of literals    :   15 (   1 equ;   5 neg)
%            Maximal clause size   :    2 (   1 avg)
%            Maximal term depth    :    2 (   1 avg)
%            Number of predicates  :    7 (   5 usr;   1 prp; 0-2 aty)
%            Number of functors    :    3 (   3 usr;   2 con; 0-1 aty)
%            Number of variables   :    3 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(1,axiom,
    ( ~ capital(A)
    | city(A) ),
    file('PUZ132+1.p',unknown),
    [] ).

cnf(3,axiom,
    ( ~ city(A)
    | has_crime(A) ),
    file('PUZ132+1.p',unknown),
    [] ).

cnf(4,axiom,
    ( ~ country(A)
    | beautiful(capital_city(A)) ),
    file('PUZ132+1.p',unknown),
    [] ).

cnf(5,axiom,
    ( ~ beautiful(washington)
    | ~ has_crime(washington) ),
    file('PUZ132+1.p',unknown),
    [] ).

cnf(10,axiom,
    capital(washington),
    file('PUZ132+1.p',unknown),
    [] ).

cnf(11,axiom,
    country(usa),
    file('PUZ132+1.p',unknown),
    [] ).

cnf(13,axiom,
    capital_city(usa) = washington,
    file('PUZ132+1.p',unknown),
    [] ).

cnf(18,plain,
    city(washington),
    inference(hyper,[status(thm)],[10,1]),
    [iquote('hyper,10,1')] ).

cnf(19,plain,
    beautiful(washington),
    inference(demod,[status(thm),theory(equality)],[inference(hyper,[status(thm)],[11,4]),13]),
    [iquote('hyper,11,4,demod,13')] ).

cnf(21,plain,
    has_crime(washington),
    inference(hyper,[status(thm)],[18,3]),
    [iquote('hyper,18,3')] ).

cnf(22,plain,
    $false,
    inference(hyper,[status(thm)],[21,5,19]),
    [iquote('hyper,21,5,19')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.04/0.12  % Problem  : PUZ132+1 : TPTP v8.1.0. Released v4.1.0.
% 0.04/0.13  % Command  : otter-tptp-script %s
% 0.13/0.34  % Computer : n007.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit : 300
% 0.13/0.34  % WCLimit  : 300
% 0.13/0.34  % DateTime : Wed Jul 27 01:32:01 EDT 2022
% 0.13/0.34  % CPUTime  : 
% 1.72/1.90  ----- Otter 3.3f, August 2004 -----
% 1.72/1.90  The process was started by sandbox2 on n007.cluster.edu,
% 1.72/1.90  Wed Jul 27 01:32:01 2022
% 1.72/1.90  The command was "./otter".  The process ID is 16604.
% 1.72/1.90  
% 1.72/1.90  set(prolog_style_variables).
% 1.72/1.90  set(auto).
% 1.72/1.90     dependent: set(auto1).
% 1.72/1.90     dependent: set(process_input).
% 1.72/1.90     dependent: clear(print_kept).
% 1.72/1.90     dependent: clear(print_new_demod).
% 1.72/1.90     dependent: clear(print_back_demod).
% 1.72/1.90     dependent: clear(print_back_sub).
% 1.72/1.90     dependent: set(control_memory).
% 1.72/1.90     dependent: assign(max_mem, 12000).
% 1.72/1.90     dependent: assign(pick_given_ratio, 4).
% 1.72/1.90     dependent: assign(stats_level, 1).
% 1.72/1.90     dependent: assign(max_seconds, 10800).
% 1.72/1.90  clear(print_given).
% 1.72/1.90  
% 1.72/1.90  formula_list(usable).
% 1.72/1.90  all A (A=A).
% 1.72/1.90  exists A capital(A).
% 1.72/1.90  exists A city(A).
% 1.72/1.90  all A (capital(A)->city(A)).
% 1.72/1.90  exists A country(A).
% 1.72/1.90  capital(washington).
% 1.72/1.90  country(usa).
% 1.72/1.90  all A (country(A)->capital(capital_city(A))).
% 1.72/1.90  all X (city(X)->has_crime(X)).
% 1.72/1.90  capital_city(usa)=washington.
% 1.72/1.90  all X (country(X)->beautiful(capital_city(X))).
% 1.72/1.90  -(beautiful(washington)&has_crime(washington)).
% 1.72/1.90  end_of_list.
% 1.72/1.90  
% 1.72/1.90  -------> usable clausifies to:
% 1.72/1.90  
% 1.72/1.90  list(usable).
% 1.72/1.90  0 [] A=A.
% 1.72/1.90  0 [] capital($c1).
% 1.72/1.90  0 [] city($c2).
% 1.72/1.90  0 [] -capital(A)|city(A).
% 1.72/1.90  0 [] country($c3).
% 1.72/1.90  0 [] capital(washington).
% 1.72/1.90  0 [] country(usa).
% 1.72/1.90  0 [] -country(A)|capital(capital_city(A)).
% 1.72/1.90  0 [] -city(X)|has_crime(X).
% 1.72/1.90  0 [] capital_city(usa)=washington.
% 1.72/1.90  0 [] -country(X)|beautiful(capital_city(X)).
% 1.72/1.90  0 [] -beautiful(washington)| -has_crime(washington).
% 1.72/1.90  end_of_list.
% 1.72/1.90  
% 1.72/1.90  SCAN INPUT: prop=0, horn=1, equality=1, symmetry=0, max_lits=2.
% 1.72/1.90  
% 1.72/1.90  This is a Horn set with equality.  The strategy will be
% 1.72/1.90  Knuth-Bendix and hyper_res, with positive clauses in
% 1.72/1.90  sos and nonpositive clauses in usable.
% 1.72/1.90  
% 1.72/1.90     dependent: set(knuth_bendix).
% 1.72/1.90     dependent: set(anl_eq).
% 1.72/1.90     dependent: set(para_from).
% 1.72/1.90     dependent: set(para_into).
% 1.72/1.90     dependent: clear(para_from_right).
% 1.72/1.90     dependent: clear(para_into_right).
% 1.72/1.90     dependent: set(para_from_vars).
% 1.72/1.90     dependent: set(eq_units_both_ways).
% 1.72/1.90     dependent: set(dynamic_demod_all).
% 1.72/1.90     dependent: set(dynamic_demod).
% 1.72/1.90     dependent: set(order_eq).
% 1.72/1.90     dependent: set(back_demod).
% 1.72/1.90     dependent: set(lrpo).
% 1.72/1.90     dependent: set(hyper_res).
% 1.72/1.90     dependent: clear(order_hyper).
% 1.72/1.90  
% 1.72/1.90  ------------> process usable:
% 1.72/1.90  ** KEPT (pick-wt=4): 1 [] -capital(A)|city(A).
% 1.72/1.90  ** KEPT (pick-wt=5): 2 [] -country(A)|capital(capital_city(A)).
% 1.72/1.90  ** KEPT (pick-wt=4): 3 [] -city(A)|has_crime(A).
% 1.72/1.90  ** KEPT (pick-wt=5): 4 [] -country(A)|beautiful(capital_city(A)).
% 1.72/1.90  ** KEPT (pick-wt=4): 5 [] -beautiful(washington)| -has_crime(washington).
% 1.72/1.90  
% 1.72/1.90  ------------> process sos:
% 1.72/1.90  ** KEPT (pick-wt=3): 6 [] A=A.
% 1.72/1.90  ** KEPT (pick-wt=2): 7 [] capital($c1).
% 1.72/1.90  ** KEPT (pick-wt=2): 8 [] city($c2).
% 1.72/1.90  ** KEPT (pick-wt=2): 9 [] country($c3).
% 1.72/1.90  ** KEPT (pick-wt=2): 10 [] capital(washington).
% 1.72/1.90  ** KEPT (pick-wt=2): 11 [] country(usa).
% 1.72/1.90  ** KEPT (pick-wt=4): 12 [] capital_city(usa)=washington.
% 1.72/1.90  ---> New Demodulator: 13 [new_demod,12] capital_city(usa)=washington.
% 1.72/1.90    Following clause subsumed by 6 during input processing: 0 [copy,6,flip.1] A=A.
% 1.72/1.90  >>>> Starting back demodulation with 13.
% 1.72/1.90  
% 1.72/1.90  ======= end of input processing =======
% 1.72/1.90  
% 1.72/1.90  =========== start of search ===========
% 1.72/1.90  
% 1.72/1.90  -------- PROOF -------- 
% 1.72/1.90  
% 1.72/1.90  -----> EMPTY CLAUSE at   0.00 sec ----> 22 [hyper,21,5,19] $F.
% 1.72/1.90  
% 1.72/1.90  Length of proof is 3.  Level of proof is 2.
% 1.72/1.90  
% 1.72/1.90  ---------------- PROOF ----------------
% 1.72/1.90  % SZS status Theorem
% 1.72/1.90  % SZS output start Refutation
% See solution above
% 1.72/1.90  ------------ end of proof -------------
% 1.72/1.90  
% 1.72/1.90  
% 1.72/1.90  Search stopped by max_proofs option.
% 1.72/1.90  
% 1.72/1.90  
% 1.72/1.90  Search stopped by max_proofs option.
% 1.72/1.90  
% 1.72/1.90  ============ end of search ============
% 1.72/1.90  
% 1.72/1.90  -------------- statistics -------------
% 1.72/1.90  clauses given                 13
% 1.72/1.90  clauses generated             14
% 1.72/1.90  clauses kept                  20
% 1.72/1.90  clauses forward subsumed       6
% 1.72/1.90  clauses back subsumed          0
% 1.72/1.90  Kbytes malloced              976
% 1.72/1.90  
% 1.72/1.90  ----------- times (seconds) -----------
% 1.72/1.90  user CPU time          0.00          (0 hr, 0 min, 0 sec)
% 1.72/1.90  system CPU time        0.00          (0 hr, 0 min, 0 sec)
% 1.72/1.90  wall-clock time        1             (0 hr, 0 min, 1 sec)
% 1.72/1.90  
% 1.72/1.90  That finishes the proof of the theorem.
% 1.72/1.90  
% 1.72/1.90  Process 16604 finished Wed Jul 27 01:32:02 2022
% 1.72/1.90  Otter interrupted
% 1.72/1.90  PROOF FOUND
%------------------------------------------------------------------------------